Problem 35
Question
Solve each compound inequality. Graph the solution set, and write it using interval notation. $$ x \leq 1 \quad \text { or } \quad x \leq 8 $$
Step-by-Step Solution
Verified Answer
The solution set is \( (-\infty, 8] \).
1Step 1: Understand the given inequalities
The problem gives two inequalities: \( x \leq 1 \) and \( x \leq 8 \). The solution involves solving each inequality separately and then combining the results.
2Step 2: Solve the first inequality
The first inequality is \( x \leq 1 \). This means that \( x \) can be any value that is less than or equal to 1.
3Step 3: Solve the second inequality
The second inequality is \( x \leq 8 \). This means that \( x \) can be any value that is less than or equal to 8.
4Step 4: Combine the solutions of both inequalities
Since the inequalities are combined with 'or', we need values that satisfy either or both conditions. This means the solution set includes all values \( x \leq 8 \) since any value that is less than or equal to 8 also includes all values less than or equal to 1.
5Step 5: Write the solution in interval notation
In interval notation, the solution set is \( (-\infty, 8] \). This represents all values from negative infinity up to and including 8.
6Step 6: Graph the solution set
On a number line, draw a solid circle at 8 and shade the line to the left extending to negative infinity. This represents all values less than or equal to 8.
Key Concepts
Solving InequalitiesInterval NotationGraphing Solutions
Solving Inequalities
To solve inequalities like the example given, you need to handle each part of the compound inequality separately. In our example, we have:
\( x \leq 1 \) and \( x \leq 8 \).
The goal is to identify all values of x that satisfy each inequality. For the first inequality, \( x \leq 1 \), this means x can be any value from negative infinity up to and including 1.
For the second inequality, \( x \leq 8 \), this means x can be any value from negative infinity up to and including 8.
Since these inequalities are combined with 'or', our final solution will be the union of the two individual solutions.
This essentially means that any value meeting either criterion will be included in our final solution.
\( x \leq 1 \) and \( x \leq 8 \).
The goal is to identify all values of x that satisfy each inequality. For the first inequality, \( x \leq 1 \), this means x can be any value from negative infinity up to and including 1.
For the second inequality, \( x \leq 8 \), this means x can be any value from negative infinity up to and including 8.
Since these inequalities are combined with 'or', our final solution will be the union of the two individual solutions.
This essentially means that any value meeting either criterion will be included in our final solution.
Interval Notation
Interval notation is a way to represent the set of solutions to an inequality. In our problem, we are combining the solutions \( x \leq 1 \) and \( x \leq 8 \) using 'or'.
Since the solution for \( x \leq 8 \) naturally includes the solution for \( x \leq 1 \), the overall solution is:
This concise way of writing the solution helps to clearly communicate the entire range of possible values satisfying the compound inequality.
Since the solution for \( x \leq 8 \) naturally includes the solution for \( x \leq 1 \), the overall solution is:
- x is in the interval \(( - \infty, 8 ] \)
This concise way of writing the solution helps to clearly communicate the entire range of possible values satisfying the compound inequality.
Graphing Solutions
Graphing the solution to an inequality on a number line provides a visual representation of all the values x can take. For the inequality \( x \leq 8 \), here's how to graph it:
This graphical method complements interval notation and provides another way to understand the solution range.
- Draw a number line.
- Find and mark the number 8 on the line with a solid circle. A solid circle indicates that this number is included in the solution.
- Shade the line to the left of 8, extending towards negative infinity. This shading represents all numbers less than or equal to 8.
This graphical method complements interval notation and provides another way to understand the solution range.
Other exercises in this chapter
Problem 35
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