Problem 35
Question
Simplify each expression. $$ (x-7)(x+9) $$
Step-by-Step Solution
Verified Answer
The simplified expression is \(x^2 + 2x - 63\).
1Step 1: Apply the Distributive Property
We start by using the distributive property, which says that \((a + b)(c + d) = ac + ad + bc + bd\).For the expression \((x - 7)(x + 9)\), distribute each term in the first parenthesis across each term in the second parenthesis:1. Multiply the first terms: \(x \cdot x = x^2\).2. Multiply the outer terms: \(x \cdot 9 = 9x\).3. Multiply the inner terms: \(-7 \cdot x = -7x\).4. Multiply the last terms: \(-7 \cdot 9 = -63\). Doing this gives us: \(x^2 + 9x - 7x - 63\).
2Step 2: Combine Like Terms
Now, look at the expression obtained after distribution: \(x^2 + 9x - 7x - 63\).You can combine the like terms, which are the terms with the variable \(x\).Combine \(9x - 7x\) which simplifies to \(2x\).Thus, the expression simplifies to \(x^2 + 2x - 63\).
Key Concepts
Distributive PropertyLike TermsFactoring
Distributive Property
The Distributive Property is a fundamental concept in algebra that allows us to simplify expressions with ease. Imagine it as breaking down a complex multiplication problem into smaller, more manageable parts. The property states that for any numbers or variables, the expression \(a(b + c)\) is equivalent to \(ab + ac\).
This property is extremely useful when dealing with polynomials, which are algebraic expressions made up of terms. In our case, when simplifying \((x - 7)(x + 9)\), the distributive property helps to expand this expression into individual terms: \(x \cdot x\), \(x \cdot 9\), \(-7 \cdot x\), and \(-7 \cdot 9\).
Think of each term as a piece of a puzzle. By multiplying each component and adding them together, we can fully express the original polynomial in its expanded form.
This property is extremely useful when dealing with polynomials, which are algebraic expressions made up of terms. In our case, when simplifying \((x - 7)(x + 9)\), the distributive property helps to expand this expression into individual terms: \(x \cdot x\), \(x \cdot 9\), \(-7 \cdot x\), and \(-7 \cdot 9\).
Think of each term as a piece of a puzzle. By multiplying each component and adding them together, we can fully express the original polynomial in its expanded form.
Like Terms
Combining like terms is a crucial step in simplifying algebraic expressions. Like terms are terms that have the same variables raised to the same power. In the expression \(x^2 + 9x - 7x - 63\), we look for terms with the same variable component.
Here, \(+9x\) and \(-7x\) are like terms because they both contain the same variable \(x\) raised to the first power. To combine them, it's like adding and subtracting normal numbers:
Here, \(+9x\) and \(-7x\) are like terms because they both contain the same variable \(x\) raised to the first power. To combine them, it's like adding and subtracting normal numbers:
- Add the coefficients of identical variable terms together. \(9x - 7x\) simplifies to \(2x\).
Factoring
Factoring is the process of breaking down a polynomial into simpler terms, often called factors, that when multiplied together, produce the original polynomial. It can be thought of as the reverse process of distributing. In our case, while the problem requires expanding the expression \((x - 7)(x + 9)\), understanding factoring can help contextualize the simplified form we arrived at.
Once the expression is simplified to \(x^2 + 2x - 63\), factoring can actually help in breaking it back down into binomials if needed, or used for solving equations. A factored expression is easier to solve, especially when set equal to zero. This is because each factor represents a potential solution.
Though our exercise didn't require factoring back the expression, recognizing the layout of a factored expression, like our starting point \((x-7)(x+9)\), gives a full circle understanding of polynomial expressions in algebra.
Once the expression is simplified to \(x^2 + 2x - 63\), factoring can actually help in breaking it back down into binomials if needed, or used for solving equations. A factored expression is easier to solve, especially when set equal to zero. This is because each factor represents a potential solution.
Though our exercise didn't require factoring back the expression, recognizing the layout of a factored expression, like our starting point \((x-7)(x+9)\), gives a full circle understanding of polynomial expressions in algebra.
Other exercises in this chapter
Problem 34
Find the indicated term of each expansion. third term of \((x+y)^{8}\)
View solution Problem 35
A set of 250 data values is normally distributed with a mean of 50 and a standard deviation of 5.5 What is the probability that a data value selected at random
View solution Problem 35
Find a counterexample for the following statement. The standard deviation of a set of data is always less than the variance.
View solution Problem 35
BINOMIAL DISTRIBUTION For Exercises 34 and \(35,\) use the following information. You can use a TI-83 \(/ 84\) Plus graphing calculator to investigate the graph
View solution