Problem 35
Question
Prove or disprove the identity. $$\csc ^{2} x\left(1+\sin ^{2} x\right)=\cot ^{2} x$$
Step-by-Step Solution
Verified Answer
The identity is disproven.
1Step 1: Express Identity in Terms of Basic Functions
The original identity is given as \( \csc^2 x (1 + \sin^2 x) = \cot^2 x \). To begin, express \( \csc^2 x \) and \( \cot^2 x \) in terms of \( \sin x \) and \( \cos x \). Recall that \( \csc x = \frac{1}{\sin x} \) and \( \cot x = \frac{\cos x}{\sin x} \). Thus, \( \csc^2 x = \frac{1}{\sin^2 x} \) and \( \cot^2 x = \frac{\cos^2 x}{\sin^2 x} \).
2Step 2: Substitute and Simplify Left Side
Substituting these into the left side of the identity, we have \( \csc^2 x (1 + \sin^2 x) = \frac{1}{\sin^2 x} (1 + \sin^2 x) \). This simplifies to \( \frac{1 + \sin^2 x}{\sin^2 x} \) or \( \frac{1}{\sin^2 x} + 1 \).
3Step 3: Further Simplify Left Side
The expression \( \frac{1}{\sin^2 x} + 1 \) can be expanded to \( \frac{1 + \sin^2 x}{\sin^2 x} = \frac{1}{\sin^2 x} + \frac{\sin^2 x}{\sin^2 x} = \frac{1}{\sin^2 x} + 1 \). This simplifies directly to \( \csc^2 x \) because \( \frac{1}{\sin^2 x} = \csc^2 x \), so this part simplifies to \( \csc^2 x \) itself.
4Step 4: Assess the Right Side
Now, evaluate the right side, \( \cot^2 x = \frac{\cos^2 x}{\sin^2 x} \).
5Step 5: Compare Both Sides of the Identity
The left side simplifies to \( \frac{1}{\sin^2 x} + 1 \), while the right side is \( \frac{\cos^2 x}{\sin^2 x} \). Recognizing the Pythagorean identity \( \sin^2 x + \cos^2 x = 1 \), rewrite \( \frac{1}{\sin^2 x} + 1 \) by expressing 1 as \( \frac{\sin^2 x + \cos^2 x}{\sin^2 x} \). This makes the left side \( \frac{1 + \cos^2 x}{\sin^2 x} \), which does not simplify to \( \frac{\cos^2 x}{\sin^2 x} \). Therefore, the original identity, \( \csc^2 x (1 + \sin^2 x) = \cot^2 x \), does not hold true.
Key Concepts
Cosecant FunctionCotangent FunctionPythagorean Identity
Cosecant Function
The cosecant function, often denoted as \( \csc x \), is one of the basic trigonometric functions related to the sine function. It is defined as the reciprocal of the sine function. This means:
- \( \csc x = \frac{1}{\sin x} \)
- \( \csc^2 x = \left( \frac{1}{\sin x} \right)^2 = \frac{1}{\sin^2 x} \)
Cotangent Function
The cotangent function, represented by \( \cot x \), is another fundamental trigonometric function. It is the reciprocal of the tangent function, thus:
- \( \cot x = \frac{1}{\tan x} = \frac{\cos x}{\sin x} \)
- \( \cot^2 x = \left( \frac{\cos x}{\sin x} \right)^2 = \frac{\cos^2 x}{\sin^2 x} \)
Pythagorean Identity
The Pythagorean identity is one of the most fundamental identities in trigonometry. It is based on the Pythagorean theorem and relates the square of sine and cosine functions. The basic form is:
- \( \sin^2 x + \cos^2 x = 1 \)
- Expressing \( 1 \) as \( \sin^2 x + \cos^2 x \) allows transformations like \( 1 = \frac{\sin^2 x + \cos^2 x}{\sin^2 x} \) used in algebraic manipulations.
- Solving identities by rewriting expressions to match specific forms, as seen when comparing two sides of a trigonometric equation.
Other exercises in this chapter
Problem 33
Verify the identity. $$\cos ^{2} x-\tan ^{2} x=2-\sin ^{2} x-\sec ^{2} x$$
View solution Problem 34
Prove or disprove the identity. $$\frac{1}{1+\cos x}-\frac{1}{1-\cos (-x)}=-2 \cot x \csc x$$
View solution Problem 36
Prove or disprove the identity. $$\left(\frac{\sec ^{2}(-x)-\tan ^{2} x}{\tan x}\right)\left(\frac{2+2 \tan x}{2+2 \cot x}\right)-2 \sin ^{2} x=\cos 2 x$$
View solution Problem 37
Prove or disprove the identity. $$\frac{\tan x}{\sec x} \sin (-x)=\cos ^{2} x$$
View solution