Problem 35
Question
Physics The formula \(F=\frac{G m, m_{2}}{r^{2}}\) relates the gravitational force \(F\) between an object of mass \(m_{1}\) and an object of mass \(m_{2}\) separated by distance \(r\) . \(G\) is a constant known as the constant of gravitation. Solve the formula for \(r\) . Rationalize the denominator.
Step-by-Step Solution
Verified Answer
By rearranging the equation and rationalizing the denominator, the result of solving the equation for \(r\) is \(r=\frac{\sqrt{FGm_{1}m_{2}}}{F}\).
1Step 1: Rearrange the Formula to Solve for \(r\)
To solve for \(r\) in the equation \(F=\frac{G m_{1} m_{2}}{r^{2}}\), first, you will multiply both sides of the equation by \(r^{2}\) to isolate \(r^{2}\) on one side of the equation, resulting in \(Fr^{2}=Gm_{1}m_{2}\). Next, you will divide both sides of the equation by \(F\) to solve for \(r^{2}\) which will produce \(r^{2}=\frac{Gm_{1}m_{2}}{F}\).
2Step 2: Take the Square Root of Both Sides
With the formula \(r^{2}=\frac{Gm_{1}m_{2}}{F}\), the next step is to isolate \(r\) by taking the square root of both sides of the equation. This produces \(r=\sqrt{\frac{Gm_{1}m_{2}}{F}}\).
3Step 3: Rationalize the Denominator
To rationalize the denominator in the equation \(r=\sqrt{\frac{Gm_{1}m_{2}}{F}}\), you would multiply both the numerator and the denominator inside the square root by \(F\). The resulting equation would be \(r=\sqrt{\frac{FGm_{1}m_{2}}{F^{2}}}=\frac{\sqrt{FGm_{1}m_{2}}}{F}\).
Key Concepts
Solving for VariablesRationalizing DenominatorsGravitational ConstantAlgebraic Manipulation
Solving for Variables
In physics, solving for variables is a common task that allows us to find the unknown values in equations. In the gravitational force equation, we start with the equation \( F = \frac{G m_1 m_2}{r^2} \). Our goal is to find \( r \), the distance between two masses. To do this, we need to isolate \( r \) on one side of the equation. We begin by multiplying both sides of the equation by \( r^2 \) to move \( r^2 \) to the side where \( F \) is:
- Step 1: Multiply both sides by \( r^2 \)
- Step 2: Rearrange to get \( Fr^2 = G m_1 m_2 \)
- Step 3: Divide both sides by \( F \)
- This results in: \( r^2 = \frac{G m_1 m_2}{F} \)
Rationalizing Denominators
Rationalizing denominators is a mathematical process used to eliminate radicals from the denominator of a fraction. In the expression \( r = \sqrt{\frac{G m_1 m_2}{F}} \), we have a square root in the numerator and the denominator. Our objective is to make the denominator a rational number.To rationalize the denominator, we multiply both the numerator and the denominator by \( F \), thus eliminating the radical in the denominator. This is important because rationalizing helps simplify the expression and makes it easier to understand or compute:
- Multiply both the numerator and the denominator by \( F \)
- Transform the expression into: \( r = \frac{\sqrt{F G m_1 m_2}}{F} \)
Gravitational Constant
The gravitational constant, denoted as \( G \), is a key part of the gravitational force equation. The constant \( G \) is approximately \(6.674 \times 10^{-11} \, \text{Nm}^2\, \text{kg}^{-2}\) and defines the strength of gravity. It reflects how much two masses will attract each other in the universe due to gravity. This constant is fundamental in physics, especially in calculations involving gravitational forces:
- \( G \) is a crucial factor in the equation \( F = \frac{G m_1 m_2}{r^2} \)
- Plays a key role in determining the magnitude of the gravitational force
Algebraic Manipulation
Algebraic manipulation involves using various algebraic techniques to reorganize and solve mathematical equations. This is a critical skill in working with formulas like the gravitational force equation.When manipulating the equation \( F = \frac{G m_1 m_2}{r^2} \), we need to move terms and factors appropriately to solve for a variable. Here’s how we do it:
- Step 1: Rearrange the equation to address the desired variable (such as \( r \))
- Step 2: Simplify expressions by multiplying or dividing both sides to eliminate unwanted terms
- Step 3: Use mathematical operations, like taking square roots, to further simplify
Other exercises in this chapter
Problem 35
Let \(f(x)=x^{2}\) and \(g(x)=x-3 .\) Find each value or expression. $$ (g \circ f)(3.5) $$
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Simplify each number. $$4^{1.5}$$
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Find the two real-number solutions of each equation. $$ x^{2}=0.25 $$
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