Problem 35
Question
Let \(S\) be a lamina in the \(x y\)-plane with center of mass at the origin, and let \(L\) be the line \(a x+b y=0\), which goes through the origin. Show that the (signed) distance \(d\) of a point \((x, y)\) from \(L\) is \(d=(a x+b y) / \sqrt{a^{2}+b^{2}}\), and use this to conclude that the moment of \(S\) with respect to \(L\) is 0 . Note: This shows that a lamina will balance on any line through its center of mass.
Step-by-Step Solution
Verified Answer
The moment of the lamina with respect to any line through the origin is zero.
1Step 1: Set Up the Problem
We are given a line represented by the equation \(L: ax + by = 0\), going through the origin. A lamina \(S\) has its center of mass at the origin, \((0, 0)\). We need to find the expression for the signed distance \(d\) from a point \((x, y)\) to this line \(L\).
2Step 2: Derive the Expression for Distance
The general formula for the signed distance from a point \((x_0, y_0)\) to a line \(ax + by + c = 0\) is \(d = \frac{ax_0 + by_0 + c}{\sqrt{a^2 + b^2}}\). In our case, \(c = 0\), so the expression becomes \(d = \frac{ax + by}{\sqrt{a^2 + b^2}}\). This is the signed distance of the point \((x, y)\) from the line \(L\).
3Step 3: Define the Moment of the Lamina with respect to the Line
The moment \(M\) of the lamina \(S\) with respect to line \(L\) is defined as the integral of the signed distance over the lamina: \(M = \int_S d \, dm\), where \(dm\) represents an infinitesimal mass element of the lamina.
4Step 4: Apply the Condition of the Center of Mass
Since the center of mass of the lamina is at the origin \((0, 0)\), we know by symmetry that all contributions of the form \(ax_i + by_i\) over the entire lamina will sum to zero. Therefore, the moment \(M\) becomes zero because all signed distances, when integrated over the lamina, cancel each other out.
5Step 5: Conclude the Moment Expression
The integral expression for the moment becomes zero due to symmetry around the origin. Therefore, the moment \(M = \int_S d \, dm = 0\), indicating that the lamina will balance on any line through its center of mass.
Key Concepts
LaminaMoment of a SystemSigned DistanceSymmetry in Physics
Lamina
A lamina is a two-dimensional, flat object with negligible thickness. It can be thought of as a thin sheet or plate. In physics, we often study laminae to understand how mass is distributed across a plane. When considering the center of mass, this concept helps to determine balance and stability. For any lamina, the center of mass, if symmetrically distributed, gives insight into
- where the mass effectively acts
- how the object behaves under external forces
- its tendency to maintain orientation
Moment of a System
The moment of a system measures how much rotational force is present. In the case of a lamina, the moment with respect to a line is a way to evaluate how far the mass of the lamina shifts from this line. For a system, the moment would be calculated as:
- Moment = \ \( M = \int_S d \, dm \ \)
- where \ \( d \ \) is the signed distance from each infinitesimal mass element \ \( dm \ \) to the line
Signed Distance
The signed distance from a point to a line helps us understand not just how far a point is from a line, but also on which side of the line the point lies. The formula for the signed distance is: \ \( d = \frac{ax + by}{\sqrt{a^2 + b^2}} \ \).This formula takes:
- coordinates \ \((x, y)\ \)
- coefficients \ \((a, b)\ \)
Symmetry in Physics
Symmetry is a powerful concept used to simplify problems. In physics, symmetry often suggests some form of invariance or consistency when an object is subject to certain operations, like rotations or reflections. When applied to the lamina:
- the symmetry about the center of mass indicates an equal distribution of mass on all sides of a point
- this implies that even if forces or moments are applied, they'll cancel out
Other exercises in this chapter
Problem 35
Consider the ring \(A\) of height \(2 b\) obtained from a sphere of radius \(a\) when a hole of radius \(c(c
View solution Problem 35
Evaluate $$ \int_{0}^{1} \int_{0}^{1} x y e^{x^{2}+y^{2}} d y d x $$
View solution Problem 36
Find the volume of the solid trapped between the surface \(z=\cos x \cos y\) and the \(x y\)-plane, where \(-\pi \leq x \leq \pi\), \(-\pi \leq y \leq \pi\).
View solution Problem 37
Show that $$ \int_{0}^{\infty} \int_{0}^{\infty} \frac{1}{\left(1+x^{2}+y^{2}\right)^{2}} d y d x=\frac{\pi}{4} $$
View solution