Problem 35
Question
In Problems 35 and 36, express the given complex number first in polar form and then in the form \(a+i b\). $$ \left(\cos \frac{\pi}{9}+i \sin \frac{\pi}{9}\right)^{12}\left[2\left(\cos \frac{\pi}{6}+i \sin \frac{\pi}{6}\right)\right]^{5} $$
Step-by-Step Solution
Verified Answer
The polar form is \(32\left(\cos \frac{\pi}{6} + i \sin \frac{\pi}{6}\right)\) and the rectangular form is \(16\sqrt{3} + 16i\).
1Step 1: Recognize Format of Given Complex Number
The given complex numbers are in the form \(\cos\theta + i\sin\theta\), which are written as **Euler's formula**: \(e^{i\theta}\). So we transform them into exponential form first.
2Step 2: Convert to Exponential Form
Convert each term in the product to exponential form using Euler's formula.\[(\cos \frac{\pi}{9} + i \sin \frac{\pi}{9})^{12} = \left(e^{i \frac{\pi}{9}}\right)^{12} = e^{i \frac{12\pi}{9}} = e^{i \frac{4\pi}{3}},\] for the first term. \[ \left[2 \left(\cos \frac{\pi}{6} + i \sin \frac{\pi}{6}\right)\right]^{5} = 2^5 \left(e^{i \frac{\pi}{6}}\right)^{5} = 32 e^{i \frac{5\pi}{6}}.\] for the second term.
3Step 3: Multiply in Exponential Form
Multiply the two complex numbers in exponential form:\[ e^{i \frac{4\pi}{3}} \times 32 e^{i \frac{5\pi}{6}} = 32 e^{i (\frac{4\pi}{3} + \frac{5\pi}{6})} = 32 e^{i \frac{13\pi}{6}}\] Simplify the angle: \[ \frac{13\pi}{6} = \frac{13\pi}{6} - 2\pi = \frac{\pi}{6} \] So, the expression becomes \[ 32 e^{i \frac{\pi}{6}} \]
4Step 4: Convert Back to Complex Rectangular Form
Use Euler’s formula to convert back to rectangular form:\[ e^{i \frac{\pi}{6}} = \cos \frac{\pi}{6} + i \sin \frac{\pi}{6}, \] which is \[ \frac{\sqrt{3}}{2} + i \frac{1}{2}. \] Multiply by 32: \[32 \left( \frac{\sqrt{3}}{2} + i \frac{1}{2} \right) = 16\sqrt{3} + 16i.\]
5Step 5: Final Answer
The complex number in polar form is \(32\left(\cos \frac{\pi}{6} + i \sin \frac{\pi}{6}\right)\) and in rectangular form is \(16\sqrt{3} + 16i\).
Key Concepts
Euler's FormulaPolar FormRectangular Form
Euler's Formula
Euler’s Formula is a powerful tool for working with complex numbers, especially when they are expressed in trigonometric form. It states that for any real number \(\theta\), the expression \(e^{i\theta} = \cos\theta + i\sin\theta\). This elegant formula links complex exponentials to trigonometric functions, and it can be used to simplify complex calculations.
For the given exercise, we recognized expressions like \(\cos\frac{\pi}{9} + i \sin\frac{\pi}{9}\) as being in the trigonometric form and then used Euler's formula to convert them to the exponential form. For example:
For the given exercise, we recognized expressions like \(\cos\frac{\pi}{9} + i \sin\frac{\pi}{9}\) as being in the trigonometric form and then used Euler's formula to convert them to the exponential form. For example:
- \((\cos \frac{\pi}{9} + i \sin \frac{\pi}{9})^{12}\) becomes \(\left(e^{i \frac{\pi}{9}}\right)^{12} = e^{i \frac{12\pi}{9}} = e^{i \frac{4\pi}{3}}\).
- Using Euler’s formula simplifies multiplication and division of complex numbers, as it allows us to handle their phase or angle component and magnitude more easily.
Polar Form
Polar form is an alternative way to represent complex numbers. Instead of using the rectangular form \(a + ib\), complex numbers can be written in the form \(r(\cos\theta + i\sin\theta)\), where:
For the given term \(\left[2(\cos \frac{\pi}{6} + i \sin \frac{\pi}{6})\right]^{5}\), this can be thought of as a complex number with magnitude \(2\) and angle \(\frac{\pi}{6}\). Raising to the power of 5, simply:
- \(r\) is the magnitude (or modulus) of the complex number.
- \(\theta\) is the angle (or argument) made with the positive x-axis.
For the given term \(\left[2(\cos \frac{\pi}{6} + i \sin \frac{\pi}{6})\right]^{5}\), this can be thought of as a complex number with magnitude \(2\) and angle \(\frac{\pi}{6}\). Raising to the power of 5, simply:
- The magnitude is raised to the fifth power: \(2^5 = 32\).
- The angle is multiplied by 5: \(\frac{\pi}{6} \times 5 = \frac{5\pi}{6}\).
Rectangular Form
Rectangular form represents complex numbers in the form \(a + ib\), where \(a\) is the real part and \(ib\) is the imaginary part. After calculations in polar or exponential form, it's often useful to convert the result back to rectangular form to better interpret and visualize it.
Using the final expression from our exercise, \(32 e^{i \frac{\pi}{6}}\), we applied Euler’s formula to revert it to rectangular coordinates. Thus:
Using the final expression from our exercise, \(32 e^{i \frac{\pi}{6}}\), we applied Euler’s formula to revert it to rectangular coordinates. Thus:
- \(\cos \frac{\pi}{6}= \frac{\sqrt{3}}{2}\), and \(\sin \frac{\pi}{6} = \frac{1}{2}\).
- Inserting into the formula gives \(e^{i \frac{\pi}{6}} = \frac{\sqrt{3}}{2} + i \frac{1}{2}\).
- Multiplying by 32 gives \(32\left( \frac{\sqrt{3}}{2} + i \frac{1}{2} \right) = 16\sqrt{3} + 16i\).
Other exercises in this chapter
Problem 35
In Problems 35-38, give the points at which the given function will not be analytic. $$ f(z)=\frac{z}{z-3 i} $$
View solution Problem 35
In Problems 33-36, find all complex numbers for which the given statement is true. $$ \bar{z}=-z $$
View solution Problem 36
Express the given complex number first in polar form and then in the form \(a+i b\). $$ \frac{\left[8\left(\cos \frac{3 \pi}{8}+i \sin \frac{3 \pi}{8}\right)\ri
View solution Problem 36
Give the points at which the given function will not be analytic. $$ f(z)=\frac{2 i}{z^{2}-2 z+5 i z} $$
View solution