Problem 35
Question
In Exercises 33-36, find the indicated term of the sequence. \( a_n = \dfrac{4n}{2n^2 - 3} \) \( a_{11} = \Box \)
Step-by-Step Solution
Verified Answer
The 11th term of the sequence \( a_{11} \) is \( \dfrac{44}{239} \).
1Step 1: Substitute the given value
We will start by substituting the n in the given rule with 11, which is the indicated term's position: \( a_{11} = \dfrac{4*11}{2*11^2 - 3} \).
2Step 2: Simplify the expression
Next, we would calculate the expressions at the numerator and the denominator of the fraction separately, then divide them. This simplifies to \( a_{11} = \dfrac{44}{2*121 - 3} = \dfrac{44}{242-3} = \dfrac{44}{239} \).
3Step 3: Final Evaluation
Lastly, we would carry out the division of the two numbers in the fraction to get the value of \( a_{11} \). Or, if the division can't be performed exactly, the fraction is kept as it is.
Key Concepts
Term of a SequenceSubstitution MethodNumerator and Denominator SimplificationFraction Division
Term of a Sequence
In mathematics, a sequence is a list of numbers arranged in a specific order. Each number in this list is called a 'term.' The position of a term in a sequence is denoted by a subscript "n."
For example, the term at position 11 in a sequence is denoted as \( a_{11} \). The sequence's rule, or formula, allows you to calculate any term as long as you know its position. This is very important because once you know the formula, you can find any term's value without having to list all previous terms.
In this exercise, the rule for the sequence is given by the formula \( a_n = \dfrac{4n}{2n^2 - 3} \). We use this to find the value of the 11th term \( a_{11} \) by plugging 11 into the formula.
For example, the term at position 11 in a sequence is denoted as \( a_{11} \). The sequence's rule, or formula, allows you to calculate any term as long as you know its position. This is very important because once you know the formula, you can find any term's value without having to list all previous terms.
In this exercise, the rule for the sequence is given by the formula \( a_n = \dfrac{4n}{2n^2 - 3} \). We use this to find the value of the 11th term \( a_{11} \) by plugging 11 into the formula.
Substitution Method
The substitution method is a powerful tool in algebra, especially useful in finding the value of a sequence's term. You substitute the position number into the formula given for the sequence.
In this exercise, to find \( a_{11} \), we substitute \( n = 11 \) in the formula \( a_n = \dfrac{4n}{2n^2 - 3} \).
This gives us:
In this exercise, to find \( a_{11} \), we substitute \( n = 11 \) in the formula \( a_n = \dfrac{4n}{2n^2 - 3} \).
This gives us:
- Numerator: \( 4 \times 11 = 44 \)
- Denominator: \( 2 \times 11^2 - 3 \)
Numerator and Denominator Simplification
Simplifying the numerator and the denominator is crucial when working with fractions. It reduces complexity and makes equations easier to manage.
For the given sequence, \( a_n = \dfrac{4n}{2n^2 - 3} \), we calculated:
For the given sequence, \( a_n = \dfrac{4n}{2n^2 - 3} \), we calculated:
- Numerator as \( 44 \)
- Denominator as \( 2 \times 121 - 3 = 239 \)
Fraction Division
Division in fractions means finding how many times the denominator fits into the numerator. However, sometimes the result isn't a perfect number. In such cases, it's common to leave the result as a simplified fraction.
For \( a_{11} = \dfrac{44}{239} \), it's important to check if this can further be simplified or expressed as a decimal. If exact division isn't possible or doesn't result in a simple fraction, it's perfectly acceptable to leave it in this fractional form.
This method highlights precision and the elegance of mathematics, where not every problem leads to a whole number answer, but understanding the concept remains crucial.
For \( a_{11} = \dfrac{44}{239} \), it's important to check if this can further be simplified or expressed as a decimal. If exact division isn't possible or doesn't result in a simple fraction, it's perfectly acceptable to leave it in this fractional form.
This method highlights precision and the elegance of mathematics, where not every problem leads to a whole number answer, but understanding the concept remains crucial.
Other exercises in this chapter
Problem 35
In Exercises 35 - 44, write an expression for the \( n \)th term of the geometric sequence. Then find the indicated term. \( a_1 = 4, r = \dfrac{1}{2}, n = 10 \
View solution Problem 35
In Exercises 33 - 40, write the first five terms of the arithmetic sequence. \( a_1 = -2.6, d = -0.4 \)
View solution Problem 36
In Exercises 35 - 38, you are given the probability that an event will happen. Find the probability that the event will not happen. \( P(E) = 0.36 \)
View solution Problem 36
In Exercises 35 - 38, evaluate \( _nP_r \) using a graphing utility \( _{100}P_5 \)
View solution