Problem 35
Question
In a series RCL circuit the dissipated power drops by a factor of two when the frequency of the generator is changed from the resonant frequency to a nonresonant frequency. The peak voltage is held constant while this change is made. Determine the power factor of the circuit at the nonresonant frequency.
Step-by-Step Solution
Verified Answer
The power factor at the nonresonant frequency is 0.5.
1Step 1: Understand the Power Expression
The power dissipated in an RCL circuit at a nonresonant frequency can be expressed as \( P = \frac{V_m^2}{2Z} \cdot \cos \phi \), where \( V_m \) is the peak voltage, \( Z \) is the impedance, and \( \phi \) is the phase angle. At resonance, \( \cos \phi = 1 \) because the circuit is purely resistive, thus the power is \( P_0 = \frac{V_m^2}{2R} \).
2Step 2: Relate Power at Resonance and Nonresonance
Let the dissipated power at resonance be \( P_0 \) and at nonresonance be \( P_{nr} \). Given \( P_{nr} = \frac{1}{2}P_0 \), we have \( \frac{1}{2} \cdot \frac{V_m^2}{2R} = \frac{V_m^2}{2Z} \cdot \cos \phi \).
3Step 3: Solve for Power Factor
By equating the expressions for \( P_{nr} \) and substituting \( P_0 \), we get \( \frac{1}{2} = \frac{R}{Z} \cdot \cos \phi \). Since \( Z = \sqrt{R^2 + (X_L - X_C)^2} \) and \( X_L \) and \( X_C \) represent the inductive and capacitive reactances, solve \( \cos \phi = \frac{1}{2} \cdot \frac{Z}{R} \).
4Step 4: Apply Power Factor Definition
Since the power factor \( \cos \phi \) is desired, noting that \( \frac{R}{Z} = \frac{1}{2} \cdot \cos \phi \), rearrange to find \( \cos \phi = 0.5 \cdot \frac{Z}{R} = 0.5 \). Thus, \( \cos \phi = 0.5 \).
Key Concepts
Resonant Frequency in RCL CircuitsUnderstanding Power FactorExploring Dissipated Power in CircuitsImpedance and Its Role
Resonant Frequency in RCL Circuits
In an RCL circuit, resonant frequency is a key concept that affects how the circuit behaves and performs. It is the frequency at which the reactive components (inductance and capacitance) cancel each other out, meaning the impedance is at its minimum and is purely resistive. This frequency can be found using the formula:
- Resonant frequency, \( f_0 = \frac{1}{2\pi\sqrt{LC}} \), where \( L \) is inductance and \( C \) is capacitance.
Understanding Power Factor
The power factor is a crucial measure in RCL circuits when analyzing the efficiency of power usage. It is defined as the cosine of the phase angle (\( \cos \phi \)) between the voltage and current in the circuit. At resonance, the power factor is 1, meaning that voltage and current are in phase, and all the power is being effectively utilized:
- Power factor formula: \( \text{Power factor} = \cos \phi \).
Exploring Dissipated Power in Circuits
Dissipated power in an RCL circuit represents the actual power consumed by the resistive component of the circuit. This can be a critical factor, as it's the portion of the power supply that does useful work (e.g., generating heat or running a motor). The formula to calculate the dissipated power at any frequency is:
- \( P = \frac{V_m^2}{2Z} \cdot \cos \phi \).
Impedance and Its Role
Impedance is a fundamental concept in RCL circuits, which expands upon the idea of resistance by also considering capacitive and inductive reactances. It is the total opposition a circuit offers to the flow of alternating current (AC) at a given frequency. The impedance \( Z \) in a series RCL circuit is calculated as:
- \( Z = \sqrt{R^2 + (X_L - X_C)^2} \).
Other exercises in this chapter
Problem 31
The resonant frequency of an RCL circuit is \(1.3 \mathrm{kHz},\) and the value of the inductance is \(7.0 \mathrm{mH}\). What is the resonant frequency (in \(\
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Suppose you have a number of capacitors. Each is identical to the capacitor that is already in a series RCL circuit. How many of these additional capacitors mus
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When a resistor is connected across the terminals of an ac generator \((112 \mathrm{~V})\) that has a fixed frequency, there is a current of \(0.500 \mathrm{~A}
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A capacitor is attached to a 5.00 -Hz generator. The instantaneous current is observed to reach a maximum value at a certain time. What is the least amount of t
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