Problem 35
Question
In \(11-38,\) evaluate each expression in the set of real numbers. $$ -\sqrt[4]{\frac{b^{8}}{1,296}}, b \geq 0 $$
Step-by-Step Solution
Verified Answer
The expression evaluates to \(-\frac{b^{2}}{6}\).
1Step 1: Simplify the expression inside the root
The given expression is \(-\sqrt[4]{\frac{b^{8}}{1,296}}\). First, let's simplify the expression inside the fourth root: \(\frac{b^{8}}{1,296}\). Since \(b^{8} = (b^{4})^2\), this can be rewritten as \(\frac{(b^{4})^2}{1,296}\).
2Step 2: Evaluate the fourth root
Now, find the fourth root: \(\sqrt[4]{\frac{b^{8}}{1,296}} = \frac{b^{8/4}}{1,296^{1/4}} = \frac{b^{2}}{6}\). Here, we used the properties of exponents and roots: \(b^{8/4} = b^2\) and since \(1,296 = 6^4\), thus \(1,296^{1/4} = 6\).
3Step 3: Apply the negative sign to the evaluated root
Finally, apply the negative sign outside the root: \(-\sqrt[4]{\frac{b^{8}}{1,296}} = -\frac{b^{2}}{6}\). This is the simplification of the original expression.
Key Concepts
Fourth rootExponent propertiesSimplifying expressionsReal numbers
Fourth root
Finding the fourth root of a number is quite similar to the more familiar square root, but instead of seeking a number that, when squared, gives the original, we're looking for a number that, when raised to the fourth power, yields the original number. For instance, to find \( \sqrt[4]{x} \), we ask: "What number multiplied by itself four times is equal to \( x \)?".
- It's denoted as \( x^{1/4} \) or \( \sqrt[4]{x} \).
- If you have a number like \( 64 \), since \( 64 = 4^3 \), \( \sqrt[4]{64} = 4 \).
Exponent properties
Exponent properties help us manipulate and simplify expressions involving powers. These properties include how to deal with numbers that are raised to an exponent, like \( a^b \), where \( a \) is the base and \( b \) is the exponent.
- Product of Powers: \( a^m \times a^n = a^{m+n} \).
- Power of a Power: \( (a^m)^n = a^{m \cdot n} \).
- Power of a Product: \( (ab)^n = a^n \times b^n \).
- Quotient of Powers: \( \frac{a^m}{a^n} = a^{m-n} \), provided \( a eq 0 \).
Simplifying expressions
Simplifying expressions is a fundamental part of algebra. It involves rewriting expressions in their most concise form, ensuring they are easier to evaluate and interpret. We focused on simplifying the expression inside the fourth root and the result after applying the root itself.
- Break down complex expressions into simpler components using properties of exponents and roots.
- Recognize perfect powers like \( 1,296 = 6^4 \), making it easier to simplify \( \sqrt[4]{1,296} = 6 \).
- Apply operations, such as factoring, to simplify the expression as much as possible.
Real numbers
Real numbers include all the numbers you use in everyday life, encompassing whole numbers, integers, fractions, and decimals. They can be further divided into rational and irrational numbers. In this exercise, we worked within the set of real numbers.
- Rational Numbers: Can be expressed as fractions or ratios of integers, e.g., \( \frac{7}{2}, \frac{b^2}{6} \).
- Irrational Numbers: Cannot be neatly expressed as simple fractions, e.g., \( \pi, \sqrt{2} \).
- Every real number can be placed on an infinite number line. From left to right, numbers increase in value.
Other exercises in this chapter
Problem 35
In \(3-41\) , express each product in simplest form. Variables in the radicand with an even index are non-negative. $$ (\sqrt{6}+6)(\sqrt{6}-7) $$
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In \(3-38,\) solve each equation for the variable, check, and write the solution set. $$ \sqrt{x+5}=1+\sqrt{x} $$
View solution Problem 35
In \(3-38\) write each expression in simplest form. Variables in the radicand with an even index are non-negative. Variables occurring in the denominator of a f
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Rationalize the denominator and write each fraction in simplest form. All variables represent positive numbers. \(\frac{2}{\sqrt{x}}+\frac{2}{\sqrt{y}}\)
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