Problem 35
Question
If possible, simplify each radical expression. Assume that all variables represent positive real numbers. $$\sqrt[3]{16(-2)^{4}(2)^{8}}$$
Step-by-Step Solution
Verified Answer
The simplified expression is \(32 \sqrt[3]{2}\).
1Step 1: Simplify the expression inside the radical
Start by simplifying the expression inside the cube root: \(16(-2)^4(2)^8\). 1. Calculate \((-2)^4\): \((-2)^4 = 16\). 2. Calculate \((2)^8\): \((2)^8 = 256\). Now the expression becomes \(16 \times 16 \times 256\).
2Step 2: Simplify the product
Now multiply the simplified numbers inside the cube root:\(16 \times 16 = 256\).Next, multiply \(256 \times 256\):\(256 \times 256 = 65536\).So, the expression now is \(\sqrt[3]{65536}\).
3Step 3: Find the cube root
Now determine the cube root of 65536. Recall that:\(65536 = 2^{16}\).The cube root of \(2^{16}\) is calculated as follows:\(\sqrt[3]{2^{16}} = 2^{\frac{16}{3}} = 2^{5 + \frac{1}{3}}\).This simplifies to \(32 \times \sqrt[3]{2}\).
Key Concepts
Cube RootsExponentsProduct Property of Radicals
Cube Roots
Understanding cube roots is essential when simplifying radical expressions like the one in our example, \(\sqrt[3]{16(-2)^4(2)^8}\). A cube root is simply a number that, when multiplied by itself three times, results in the given number. To visualize:
- The cube root of 8 is 2 because \(2 \times 2 \times 2 = 8\).
- The cube root of 27 is 3 because \(3 \times 3 \times 3 = 27\).
Exponents
Exponents are the shorthand used for expressing the repeated multiplication of a number by itself. They are crucial in simplifying radical expressions. Consider the original expression \(16(-2)^4(2)^8\). Here, exponents show how many times each base is used as a factor. Let's break this down further:
- \((-2)^4 = 16\) indicates \((-2)\) is multiplied by itself 4 times.
- \((2)^8=256\) means \(2\) is used as a factor 8 times repeated.
Product Property of Radicals
The product property of radicals is a vital tool when simplifying radical expressions involving multiplication. This property states that the radical of a product is equal to the product of the radicals of each factor. In simpler terms, if you have a product under a radical, you can split it into separate radicals for each factor.For example, if you have \(\sqrt{a \times b}\), it is equivalent to \(\sqrt{a} \times \sqrt{b}\). In the case of cube roots, it looks like:\[ \sqrt[3]{a \times b} = \sqrt[3]{a} \times \sqrt[3]{b} \]Applying this in our problem, after simplifying inside the cube root, we used the property to express the square number \(65536\) as \(2^{16}\), which helps us determine the radical. Knowing this property lets you break down complex expressions into smaller, more manageable parts. It's especially handy when individual factors can be simplified or have recognizable cube roots, streamlining the calculation process.
Other exercises in this chapter
Problem 34
Find each product or quotient. $$\frac{6 n^{2}-5 n-6}{6 n^{2}+5 n-6} \cdot \frac{12 n^{2}-17 n+6}{12 n^{2}-n-6}$$
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Find each product. $$(2 z-1)\left(-z^{2}+3 z-4\right)$$
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Perform the indicated operations. Write your answers with only positive exponents. Assume that all variables represent positive real numbers. $$\left(2 y^{3 / 4
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Factor each perfect square trinomial completely. $$20 p^{2}-100 p q+125 q^{2}$$
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