Problem 35
Question
Give the domain and range of the function. $$f(x)=\sqrt{x-4}$$
Step-by-Step Solution
Verified Answer
The domain of the function \(f(x)=\sqrt{x-4}\) is \([4, +\infty)\) and the range is \([0, +\infty)\).
1Step 1: Identify the argument of the square root function
The argument of the square root function is \(x-4\). We cannot take the square root of a negative value, so \(x-4\) must be greater than or equal to 0. This gives the inequality \(x-4 \geq 0\).
2Step 2: Solve the inequality for the domain
Solving the inequality will give the domain of the function. To solve it, add 4 to both sides of the inequality \(x-4 \geq 0\), which yields \(x \geq 4\). Therefore, the domain of \(f(x)=\sqrt{x-4}\) is \([4, +\infty)\).
3Step 3: Determine the range
The square root function always outputs values from 0 upwards when the radicand is non-negative. Therefore, the range of \(f(x)=\sqrt{x-4}\) is \([0, +\infty)\).
Key Concepts
Solving InequalitiesDomain of a FunctionRange of a FunctionSquare Root Properties
Solving Inequalities
Solving inequalities is similar to solving equations, but instead of equal signs, we use inequality symbols to compare two values. These symbols include greater than (>), less than (<), greater than or equal to (≥), and less than or equal to (≤).
When solving an inequality, we perform operations on both sides, just like with an equation, but we need to be careful—multiplying or dividing by a negative number will reverse the inequality. For example, solving the inequality from the exercise step-by-step, we start with \(x - 4 \geq 0\) and isolate \(x\) by adding 4 to both sides, resulting in \(x \geq 4\). It is crucial to plot the solutions on a number line or use interval notation, like \([4, +\infty)\), to visually represent the range of values that \(x\) can take.
When solving an inequality, we perform operations on both sides, just like with an equation, but we need to be careful—multiplying or dividing by a negative number will reverse the inequality. For example, solving the inequality from the exercise step-by-step, we start with \(x - 4 \geq 0\) and isolate \(x\) by adding 4 to both sides, resulting in \(x \geq 4\). It is crucial to plot the solutions on a number line or use interval notation, like \([4, +\infty)\), to visually represent the range of values that \(x\) can take.
Domain of a Function
The domain of a function includes all the possible inputs, or \(x\)-values, that the function can accept without violation of mathematical rules. For functions involving square roots, like \(f(x) = \sqrt{x - 4}\), the domain is constrained to prevent taking the square root of a negative number—since that's not defined within the set of real numbers.
In our exercise, the argument of the square root, \(x - 4\), must be non-negative. So we set up an inequality \(x - 4 \geq 0\) and solve for \(x\) to find the domain. After solving, we find that the domain of \(f(x)\) is \([4, +\infty)\), meaning \(f(x)\) can accept any real number greater than or equal to 4 according to the square root properties.
In our exercise, the argument of the square root, \(x - 4\), must be non-negative. So we set up an inequality \(x - 4 \geq 0\) and solve for \(x\) to find the domain. After solving, we find that the domain of \(f(x)\) is \([4, +\infty)\), meaning \(f(x)\) can accept any real number greater than or equal to 4 according to the square root properties.
Range of a Function
The range of a function consists of all possible outputs, or \(y\)-values, that the function can produce. Unlike the domain, which is determined by the inputs, the range is impacted by the function's operations on those inputs.
For the square root function \(f(x) = \sqrt{x - 4}\) from our exercise, we start by inspecting the lowest value of the square root expression—since square roots produce non-negative outputs, the smallest value for \(f(x)\) is 0, when \(x - 4\) is 0 (or when \(x\) is 4). As \(x\) increases, \(f(x)\) also increases without bound. Thus, the range is \([0, +\infty)\). This tells us that the square root function's range starts from 0 and stretches indefinitely upwards.
For the square root function \(f(x) = \sqrt{x - 4}\) from our exercise, we start by inspecting the lowest value of the square root expression—since square roots produce non-negative outputs, the smallest value for \(f(x)\) is 0, when \(x - 4\) is 0 (or when \(x\) is 4). As \(x\) increases, \(f(x)\) also increases without bound. Thus, the range is \([0, +\infty)\). This tells us that the square root function's range starts from 0 and stretches indefinitely upwards.
Square Root Properties
Square root properties are essential for understanding functions that include square root operations, such as \(f(x) = \sqrt{x - 4}\). The square root function, denoted as \(\sqrt{\cdot}\), only accepts non-negative radicands—the numbers under the root symbol—since the square of any real number is non-negative. This leads to two key properties:
- The result of a square root is always non-negative, which defines the range of square root functions.
- The domain is limited to non-negative radicands to avoid undefined or complex results within the real number system.
Other exercises in this chapter
Problem 34
Find an equation for the line that passes through the poiot \(P(2,7)\) and is parallel to the line \(y-2 x: 5=0\)
View solution Problem 35
Find \(f\) such that \(f \circ g=F\) given that $$g(x)=\frac{1+x^{2}}{1+x^{4}}, F(x)=\frac{1+x^{4}}{1+x^{2}}$$
View solution Problem 35
Give the domain of the function and sketch the graph. $$f(x)=\frac{1}{2} x+2$$
View solution Problem 35
Find the number(s) \(x\) in the interval \([0.2 \pi]\) which satisfy the equation. $$\cos x=\sqrt{2} / 2$$.
View solution