Problem 35
Question
For the following exercises, solve for \(x\) by converting the logarithmic equation to exponential form. \(\ln (x)=2\)
Step-by-Step Solution
Verified Answer
\( x = e^2 \)
1Step 1: Identify the form of the logarithmic equation
The given equation is in the natural logarithm form: \( \ln(x) = 2 \), where \( \ln \) denotes the natural logarithm, which is the logarithm to the base \( e \).
2Step 2: Convert logarithmic equation to exponential form
To convert \( \ln(x) = 2 \) into its exponential form, we use the property that \( \ln(x) = 2 \) is equivalent to \( e^2 = x \) because the natural logarithm has a base of \( e \).
3Step 3: Solve for x
Now that we have converted the equation to its exponential form \( e^2 = x \), it implies that \( x = e^2 \). Compute this expression to find the value of \( x \).
Key Concepts
Natural LogarithmLogarithmic to Exponential ConversionSolving for VariablesBase e Logarithms
Natural Logarithm
The natural logarithm, often represented as \( \ln \), is a special type of logarithm where the base is the mathematical constant \( e \). This constant \( e \) is approximately equal to 2.71828 and is fundamental in many areas of mathematics and science. The natural logarithm helps to model continuous growth processes such as population growth or radioactive decay.
When you encounter \( \ln(x) \), it means "the power to which \( e \) must be raised to obtain \( x \)." For instance, if \( \ln(x) = 2 \), it indicates that \( e \) raised to the power of 2 gives you \( x \). Understanding this concept is essential for converting and solving equations that involve natural logarithms.
When you encounter \( \ln(x) \), it means "the power to which \( e \) must be raised to obtain \( x \)." For instance, if \( \ln(x) = 2 \), it indicates that \( e \) raised to the power of 2 gives you \( x \). Understanding this concept is essential for converting and solving equations that involve natural logarithms.
Logarithmic to Exponential Conversion
One of the key steps in solving logarithmic equations is understanding how to convert them into exponential form. This involves using the properties of logarithms and exponents. If you have an equation \( \ln(x) = n \), the conversion process entails rewriting this as \( e^n = x \).
- Identify that \( \ln(x) \) means the logarithm with a base \( e \).
- Recognize the equivalence in conversion: logarithmic form to exponential form.
Solving for Variables
Solving equations, especially those involving logarithms, often requires isolating the variable of interest. In logarithmic equations, once converted to exponential form, it becomes much simpler to solve for the variable. Let's consider the equation \( e^n = x \).
- After conversion, focus on isolating \( x \).
- Identify the numerical value or expression equivalent to the variable.
Base e Logarithms
Base \( e \) logarithms, known as natural logarithms, are integral to calculus and mathematical modeling. The base \( e \) itself arises naturally in scenarios of continuous growth, compounding interest, or decay processes. It's defined as the unique number that makes the statement \( \ln(e) = 1 \).
When working with logarithmic equations:
When working with logarithmic equations:
- Recognize that \( \ln(x) = y \) implies \( e^y = x \).
- The base \( e \) plays a critical role in converting logs to exponential form.
Other exercises in this chapter
Problem 35
For the following exercises, use the change-of-base formula to evaluate each expression as a quotient of natural logs. Use a calculator to approximate each to f
View solution Problem 35
For the following exercises, sketch the graphs of each pair of functions on the same axis. \(f(x)=\log (x)\) and \(g(x)=\log _{\frac{1}{2}}(x)\)
View solution Problem 35
For the following exercises, start with the graph of \(f(x)=4^{x}\). Then write a function that results from the given transformation. Shift \(f(x) \quad 5\) un
View solution Problem 36
For the following exercises, refer to \(\underline{\text { Table }}\). $$ \begin{array}{|c|c|c|c|c|c|c|} \hline \boldsymbol{x} & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline
View solution