Problem 35
Question
Find the sum for each series. $$\sum_{k=1}^{6}(-1)^{k} \cdot k$$
Step-by-Step Solution
Verified Answer
The sum of the series is 3.
1Step 1: Understand the Series
We are given the series \( \sum_{k=1}^{6}(-1)^{k} \cdot k \). This notation indicates we need to sum the terms generated by the expression \((-1)^{k} \cdot k\) as \(k\) varies from 1 to 6.
2Step 2: Calculate Each Term in the Series
Calculate each term of the series using the expression \((-1)^{k} \cdot k\):- For \(k = 1\): \((-1)^{1} \cdot 1 = -1\)- For \(k = 2\): \((-1)^{2} \cdot 2 = 2\)- For \(k = 3\): \((-1)^{3} \cdot 3 = -3\)- For \(k = 4\): \((-1)^{4} \cdot 4 = 4\)- For \(k = 5\): \((-1)^{5} \cdot 5 = -5\)- For \(k = 6\): \((-1)^{6} \cdot 6 = 6\)
3Step 3: Sum the Calculated Terms
Now, sum up all the terms calculated:- \(-1 + 2 - 3 + 4 - 5 + 6\).Let's group and sequentially add these:1. \(-1 + 2 = 1\)2. \(1 - 3 = -2\)3. \(-2 + 4 = 2\)4. \(2 - 5 = -3\)5. \(-3 + 6 = 3\)
4Step 4: Conclude with the Final Sum
The sum of the series \( \sum_{k=1}^{6}(-1)^{k} \cdot k \) is 3. We obtained this by sequentially summing all individual terms calculated in the previous steps.
Key Concepts
Summation NotationAlternating SeriesAlgebraic Manipulation
Summation Notation
Summation notation is a mathematical shorthand used to represent the sum of a sequence of terms. This notation makes calculations for series much more organized and easier to comprehend. The symbol for summation is the Greek capital letter sigma, denoted as \( \Sigma \). When using summation notation, you typically see it in the form of \( \sum_{k=a}^{b} f(k) \). Here:
- \( k \) is the index of summation, which runs from \( a \) to \( b \).
- \( f(k) \) is the expression that defines the terms in the series.
- \( a \) is the lower limit where the summation starts, and \( b \) is the upper limit where it ends.
Alternating Series
An alternating series is a series whose terms alternate in sign. The series often takes the form of a sequence like \( a_1 - a_2 + a_3 - a_4 + \ldots \), where each term switches from positive to negative and vice versa. This behavior is crucial for understanding and predicting the summation result.
- In our series, \((-1)^k\) is responsible for creating the alternating pattern. When \(k\) is odd, \((-1)^k\) yields \(-1\), resulting in negative terms.
- Conversely, when \(k\) is even, \((-1)^k\) results in \(1\), yielding positive terms.
Algebraic Manipulation
Algebraic manipulation involves rearranging and combining terms to simplify the calculation of a series. It's a vital skill when working with series and can especially be useful in alternating series where things seem to cancel out.For the series \( \sum_{k=1}^{6}(-1)^{k} \cdot k \), the process involved calculating and summing each term explicitly:
- The first step calculated each term: \(-1, 2, -3, 4, -5,\) and \(6\).
- Then, we grouped them to assist in effective combination: \((-1 + 2), (-3 + 4), (-5 + 6)\).
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