Problem 35
Question
Find the great-circle distance from St. Paul (longitude \(93.1^{\circ} \mathrm{W}\), latitude \(45^{\circ} \mathrm{N}\) ) to Turin, Italy (longitude \(7.4^{\circ} \mathrm{E}\), latitude \(\left.45^{\circ} \mathrm{N}\right)\).
Step-by-Step Solution
Verified Answer
The great-circle distance between St. Paul and Turin is approximately 7,089 kilometers.
1Step 1: Convert Longitudes to Radians
First, convert the longitudes of St. Paul and Turin from degrees to radians. Use the formula: \[\text{Radians} = \text{Degrees} \times \frac{\pi}{180}\]For St. Paul: \[93.1^{\circ} \times \frac{\pi}{180} = 1.624 \, \text{radians} \text{ (West is negative)} = -1.624 \, \text{radians}\]For Turin: \[7.4^{\circ} \times \frac{\pi}{180} = 0.129 \, \text{radians}\]This gives the longitudes as \(-1.624\) and \(0.129\) radians, respectively.
2Step 2: Apply the Great-Circle Distance Formula
The great-circle distance can be found using the formula:\[\Delta \sigma = \cos^{-1} \left( \sin \phi_1 \sin \phi_2 + \cos \phi_1 \cos \phi_2 \cos(\lambda_2 - \lambda_1) \right)\]where \(\phi_1 = \phi_2 = 45^{\circ} \text{ (latitude in radians,} \phi = 45^{\circ} \times \frac{\pi}{180} = 0.785 \, \text{radians)}\). Substitute the values into the formula:\[\Delta \sigma = \cos^{-1} \left( \sin(0.785) \sin(0.785) + \cos(0.785) \cos(0.785) \cos(0.129 - (-1.624)) \right)\]Simplifying inside the cosine inverse gives the distance angle \(\Delta \sigma\).
3Step 3: Calculate the Angular Separation
Calculate:\[\Delta \sigma = \cos^{-1} \left( \sin^2(0.785) + \cos^2(0.785) \cos(1.753) \right)\]First, find \(\sin(0.785) = \cos(0.785) = \frac{\sqrt{2}}{2}\), and then:\[= \cos^{-1} \left( \frac{1}{2} + \frac{1}{2} \cos(1.753) \right)\]Calculate \(\cos(1.753)\) and substitute it back in to find \(\Delta \sigma\).
4Step 4: Convert Angular Separation to Distance
Find the Earth’s radius and compute the great-circle distance using:\[D = R \Delta \sigma\]where the Earth's radius \(R\) is approximately 6,371 kilometers. After finding \(\Delta \sigma\) in radians, multiply by \(6,371\) km to convert the angular distance into linear distance.
Key Concepts
Latitude and Longitude ConversionTrigonometric FunctionsAngular Separation Calculation
Latitude and Longitude Conversion
To solve the problem of finding the great-circle distance, it's essential to understand how to convert the geographical coordinates of latitude and longitude from degrees to radians.
When working with trigonometric functions, radians are the preferred unit because they allow for direct application in these functions.
To convert degrees to radians, use the formula:
Converting this into radians involves multiplying by \( \frac{\pi}{180} \), resulting in approximately \(-1.624 \text{ radians} \).
The westward longitude is typically negative in mathematical calculations.
For Turin, Italy, the longitude is \(7.4^{\circ} \text{E}\), which converts to about \(0.129 \text{ radians} \).
Remembering these steps will ensure you accurately perform conversions needed for any problem involving great-circle distances on the Earth, enhancing not only this specific solution but also your broader understanding of geographical calculations.
When working with trigonometric functions, radians are the preferred unit because they allow for direct application in these functions.
To convert degrees to radians, use the formula:
- Radians = Degrees × \( \frac{\pi}{180} \)
Converting this into radians involves multiplying by \( \frac{\pi}{180} \), resulting in approximately \(-1.624 \text{ radians} \).
The westward longitude is typically negative in mathematical calculations.
For Turin, Italy, the longitude is \(7.4^{\circ} \text{E}\), which converts to about \(0.129 \text{ radians} \).
Remembering these steps will ensure you accurately perform conversions needed for any problem involving great-circle distances on the Earth, enhancing not only this specific solution but also your broader understanding of geographical calculations.
Trigonometric Functions
Trigonometric functions play a pivotal role in calculating great-circle distances because they relate to angles and circular measurements.
For great-circle distances, we utilize the cosine inverse function, or \(\cos^{-1}\), within the spherical distance formula.
Why are trigonometric functions necessary here? These functions help us understand the relationships between the angles formed by latitudes, longitudes, and the Earth's radius.
In the exercise, we calculate the angle \(\Delta \sigma\), which is key for identifying the arc length between St. Paul and Turin using
Knowing how to effectively employ these functions is crucial as they bridge the gap between geographic and mathematical calculations, facilitating accurate distance measurements on a spherical surface like Earth.
For great-circle distances, we utilize the cosine inverse function, or \(\cos^{-1}\), within the spherical distance formula.
Why are trigonometric functions necessary here? These functions help us understand the relationships between the angles formed by latitudes, longitudes, and the Earth's radius.
In the exercise, we calculate the angle \(\Delta \sigma\), which is key for identifying the arc length between St. Paul and Turin using
- \(\Delta \sigma = \cos^{-1} \left( \sin \phi_1 \sin \phi_2 + \cos \phi_1 \cos \phi_2 \cos(\lambda_2 - \lambda_1) \right)\)
Knowing how to effectively employ these functions is crucial as they bridge the gap between geographic and mathematical calculations, facilitating accurate distance measurements on a spherical surface like Earth.
Angular Separation Calculation
Angular separation calculation is essential when determining the shortest path between two points on a globe, known as the great-circle distance.
This process involves finding \(\Delta \sigma\) through angular relationships.
To calculate angular separation, use the formula:
Given \(\phi_1 = \phi_2\), the computation simplifies slightly but still requires understanding the precise alignment of Earth's coordinates.
Calculate \(\sin(0.785)\) and \(\cos(0.785)\) as \(\frac{\sqrt{2}}{2}\) for simplification.
This solution ultimately provides the angle in radians that, when multiplied by Earth's radius, gives the linear distance between the points.
Mastering this step offers invaluable insight into how abstract trigonometric formulas translate to tangible geographical measurements, allowing for accurate calculations of real-world distances.
This process involves finding \(\Delta \sigma\) through angular relationships.
To calculate angular separation, use the formula:
- \(\Delta \sigma = \cos^{-1} \left( \sin^2(0.785) + \cos^2(0.785) \cos(1.753) \right)\)
Given \(\phi_1 = \phi_2\), the computation simplifies slightly but still requires understanding the precise alignment of Earth's coordinates.
Calculate \(\sin(0.785)\) and \(\cos(0.785)\) as \(\frac{\sqrt{2}}{2}\) for simplification.
This solution ultimately provides the angle in radians that, when multiplied by Earth's radius, gives the linear distance between the points.
Mastering this step offers invaluable insight into how abstract trigonometric formulas translate to tangible geographical measurements, allowing for accurate calculations of real-world distances.
Other exercises in this chapter
Problem 34
In Problems 33-36, set up a definite integral for the arc length of the given curve. Use the Parabolic Rule with \(n=10\) or a CAS to approximate the integral.
View solution Problem 35
A 100 -pound chandelier is held in place by four wires attached to the ceiling at the four corners of a square. Each wire makes an angle of \(45^{\circ}\) with
View solution Problem 35
Show that the projection in the \(x z\)-plane of the curve that is the intersection of the surfaces \(y=4-x^{2}\) and \(y=x^{2}+z^{2}\) is an ellipse, and find
View solution Problem 35
In Problems 33-36, set up a definite integral for the arc length of the given curve. Use the Parabolic Rule with \(n=10\) or a CAS to approximate the integral.
View solution