Problem 35
Question
Find the first four nonzero terms in the Maclaurin series for the functions in Exercises \(31-38 .\) $$e^{\sin x}$$
Step-by-Step Solution
Verified Answer
The first four nonzero terms are: \( 1 + x + \frac{x^2}{2} - \frac{x^3}{6} \).
1Step 1: Understanding the Maclaurin Series
The Maclaurin series is a type of Taylor series expansion of a function about 0 (i.e., \( a = 0 \)). It is given by \( \sum_{n=0}^{\infty} \frac{f^{(n)}(0)}{n!}x^n \), where \( f^{(n)}(0) \) is the \( n \)-th derivative of the function evaluated at 0.
2Step 2: Find the Maclaurin Series of \( e^x \)
The Maclaurin series expansion for \( e^x \) is given by \( 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \cdots \), or more generally, \( \sum_{n=0}^{\infty} \frac{x^n}{n!} \).
3Step 3: Find the Maclaurin Series of \( \sin x \)
The Maclaurin series expansion for \( \sin x \) is \( x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \cdots \), or in general, \( \sum_{n=0}^{\infty} (-1)^n \frac{x^{2n+1}}{(2n+1)!} \).
4Step 4: Substitute \( \sin x \) Maclaurin series into \( e^{\sin x} \) series
Substitute the \( \sin x \) Maclaurin series into \( e^{\sin x} \)'s expansion:\[e^{\sin x} = e^{x - \frac{x^3}{3!} + \cdots} = 1 + (x - \frac{x^3}{6} + \cdots) + \frac{(x - \frac{x^3}{6} + \cdots)^2}{2!} + \cdots \].
5Step 5: Compute and Combine First Four Nonzero Terms
Expand the expression and collect terms up to first four nonzero terms. From the previous expansion:1. The first term is \( 1 \).2. The second term involves \( x \).3. The third term involves \( -\frac{x^3}{6} \).4. Next, we expand to bring a \( \frac{x^2}{2!} \) term from the square of \( x \ and thus include it entirely to get: \ 1 + x + \frac{x^2}{2} - \frac{x^3}{6} + \cdots \).
6Step 6: Write the First Four Nonzero Terms
Collecting the first four non-zero terms, we have \[ e^{\sin x} \approx 1 + x + \frac{x^2}{2} - \frac{x^3}{6} \].
Key Concepts
Taylor seriesexponential functionstrigonometric functions
Taylor series
The Taylor series is a powerful mathematical tool used to approximate transcendental functions. This series expands a function into an infinite sum of its derivatives at a single point.
- A Taylor series centered at a point \(a\) is expressed as \( \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!}(x-a)^n \).
- The Maclaurin series is a special case of the Taylor series where \(a = 0\).
- This means we expand the function around the origin, simplifying calculations.
exponential functions
Exponential functions are a key concept in calculus and algebra. They are defined by the function \(f(x) = a^x\), where \(a\) is a positive constant. The most common base is \(e\), where \(e\) is the natural number approximately equal to 2.71828.
- Exponential functions, such as \(e^x\), grow rapidly because their rate of growth is proportional to their value.
- The derivative of an exponential function is particularly simple: \(f'(x) = e^x\), the same as the original function.
- This property makes \(e^x\) exceptionally useful when analyzing continuous growth or decay.
trigonometric functions
Trigonometric functions like \( \sin x \), \( \cos x \), and \( \tan x \) describe relationships between angles and lengths in right-angled triangles. These functions also play a significant role in periodic phenomena, including waves and circular motion.
- The Maclaurin series for \( \sin x \) is \( x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \cdots \).
- Such series allow for the approximation of trigonometric functions near zero, turning them into manageable polynomials.
- By substituting into other functions using their series, we can analyze more complex compositions like \( e^{\sin x} \).
Other exercises in this chapter
Problem 34
Which of the sequences \(\left\\{a_{n}\right\\}\) converge, and which diverge? Find the limit of each convergent sequence. $$ a_{n}=\frac{2 n+1}{1-3 \sqrt{n}} $
View solution Problem 34
In Exercises \(1-36,\) (a) find the series' radius and interval of convergence. For what values of \(x\) does the series converge (b) absolutely (c) conditional
View solution Problem 35
Find the first three nonzero terms of the Maclaurin series for each function and the values of \(x\) for which the series converges absolutely. \(f(x)=\cos x-(2
View solution Problem 35
Use series to evaluate the limits. \begin{equation} \lim _{x \rightarrow \infty} x^{2}\left(e^{-1 / x^{2}}-1\right) \end{equation}
View solution