Problem 35
Question
Find an equation for the conic that satisfies the given conditions. Parabola, vertex \((2,3), \quad\) vertical axis, passing through \((1,5)\)
Step-by-Step Solution
Verified Answer
The equation of the parabola is \((x - 2)^2 = \frac{1}{2}(y - 3)\).
1Step 1: Identify the Parabola Equation Format
Since the parabola has a vertical axis, it follows the format \[ (x - h)^2 = 4p(y - k) \]where \((h, k)\) is the vertex. Here, \(h = 2\) and \(k = 3\). So the equation becomes \[ (x - 2)^2 = 4p(y - 3) \].
2Step 2: Use the Given Point to Find p
Substitute the point \((1, 5)\) into the equation to find the value of \(p\). We have \[ (1 - 2)^2 = 4p(5 - 3) \].Simplifying gives \[ 1 = 8p \].Solving for \(p\), we get \[ p = \frac{1}{8} \].
3Step 3: Write the Final Equation
With \(p = \frac{1}{8}\), substitute back into the parabola form to get the equation: \[ (x - 2)^2 = \left(\frac{1}{2}\right)(y - 3) \].Rewriting gives the final equation: \[ (x - 2)^2 = \frac{1}{2}(y - 3) \].
Key Concepts
Vertex Form of ParabolaVertical Axis of ParabolaSolving for Parameter p
Vertex Form of Parabola
Understanding the vertex form of a parabola is pivotal for graphing and solving problems involving parabolic equations. For a parabola with a vertical axis, the vertex form is given by:\[(x - h)^2 = 4p(y - k)\]where
- \( (h, k) \) is the vertex of the parabola.
- \( p \) is the distance from the vertex to the focus and thence to the directrix.
Vertical Axis of Parabola
When we talk about a parabola having a vertical axis, it means the parabola opens either upwards or downwards. This is a key aspect of the orientation, determined by the term \( 4p \) in the equation:\[(x - h)^2 = 4p(y - k)\]Here are some important points about a vertical axis:
- The right side of the equation contains the \( y \)-variable, indicating the axis is parallel to the y-axis.
- The parabola is symmetric about a vertical line that passes through its vertex.
- If \( p > 0 \), the parabola opens upwards; if \( p < 0 \), it opens downwards.
Solving for Parameter p
The parameter \( p \) in the parabola equation provides essential information regarding the parabola's width and direction. Here’s how to solve for \( p \):To find \( p \), we use a point that the parabola passes through, not just the vertex. Substituting this point into the equation helps solve for \( p \). For example, if the vertex is \((h, k)\) and the parabola passes through a point \((x_1, y_1)\), then substitute these into the vertex form:\[(x_1 - h)^2 = 4p(y_1 - k)\]Simplify this equation to solve for \( p \):
- Subtract \( h \) from \( x_1 \) and square the result.
- Subtract \( k \) from \( y_1 \).
- Set the two sides equal and solve for \( 4p \), and then divide to isolate \( p \).
Other exercises in this chapter
Problem 34
\(29-48\) Sketch the curve with the given polar equation. $$r=1-3 \cos \theta$$
View solution Problem 34
(a) Find parametric equations for the ellipse \(x^{2} / a^{2}+y^{2} / b^{2}=1 .\) [Hint: Modify the equations of the circle in Example \(2 . ]\) (b) Use these p
View solution Problem 35
\(29-48\) Sketch the curve with the given polar equation. $$r=\theta, \quad \theta \geqslant 0$$
View solution Problem 36
Find an equation for the conic that satisfies the given conditions. Parabola, horizontal axis, passing through \((-1,0),(1,-1),\) and \((3,1)\)
View solution