Problem 35
Question
Factor the trinomial. $$ 3 c^{2}-37 c+44 $$
Step-by-Step Solution
Verified Answer
The factored form of the trinomial \(3 c^{2}-37 c+44\) is \((3c-11) (c-4)\)
1Step 1: Identify the coefficient of each term
The coefficients of the equation are \(3, -37, 44\) respectively.
2Step 2: Find two numbers
Find two numbers that multiply to \(3 x 44\) ..which gives 132, and also the same two numbers would add up to -37 to get the middle term. After some trial and error, those two numbers are found to be -11 and -12.
3Step 3: Split the middle term
Split the middle term of the polynomial using the two numbers found in the previous step. This gives us \(3c^{2} -11c -12c +44\).
4Step 4: Factor by grouping
Note that the first two terms have a mutual factor of \(c\) and the last two terms have a mutual factor of \(4\). This gives us \(c(3c-11) -4(3c-11)\).
5Step 5: Completing the Factoring
The factored form of the equation would be \((3c-11) (c-4)\) since these two factors give the original polynomial expression when multiplied.
Key Concepts
Polynomial EquationsFactoring by GroupingQuadratic Expressions
Polynomial Equations
Polynomial equations involve expressions that include variables raised to whole number exponents. In our original exercise, we deal with the trinomial equation \( 3c^2 - 37c + 44 \). Trinomials are a type of polynomial with three terms.
The objective is often to rewrite these equations in their factorable form, if possible, to simplify or solve them.
A polynomial equation can have:
The objective is often to rewrite these equations in their factorable form, if possible, to simplify or solve them.
A polynomial equation can have:
- a constant term which doesn’t contain any variables — here it's 44,
- linear term with the variable raised to the power of one, such as \(-37c\), and
- a quadratic term with the variable raised to the power two, seen in \(3c^2\).
Factoring by Grouping
Factoring by grouping is a method used to simplify a polynomial into the product of simpler polynomials. It is particularly useful when dealing with trinomials that are not easily factorable by other means. In the step-by-step solution, this method involves breaking down the trinomial equation into four terms and then grouping the terms to find common factors.
Here's what happens:
This method proves advantageous when solving polynomial equations by making it easier to identify solutions.
Here's what happens:
- First, determine the target factors by multiplying the leading coefficient (3) by the constant (44) to get 132.
- Next, find two numbers that multiply to give 132 and add up to -37; these numbers in our example are -11 and -12.
- Incorporate these numbers into separate expressions and group: \(3c^2 - 11c - 12c + 44\).
- Lastly, factor each group separately: \(c(3c-11) -4(3c-11)\).
This method proves advantageous when solving polynomial equations by making it easier to identify solutions.
Quadratic Expressions
Quadratic expressions are a subset of polynomial expressions where the highest exponent of the variable is 2. In the exercise, \( 3c^2 - 37c + 44 \) is the quadratic expression we're working with. Quadratics generally have the form \( ax^2 + bx + c \).
Understanding quadratics:
Understanding quadratics:
- They graph as parabolas, displaying symmetrical shapes.
- The solutions to the quadratic equation or the roots can be found through various methods, including factoring, completing the square, or using the quadratic formula.
- In our trinomial, we're factoring to find these components, effectively determining where these roots or solutions occur.
Other exercises in this chapter
Problem 34
Solve the equation. \(8(n+9)(n-9)(n+12)=0\)
View solution Problem 34
$$ (2 d+3)(3 d+1) $$
View solution Problem 35
PERFECT SQUARES Factor the expression. $$ 16 w^{2}-80 w+100 $$
View solution Problem 35
Use a vertical format to add or subtract. $$ \left(2 m-8 m^{2}-3\right)+\left(m^{2}+5 m\right) $$
View solution