Problem 35
Question
Estimate \(\Delta_{1} H^{\circ}\) for the conversion of \(1 \mathrm{~mol}\) carbon monoxide to carbon dioxide by combination with molecular oxygen. Is this reaction exothermic or endothermic?
Step-by-Step Solution
Verified Answer
The reaction is exothermic with \(\Delta_{1} H^{\circ} = -283 \text{ kJ/mol}\).
1Step 1: Write Down the Reaction
The reaction for the conversion of carbon monoxide (CO) to carbon dioxide (CO₂) by combining with molecular oxygen (O₂) is:\[2 ext{ CO} (g) + ext{O}_2 (g)
ightarrow 2 ext{ CO}_2 (g)\]
2Step 2: Calculate the Standard Enthalpy Change
To find \(\Delta_{1} H^{\circ}\) for 1 mole of CO, we need the standard enthalpies of formation (∆H⁰ₙ) for CO and CO₂.- \(\Delta_f H^{\circ} ( ext{CO}) = -110.5 \text{ kJ/mol}\)- \(\Delta_f H^{\circ} ( ext{CO}_2) = -393.5 \text{ kJ/mol}\)Using the formula for the reaction's standard enthalpy change:\[\Delta_{r} H^{\circ} = \sum (\Delta_f H^{\circ} \text{ of products}) - \sum (\Delta_f H^{\circ} \text{ of reactants})\]Substitute the values:\[\Delta_{1} H^{\circ} = [2(-393.5)] - [2(-110.5)]\]\[= -787 + 221\]\[= -566 \text{ kJ for 2 moles}; \ -283 \text{ kJ for 1 mole of CO}\]
3Step 3: Determine Exothermic or Endothermic
Since \(\Delta_{1} H^{\circ} = -283 \text{ kJ/mol}\) is negative, the reaction is exothermic.
Key Concepts
Enthalpy of ReactionExothermic and Endothermic ReactionsStandard Enthalpy of Formation
Enthalpy of Reaction
The enthalpy of reaction, denoted as \( \Delta_r H^{\circ} \), indicates the heat change during a chemical reaction at standard conditions. Standard conditions are often at a pressure of 1 atm and a temperature of 25°C (298 K). This value helps understand whether a reaction absorbs or releases heat. Enthalpy, represented by the symbol \( H \), is akin to measuring the total "heat content" in a system. In chemistry, we are often interested in the change in enthalpy, rather than the total enthalpy itself. Changes in enthalpy during chemical reactions can signal the energy transfers as bonds break and new bonds form. The enthalpy of reaction can be calculated using the formula:
- \( \Delta_{r} H^{\circ} = \sum (\Delta_f H^{\circ} \text{ of products}) - \sum (\Delta_f H^{\circ} \text{ of reactants}) \)
Exothermic and Endothermic Reactions
Chemical reactions are often categorized by how they transfer energy, specifically heat. Two primary categories describe these energy changes: exothermic and endothermic reactions.
- Exothermic Reactions: These reactions release heat into the surroundings. They are commonly felt because they increase the temperature of the surroundings (e.g., burning wood). A negative value for \( \Delta_{1} H^{\circ} \) indicates an exothermic process, as energy is expelled.
- Endothermic Reactions: These reactions absorb heat from the surroundings, thus reducing the temperature of the environment (e.g., melting ice). For these reactions, \( \Delta_{1} H^{\circ} \) is positive, indicating an uptake of energy from the surrounding area.
Standard Enthalpy of Formation
The standard enthalpy of formation, \( \Delta_f H^{\circ} \), is a crucial concept used to compute the enthalpy of reaction. It represents the change in enthalpy during the formation of 1 mole of a substance from its elements in their standard states, measured at 1 atm and 25°C.
- Standard State: This refers to the most stable form of an element or compound at standard conditions.
- Reference Points: The standard enthalpy of formation for a pure element in its reference state (like O2, N2) is zero. This serves as the baseline. Values for compounds are typically based on experimental data and vary depending on the specific substance.
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