Problem 35
Question
Compare the graph of the function with the graph of \(f(x)=\arcsin x\) \(g(x)=\arcsin (-x)\)
Step-by-Step Solution
Verified Answer
The graph of \(g(x)=\arcsin(-x)\) is a reflection of the graph of \(f(x)=\arcsin x\) in the y-axis. For \(x>0\), \(g(x)\) takes the negative of the corresponding \(y\)-values from \(f(x)\) and for \(x<0\), \(g(x)\) takes the negative of the corresponding \(y\)-values from \(f(x)\).
1Step 1: Understanding Function Transformations
The transformation \(f(x) \rightarrow f(-x)\) results in reflection of the graph along the y-axis. Thus, \(g(x)=\arcsin(-x)\) will be the reflection of \(f(x)=\arcsin x\) in the y-axis which means the positive y-values of \(f(x)\) will correspond to the negative x-values of \(g(x)\) and vice-versa.
2Step 2: Drawing Graphs
Draw the graph of \(f(x) = \arcsin x\) and \(g(x) = \arcsin (-x)\). The graph of \(f(x) =\arcsin x\) rises from -π/2 when x=-1 to π/2 when x=1. When the graph is reflected along the y-axis to get \(g(x)=\arcsin -x, the graph rises from -π/2 when x=1 to π/2 when x=-1.
3Step 3: Analysis of the Graphs
The values of \(f(x)\) and \(g(x)\) are equal at x=0, since both \(f(0)\) and \(g(0)\) are 0. For \(x>0\), \(g(x) = -f(x)\), and for \(x<0\), \(g(x) = -f(x)\). Thus the graph of \(g(x)\) is a reflection of the graph of \(f(x)\) in the y-axis.
Key Concepts
Understanding Function TransformationsExploring Graph ReflectionsDiving into Inverse Trigonometric Functions
Understanding Function Transformations
Function transformations are critical concepts in mathematics that change the appearance of a graph through translations, reflections, stretches, or compressions. When we say "transformation," it often involves altering a function in a way that its graph shifts horizontally or vertically. A common type of transformation is a reflection, such as when you change a function from \( f(x) \) to \( f(-x) \). This transformation mirrors the graph over the y-axis.
In the context of the arcsine function, if you start with \( f(x) = \arcsin x \), changing it to \( g(x) = \arcsin(-x) \) results in this y-axis reflection. This transformation essentially flips each point on the graph across the y-axis, which means the graph of \( g(x) \) appears as the mirror image of \( f(x) \). This effect preserves the graph's overall shape but changes the direction in which it unfolds across the x-axis.
In the context of the arcsine function, if you start with \( f(x) = \arcsin x \), changing it to \( g(x) = \arcsin(-x) \) results in this y-axis reflection. This transformation essentially flips each point on the graph across the y-axis, which means the graph of \( g(x) \) appears as the mirror image of \( f(x) \). This effect preserves the graph's overall shape but changes the direction in which it unfolds across the x-axis.
- Transformation doesn't change the y-values but shifts around x-axis placements.
- Reflection transformations like \( f(-x) \) switch x values, not the function's shape.
Exploring Graph Reflections
Graph reflections are a specific type of function transformation that results in a symmetrical image of the original graph. When examining the function \( g(x) = \arcsin(-x) \), its graph is a perfect reflection of \( f(x) = \arcsin x \) across the y-axis.
This kind of reflection means positive x-values on the original graph now map to negative x-values on the reflected graph, and vice versa. At the same time, y-values remain untouched. When you draw the graphs of these functions, notice how the graph of \( f(x) \) rising from \(-\pi/2\) at x = -1 to \(\pi/2\) at x = 1, flips for \( g(x) \) to \(-\pi/2\) at x = 1 to \(\pi/2\) at x = -1. This illustrates how reflections maintain angles and distances but swap sides.
This kind of reflection means positive x-values on the original graph now map to negative x-values on the reflected graph, and vice versa. At the same time, y-values remain untouched. When you draw the graphs of these functions, notice how the graph of \( f(x) \) rising from \(-\pi/2\) at x = -1 to \(\pi/2\) at x = 1, flips for \( g(x) \) to \(-\pi/2\) at x = 1 to \(\pi/2\) at x = -1. This illustrates how reflections maintain angles and distances but swap sides.
- Reflections produce symmetric graphs on opposite sides of an axis.
- The shape of the graph remains consistent, but orientation changes.
- Positive and negative x-values swap places in a y-axis reflection.
Diving into Inverse Trigonometric Functions
Inverse trigonometric functions are essential tools for solving equations involving trigonometric expressions. They help reverse the process of regular trigonometric functions. In the realm of inverse functions, the arcsine function is denoted by \( \arcsin x \) and represents the angle whose sine is \( x \).
Let's take a closer look at \( f(x) = \arcsin x \). As an inverse function, it takes an input between -1 and 1 and returns an output ranging from \(-\pi/2\) to \(\pi/2\). This range ensures the function is well-defined and can accurately map values from the sine function's outputs back to angles. So when you transform \( f(x) \) into \( g(x) = \arcsin(-x) \), you're utilizing reflections to keep within these bounds but shift how input values relate to angles.
Keep in mind:
Let's take a closer look at \( f(x) = \arcsin x \). As an inverse function, it takes an input between -1 and 1 and returns an output ranging from \(-\pi/2\) to \(\pi/2\). This range ensures the function is well-defined and can accurately map values from the sine function's outputs back to angles. So when you transform \( f(x) \) into \( g(x) = \arcsin(-x) \), you're utilizing reflections to keep within these bounds but shift how input values relate to angles.
Keep in mind:
- Inverse functions like \( \arcsin x \) have restricted domains to maintain one-to-one mappings.
- The range of \( \arcsin x \) ensures you can solve for the correct angle values.
- Comparing graph forms helps in visualizing transformations effectively.
Other exercises in this chapter
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