Problem 35
Question
Add or subtract as indicated. $$ \frac{x^{2}-2 x}{x^{2}+3 x}+\frac{x^{2}+x}{x^{2}+3 x} $$
Step-by-Step Solution
Verified Answer
The result of the addition is \(\frac{2x² - x}{x² +3x}\).
1Step 1: Identify the Common Denominator
The common denominator of the two fractions is \(x^{2}+3x\). It is the same in both fractions, so there's no need to find the lowest common denominator.
2Step 2: Add or Subtract the Numerators
When the fractions have the same denominators, add or subtract the numerators based on the operation indicated. Here, we need to add the numerators. So, the equation becomes: \[(x² -2x) + (x²+x)\] Simplifying the above equation gives \(2x² -x\).
3Step 3: Write the Sum or Difference over the Common Denominator
Now, write the sum or difference of the numerators over the common denominator. So, our final expression becomes \[\frac{2x² - x}{x² +3x}\]
Key Concepts
Common DenominatorNumerical SimplificationAlgebraic ExpressionsFraction Addition
Common Denominator
In the world of fractions, a common denominator is like finding a shared stage for two performers. Both fractions need to "stand" on the same value to be properly added or subtracted.
In this exercise, the two fractions already have a common denominator: \(x^2 + 3x\). This makes our job much easier since there's no need to manipulate the denominators to make them the same.
When fractions share the same denominator, it's all about working with the numerators, leaving the shared denominator unchanged. Remember: no extra work needed if the denominators already match!
In this exercise, the two fractions already have a common denominator: \(x^2 + 3x\). This makes our job much easier since there's no need to manipulate the denominators to make them the same.
When fractions share the same denominator, it's all about working with the numerators, leaving the shared denominator unchanged. Remember: no extra work needed if the denominators already match!
Numerical Simplification
Numerical simplification might sound complex, but it's simply the act of combining or rewriting numerical expressions in a simpler form. Once you have the same denominator, focus shifts to the numerators.
In our case, the expression states: \((x^2-2x) + (x^2+x)\). We need to combine these terms by collecting like terms (those that have the same variable and exponent).
By adding the coefficients of \( x^2 \) and \( x \), the result is \(2x^2-x\). Each step reduces the expression into something more straightforward, making the math easier to digest.
Simplification is a helpful tool to keep expressions neat and solutions manageable.
In our case, the expression states: \((x^2-2x) + (x^2+x)\). We need to combine these terms by collecting like terms (those that have the same variable and exponent).
By adding the coefficients of \( x^2 \) and \( x \), the result is \(2x^2-x\). Each step reduces the expression into something more straightforward, making the math easier to digest.
Simplification is a helpful tool to keep expressions neat and solutions manageable.
Algebraic Expressions
Algebraic expressions are like sentences in the language of algebra. They often contain numbers, variables, and operators (like addition or subtraction).
When working with these expressions, it's important to understand how to manipulate them correctly. In our fraction, the algebraic expressions are found in both the numerators and the denominators.
To tackle these, recognize pattern: terms with "\(x^2\)," terms with "\(x\)," and constant numbers.
Managing such terms allows you to add, subtract, and even factor the expressions if needed. They are the building blocks for solving not only this problem but also many others in algebra.
When working with these expressions, it's important to understand how to manipulate them correctly. In our fraction, the algebraic expressions are found in both the numerators and the denominators.
To tackle these, recognize pattern: terms with "\(x^2\)," terms with "\(x\)," and constant numbers.
Managing such terms allows you to add, subtract, and even factor the expressions if needed. They are the building blocks for solving not only this problem but also many others in algebra.
Fraction Addition
Adding fractions isn't too different from adding numbers: it's just a bit more elaborate due to denominators and numerators. With a common denominator in place, focus shifts to the top part—the numerators.
For this exercise, we start by simply adding the numerators \((x^2-2x) + (x^2+x)\). Then, carry out the addition keeping like terms together, bringing us to \(2x^2-x\).
Once added, place this new numerator back over the common denominator to form the final answer: \( \frac{2x^2 - x}{x^2 + 3x}\). This step-by-step adds precision to our fraction addition skills and reinforces the logical flow from problem to solution.
For this exercise, we start by simply adding the numerators \((x^2-2x) + (x^2+x)\). Then, carry out the addition keeping like terms together, bringing us to \(2x^2-x\).
Once added, place this new numerator back over the common denominator to form the final answer: \( \frac{2x^2 - x}{x^2 + 3x}\). This step-by-step adds precision to our fraction addition skills and reinforces the logical flow from problem to solution.
Other exercises in this chapter
Problem 35
In Exercises \(27-38,\) add or subtract terms whenever possible. $$3 \sqrt{18}+5 \sqrt{50}$$
View solution Problem 35
In Exercises \(31-40,\) factor the difference of two squares. $$9 x^{2}-25 y^{2}$$
View solution Problem 36
Simplify each exponential expression $$ \frac{x^{30}}{x^{10}} $$
View solution Problem 36
express the distance between the given numbers using absolute value. Then find the distance by evaluating the absolute value expression. \(-26\) and \(-3\)
View solution