Problem 35
Question
A closed curve encircles several conductors. The line integral \(\phi \overrightarrow{\boldsymbol{B}} \cdot d \vec{l}\) around this curve is \(3.83 \times 10^{-4} \mathrm{T} \cdot \mathrm{m} .\) (a) What is the net current in the conductors? (b) If you were to integrate around the curve in the opposite direction, what would be the value of the line integral? Explain.
Step-by-Step Solution
Verified Answer
(a) 303.4 A;
(b) Line integral is \(-3.83 \times 10^{-4} \mathrm{T} \cdot \mathrm{m}\).
1Step 1: Use Ampère's Law
According to Ampère's Law, the line integral of the magnetic field \( \overrightarrow{\boldsymbol{B}} \) around a closed path is equal to \( \mu_0 \) times the net current \( I \) enclosed by the path. The formula for this is: \( \oint \overrightarrow{\boldsymbol{B}} \cdot d \vec{l} = \mu_0 I \).Given that \( \oint \overrightarrow{\boldsymbol{B}} \cdot d \vec{l} = 3.83 \times 10^{-4} \mathrm{T} \cdot \mathrm{m} \), we can use this equation to find the net current, \( I \).
2Step 2: Solve for Net Current
We know that:\[ \oint \overrightarrow{\boldsymbol{B}} \cdot d \vec{l} = \mu_0 I \]Solving for \( I \), we have:\[ I = \frac{\oint \overrightarrow{\boldsymbol{B}} \cdot d \vec{l}}{\mu_0} \]Assuming \( \mu_0 = 4\pi \times 10^{-7} \text{ T} \cdot \text{m/A} \), substitute \( 3.83 \times 10^{-4} \text{ T} \cdot \text{m} \) for the line integral:\[ I = \frac{3.83 \times 10^{-4}}{4\pi \times 10^{-7}} \approx 303.4 \text{ A} \].
3Step 3: Consider the Opposite Direction Integral
If the integration is performed in the opposite direction, this simply inverts the sign of the line integral due to the reversal of path direction. Thus, the value becomes \(-3.83 \times 10^{-4} \mathrm{T} \cdot \mathrm{m} \). Ampère's Law itself remains unchanged as it is a scalar relation dependent on the enclosed current and measures direction change with a negative sign.
Key Concepts
Magnetic FieldLine IntegralNet Current
Magnetic Field
A magnetic field is a region around a magnetic material or a moving electric charge within which the force of magnetism acts. It is represented by the symbol \( \overrightarrow{\boldsymbol{B}} \), and it's a vector field.
- Think of the magnetic field lines like invisible threads pulling magnetic objects towards or away from a magnet.
- These lines give us a visual cue about the strength and direction of the magnetic influence.
Line Integral
In mathematics, a line integral is a type of integral where a function is integrated along a curve. In physics, particularly electromagnetism, it describes how a field behaves over a path or boundary. For the magnetic field \( \overrightarrow{\boldsymbol{B}} \), we use a line integral to understand its cumulative effect across a closed loop.
- The line integral is computed using \( \oint \overrightarrow{\boldsymbol{B}} \cdot d \vec{l} \), representing the integral of the magnetic field over the path \( d \vec{l} \).
- This integral helps in calculating the total magnetic effect along a given path around current-carrying conductors.
Net Current
Net current indicates the total current flowing through conductors encircled by a chosen closed path. Ampère's Law provides the concept that relates the magnetic field around a path to the current enclosed by it.
- According to Ampère's Law, \( \oint \overrightarrow{\boldsymbol{B}} \cdot d \vec{l} = \mu_0 I \), where \( \mu_0 \) is the permeability of free space, a constant. By solving this equation for \( I \), we find the net current.
- In our exercise, the given line integral allowed us to compute the enclosed current as approximately 303.4 A.
Other exercises in this chapter
Problem 33
A closely wound, circular coil with a diameter of 4.00 cm has 600 turns and carries a current of 0.500 A. What is the magnitude of the magnetic field (a) at the
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A closely wound coil has a radius of 6.00 \(\mathrm{cm}\) and carries a current of 2.50 A. How many turns must it have if, at a point on the coil axis 6.00 \(\m
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A long, straight, cylindrical wire of radius \(R\) carries a current uniformly distributed over its cross section. At what location is the magnetic field produc
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A 15.0 -cm-long solenoid with radius 2.50 \(\mathrm{cm}\) is closely wound with 600 turns of wire. The current in the windings is 8.00 A. Compute the magnetic f
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