Problem 35
Question
\(29-40\) Find an equation for the parabola that has its vertex at the origin and satisfies the given condition(s). Directrix: \(y=-10\)
Step-by-Step Solution
Verified Answer
The equation of the parabola is \(x^2 = 40y\).
1Step 1: Identify the Parabola Type and Orientation
Given that the directrix is a horizontal line at \(y = -10\) and the vertex is at the origin \((0,0)\), the parabola opens upwards. Parabolas that open up or down have the general equation form \(x^2 = 4py\).
2Step 2: Determine the Value of \(p\)
The distance \(p\) from the vertex to the directrix is 10 units, since the directrix is at \(y = -10\) and the vertex is at \(y = 0\). Hence, \(p = 10\). Since the parabola opens upwards, \(p\) remains positive.
3Step 3: Write the Equation of the Parabola
Using the general form \(x^2 = 4py\) and substituting \(p = 10\), the equation of the parabola becomes \(x^2 = 4(10)y\). Simplifying this gives \(x^2 = 40y\).
Key Concepts
Vertex Form of a ParabolaDirectrix of a ParabolaOrientation of Parabolas
Vertex Form of a Parabola
Understanding the vertex form of a parabola is key to easily identifying the parabola's properties from its equation. The vertex form of a parabola is expressed as \[ y = a(x - h)^2 + k \] where
- \( (h, k) \) is the vertex of the parabola,
- \( a \) determines the width and direction of the parabola's opening.
Directrix of a Parabola
The directrix of a parabola serves as a fundamental component in understanding its shape and location. A directrix is a line, which, together with the focus, gives a geometric definition to the parabola.For a parabola, every point on it is equidistant to a fixed point known as the focus and a fixed line known as the directrix. This means the parabola is the set of all points such that the distance to the focus equals the distance to the directrix.In our exercise example, the directrix is at \( y = -10 \), which communicates that the parabola does not stretch infinitely vertically; rather, it stops once it reaches the same distance from the origin as the distance to the directrix. From given conditions, we identify the directrix to correctly position the parabola in the space, making it possible to write the parabola's equation correctly.
Orientation of Parabolas
The orientation of a parabola tells us the direction in which it opens, and it is determined by both its vertex form and the sign of the parameter \( p \). In the equation \( x^2 = 4py \), \( p \) plays a critical role:
- If \( p > 0 \), the parabola opens upwards.
- If \( p < 0 \), it opens downwards.
Other exercises in this chapter
Problem 35
Solve the equations $$ \begin{aligned} x &=X \cos \phi-Y \sin \phi \\ y &=X \sin \phi+Y \cos \phi \end{aligned} $$ for \(X\) and \(Y\) in terms of \(x\) and \(y
View solution Problem 35
Find an equation for the ellipse that satisfies the given conditions. Length of major axis: 4 , length of minor axis: \(2,\) foci on \(y\) -axis
View solution Problem 36
Find an equation for the hyperbola that satisfies the given conditions. Vertices: \((0, \pm 6),\) asymptotes: \(y=\pm \frac{1}{3} X\)
View solution Problem 36
(a) Find the eccentricity and identify the conic. (b) Sketch the conic and label the vertices. $$ r=\frac{8}{3+\cos \theta} $$
View solution