Problem 35
Question
(1) What are the dimensions of density, which is mass per volume?
Step-by-Step Solution
Verified Answer
The dimensions of density are \([M L^{-3}]\).
1Step 1: Identify the Formula for Density
Density is defined as mass per unit volume. The formula for density \( \rho \) is given by \( \rho = \frac{{m}}{{V}} \), where \( m \) is the mass and \( V \) is the volume.
2Step 2: Analyze the Dimensions of Mass
The dimension of mass is represented as \([M]\). This notation indicates that mass has one fundamental dimension, denoted as \( M \).
3Step 3: Analyze the Dimensions of Volume
Volume is the space occupied by a substance and is typically represented in terms of length. The dimensional formula for volume is \([L^3]\) because it involves three linear dimensions (i.e., length, width, and height).
4Step 4: Compute the Dimensions of Density
To find the dimensions of density, divide the dimensional representation of mass \([M]\) by that of volume \([L^3]\). Thus, the dimensions of density are \( \left[ \frac{M}{L^3} \right] = [M L^{-3}] \).
5Step 5: State the Dimensions of Density
The dimensions of density are expressed in terms of mass and volume as \([M L^{-3}]\). This indicates that density is dependent on the mass dimension and inversely proportional to the cube of the length dimension.
Key Concepts
Mass Per VolumeDimensional AnalysisFundamental DimensionsVolume Dimensions
Mass Per Volume
Density tells us how much mass is packed into a given volume. It is a measure of how much stuff there is in a certain amount of space. Imagine packing a suitcase for a trip. If you pack more clothes into the same suitcase, the suitcase becomes more dense. This is similar to the concept of density in physics.
To find density, we use the formula:
To find density, we use the formula:
- Density, \( \rho = \frac{m}{V} \)
Dimensional Analysis
Dimensional analysis is like a tool that helps us check our math in physics. It ensures that equations or expressions make sense with respect to the physical dimensions involved.
Using dimensions allows us to confirm if our calculations are correct and consistent.
In the case of density, we need to consider both dimensions of mass and volume.
This gives us clarity about what exactly our calculations refer to. This is crucial in maintaining accuracy, especially in scientific equations.
By analyzing dimensions in equations, we can:
By analyzing dimensions in equations, we can:
- Verify if an equation is dimensionally correct.
- Convert units appropriately.
- Identify any possible errors in a formula or calculation.
Fundamental Dimensions
In physics, every physical quantity is expressed in terms of fundamental dimensions. The fundamental dimensions include things like:
- Mass (\( [M] \))
- Length (\( [L] \))
- Time (\( [T] \))
Volume Dimensions
Volume describes how much space a substance or object occupies, and it is intrinsically linked to length. Think about a box; it has dimensions of length, width, and height. When calculating volume, these three dimensions are multiplied, giving the dimensional formula \( [L^3] \). This means we consider three linear (length-based) dimensions creating a three-dimensional space. When calculating density, the volume dimension \( [L^3] \) comes into play as we use it in the denominator: \( [M L^{-3}] \). This shows us that density decreases if the volume increases, assuming mass stays constant. Being familiar with volume dimensions helps us visualize and quantify the capacity of an object, which is essential in understanding how much matter it can hold.
Other exercises in this chapter
Problem 32
(III) I agree to hire you for 30 days and you can decide between two possible methods of payment: cither \((1) \$ 1000\) a day, or (2) one penny on the first da
View solution Problem 35
What are the dimensions of density, which is mass per volume?
View solution Problem 36
The speed \(v\) of an object is given by the equation \(v=A t^{3}-B t,\) where \(t\) refers to time. \((a)\) What are the dimensions of \(A\) and \(B ?(b)\) Wha
View solution Problem 36
$$ \begin{array}{l}{\text { (II) The spced } v \text { of an object is given by the equation }} \\ {v=A t^{3}-B t, \text { where } t \text { refers to time. (a)
View solution