Problem 347
Question
$$ \lim _{x \rightarrow 0}(\ln \cot x)^{\tan x}\\{\text { Ans. } 1\\} $$
Step-by-Step Solution
Verified Answer
The limit of the given function as x approaches 0 is 0
1Step 1: Identify the indeterminate form
First identify the form of the given function as x approaches 0, which is \((\ln \cot x)^{\tan x}\). We can see it is of the form \(0^0\) as \(\ln \cot 0\) tends to \(-\infty\) and \(\tan 0\) is 0, which makes the expression indeterminate.
2Step 2: Simplify the expression
In order to solve it, we can simplify the logarithmetic part of the function by using the relationship \(\ln a^b = b \ln a\), then it becomes \(\tan x \cdot \ln(\cot x)\). Now, we can confirm that as x approaches 0, the expression is of the \(0 \cdot -\infty\) form, which can be simplified into a \(\frac{0}{0}\) or \(\frac{-\infty}{\infty}\) form by putting \(\tan x = \frac{1}{\cot x}\), thus the expression can be written as \(\frac{\ln(\cot x)}{\cot x}\)
3Step 3: Apply l'Hopital's Rule
Now that we've transformed our indeterminate form into a quotient, we can apply l'Hopital's rule, which states that for any limit of the form \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\), we can take the derivative of both the numerator and the denominator individually until we get a determinable limit. Derivatives of the logarithm function and the cotangent function are \(\frac{1}{x}\) and \(-\csc^2 x\), respectively. Hence, we have \(\lim_{x \to 0} \frac{1/\cot x}{-\csc^2 x}\), which simplifies to \(\lim_{x \to 0} -\tan x = 0\)
4Step 4: Evaluate the limit
After simplification, our function becomes a determinate form. So now, we can apply the limit and get the final result. Thus, the value of the limit as x tends to 0 is 0
Key Concepts
Indeterminate FormsL'Hopital's RuleLogarithmic Functions
Indeterminate Forms
Indeterminate forms occur in calculus when evaluating a limit doesn't initially yield a clear outcome. They are called 'indeterminate' because it's not immediately obvious what value they will resolve to, which necessitates the use of further analysis or mathematical techniques.
- The common types of indeterminate forms include: \(\frac{0}{0}\), \(\frac{\infty}{\infty}\), \(0\cdot\infty\), \(\infty - \infty\), \(1^\infty\), \(0^0\), and \(\infty^0\).
- In our exercise, the expression \((\ln \cot x)^{\tan x}\) as \(x\) approaches 0 appeared initially to be of form \(0^0\), transforming into a \(0 \cdot -\infty\) form during simplification. These forms complicate direct evaluation of limits.
L'Hopital's Rule
L'Hopital's Rule is a powerful tool in calculus used to resolve limits involving indeterminate forms, particularly the \(\frac{0}{0}\) and \(\frac{\infty}{\infty}\) types. The rule allows us to simplify these forms by differentiating the numerator and the denominator separately.
- To apply L'Hopital's Rule, transform the indeterminate form into a fraction where you get one of the applicable forms \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\).
- Differentiate both the numerator and denominator independently, and then compute the limit of this new function.
- In our specific exercise, transforming the expression to \(\frac{\ln(\cot x)}{\cot x}\) allowed us to use L'Hopital's Rule as both components tended toward forms suitable for its application.
Logarithmic Functions
Logarithmic functions, most simply understood as the inverse of exponential functions, play a significant role in calculus. Here, they help in dealing with exponents and complexities involving growth, decay, and trends.
- The logarithm base \(b\), usually denoted as \(\log_b(x)\), answers the question: to what power must \(b\) be raised, to yield \(x\)? Most commonly used bases are 10 and \(e\) (natural logarithms), with \(\ln(x)\) denoting the natural logarithm.
- In calculus, logarithmic differentiation often simplifies the process of finding limits, especially when dealing with exponentials involved in a given function.
- In our exercise, simplifying the function using logarithmic identities, like \(\ln(a^b) = b \ln(a)\), transformed a complex power into a solvable product.
Other exercises in this chapter
Problem 345
$$ \lim _{x \rightarrow \infty} x^{2}\left[\cosh \frac{a}{x}-1\right]\left\\{\text { Ans. } \frac{a^{2}}{2}\right\\} $$
View solution Problem 346
$$ \lim _{x \rightarrow 0}\left(\frac{5}{2+\sqrt{9+x}}\right)^{\frac{1}{\sin x}}\left\\{\text { Ans. } e^{-\frac{1}{30}}\right\\} $$
View solution Problem 348
$$ \lim _{x \rightarrow 0} \frac{1-\sqrt{1+x^{2}} \cos x}{\tan ^{4} x}\left\\{\text { Ans. } \frac{1}{3}\right\\} $$
View solution Problem 349
$$ \lim _{x \rightarrow 0} \frac{\sqrt[3]{1+3 x}-\sqrt{1+2 x}}{x^{2}}\left\\{\text { Ans. }-\frac{1}{2}\right\\} $$
View solution