Problem 34
Question
Write the matrix in reduced row-echelon form. $$ \left[\begin{array}{rr} 1 & -3 \\ -1 & 8 \\ 0 & 4 \\ -2 & 10 \end{array}\right] $$
Step-by-Step Solution
Verified Answer
The reduced row-echelon form of the provided matrix is the 4x2 matrix \[ \begin{bmatrix} 1 & 0 \\ 0 & 1 \\ 0 & 0 \\ 0 & 0\end{bmatrix}\].
1Step 1: Identify the Pivot Element
The first pivot should be the number 1 in the top left of the matrix. The pivot lies at the intersection of the first row and the first column. \[\begin{{bmatrix}}1 & -3 \-1 & 8 \0 & 4 \-2 & 10\end{{bmatrix}}\]
2Step 2: Zero Below the Pivot
By adding suitable multiples of the first row to the other rows, zeros can be placed below the pivot. R2 can be obtained by adding R1 to the original R2, R4 can be obtained by adding 2*R1 to the original R4. \[\begin{{bmatrix}}1 & -3 \0 & 5 \0 & 4 \0 & 4\end{{bmatrix}}\]
3Step 3: Identify the Next Pivot Element
The next pivot element is number 5 in row 2. But in order to simplify the calculation the pivot element should be 1. The second row can be transformed, dividing it by 5. \[\begin{{bmatrix}}1 & -3 \0 & 1 \0 & 4 \0 & 4\end{{bmatrix}}\]
4Step 4: Zero Above and Below the Second Pivot
Adding multiples of the new R2 to R1, R3 and R4 will result in zeros both above and below the second pivot. R3 can be obtained by subtracting 4*R2 from the original R3, R4 can be obtained by subtracting 4*R2 from the original R4, and R1 can be obtained by adding 3*R2 to the original R1. \[\begin{{bmatrix}}1 & 0 \0 & 1 \0 & 0 \0 & 0\end{{bmatrix}}\]
5Step 5: Outcome in Reduced Row-Echelon Form
The matrix is now in Reduced Row-Echelon Form as there are leading 1s from left to right and there is zero below and above leading 1s.
Key Concepts
Matrix OperationsRow-Echelon FormPivot Element
Matrix Operations
Matrix operations are fundamental processes in linear algebra, allowing us to manipulate matrices efficiently to solve various problems. Three primary operations are commonly used: addition, multiplication, and scalar multiplication. Matrix addition involves adding corresponding elements from two matrices of the same dimensions. Matrix multiplication requires a bit more understanding. It involves taking the dot product of the rows of the first matrix with the columns of the second. Only matrices where the number of columns in the first equals the number of rows in the second can be multiplied.
When performing matrix operations, it’s crucial to follow the rules to achieve accurate results. Remember the order of operations, especially in multiplication, as it impacts the outcome. Scalar multiplication is simpler, as it involves multiplying every element in a matrix by a scalar (a single number).
Understanding these operations is key, particularly when solving linear equations or transforming matrices into different forms, such as row-echelon or reduced row-echelon form.
Row-Echelon Form
Row-echelon form (REF) is a special way of arranging elements in a matrix. It simplifies the process of solving systems of linear equations. In REF, the matrix must meet specific criteria:
- All non-zero rows are above rows with all zero elements.
- Each leading coefficient (which is the first non-zero number from the left, in each row) is to the right of the leading coefficient in the row directly above it.
- All entries in a column below a leading coefficient are zero.
Pivot Element
The pivot element is a critical concept when dealing with matrices in linear algebra. In a matrix, the pivot is the first non-zero element in each row, and it is crucial during the transformation process into row-echelon or reduced row-echelon form.
Why is a pivot element important?
- It is used as a reference point for operations to create zeros in the rest of the column.
- A pivot element of 1 makes calculations straightforward. For this reason, row operations might involve multiplying the row to create a leading 1.
Other exercises in this chapter
Problem 34
Find the determinant of the matrix by the method of expansion by cofactors. Expand using the indicated row or column. \(\left[\begin{array}{rrrr}10 & 8 & 3 & -7
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Use the matrix capabilities of a graphing utility to find the inverse of the matrix (if it exists). $$ \left[\begin{array}{rrr} 0.6 & 0 & -0.3 \\ 0.7 & -1 & 0.2
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Use a determinant to find an equation of the line passing through the points. $$ \left(-\frac{1}{2}, 3\right),\left(\frac{5}{2}, 1\right) $$
View solution Problem 35
Find the determinant of the matrix. Expand by cofactors on the row or column that appears to make the computations easiest. Use a graphing utility to confirm yo
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