Problem 34
Question
Write the equation in slope-intercept form. Then graph the equation. $$ y=-2 $$
Step-by-Step Solution
Verified Answer
The given equation is already in slope-intercept form with slope 0 and y-intercept -2. It represents a horizontal line crossing the y-axis at (0, -2).
1Step 1: Recognize the equation's form
The given equation is \(y = -2\). This is already in slope-intercept form of a line, which is \(y = mx + b\) where m is the slope of the line and b is the y-intercept.
2Step 2: Determine the slope and y-intercept
Since there's no x-term in the equation, the slope m is 0 and the y-intercept is -2. This means the line is horizontal and crosses the y-axis at the point (0,-2).
3Step 3: Graph the equation
Sketch a horizontal line that passes through the y-axis at the point (0, -2). The line represents all the solutions to the equation.
Key Concepts
horizontal linegraphing linear equationsy-intercept
horizontal line
A horizontal line is one of the simplest types of lines you can encounter in graphing. This type of line runs parallel to the x-axis and has a unique characteristic: it has a slope of zero.
The equation of a horizontal line can often be written in the form of \(y = c\), where \(c\) is a constant value.
This means that no matter which point on the line you look at, the y-value remains the same. For example, in the equation \(y = -2\), every point on this line has a y-coordinate of -2, such as (1, -2), (-3, -2), and (5, -2).
The equation of a horizontal line can often be written in the form of \(y = c\), where \(c\) is a constant value.
This means that no matter which point on the line you look at, the y-value remains the same. For example, in the equation \(y = -2\), every point on this line has a y-coordinate of -2, such as (1, -2), (-3, -2), and (5, -2).
- A horizontal line has an undefined x-intercept, except in a rare case where it lies along the x-axis.
- The slope (\[m = 0\]) indicates it's neither rising nor falling.
- It's always parallel to the x-axis regardless of its y-value.
graphing linear equations
Graphing linear equations is an essential skill in algebra, helping you visualize the relationships between variables.
There are different forms in which a linear equation can appear, but a common one is the slope-intercept form, \(y = mx + b\). Here, \(m\) represents the slope, while \(b\) is the y-intercept.
When graphing such an equation, begin by plotting the y-intercept on the y-axis. This point is where the line crosses the y-axis, and its coordinates are (0, b).
There are different forms in which a linear equation can appear, but a common one is the slope-intercept form, \(y = mx + b\). Here, \(m\) represents the slope, while \(b\) is the y-intercept.
When graphing such an equation, begin by plotting the y-intercept on the y-axis. This point is where the line crosses the y-axis, and its coordinates are (0, b).
- For the equation \(y = -2\), the graph starts at (0, -2).
- Use the slope, \(m\), to find additional points. However, with a horizontal line like \(y = -2\), the slope is 0, leading to no vertical change as you move along the x-axis.
- Draw the line through these points, maintaining its parallel alignment with the x-axis.
y-intercept
The y-intercept of a line is the point at which the line crosses the y-axis. It is a crucial element in the slope-intercept form of a linear equation, \(y = mx + b\), where \(b\) denotes the y-intercept.
For the equation \(y = -2\), the y-intercept is clearly \(-2\), showing that the graph intersects the y-axis at the point (0, -2).
For the equation \(y = -2\), the y-intercept is clearly \(-2\), showing that the graph intersects the y-axis at the point (0, -2).
- The y-intercept is significant, especially for evaluating and sketching the graph of the equation.
- It gives a definite starting point when drawing the line on a coordinate plane.
- Identifying the y-intercept helps understand the vertical position of the line in relation to the origin.
- A change in the y-intercept shifts the entire line up or down, without altering its slope.
Other exercises in this chapter
Problem 34
Plot the points and find the slope of the line passing through the points. $$(4,1),(6,1)$$
View solution Problem 34
Find the \(x\) -intercept of the graph of the equation. $$ 2 x-6 y=-18 $$
View solution Problem 34
Rewrite the equation in function form. \(\frac{1}{2} x+\frac{5}{2} y=1\)
View solution Problem 35
Solve the equation graphically. Check your solution algebraically. $$-5 x+4=12-3 x$$
View solution