Problem 34
Question
Write a differential equation expressing the information given and, when possible, find a general solution for the differential equation. The rate of change with respect to time \(t\) of the demand \(D\) for a product is decreasing in proportion to the demand at time \(t\).
Step-by-Step Solution
Verified Answer
The general solution is \( D(t) = C_1 e^{-kt} \).
1Step 1: Understanding the Problem
We are given that the rate of change of demand \( D \) over time \( t \) is decreasing proportionally to the demand itself. This suggests an exponential decay model, which means as \( D \) increases, the rate at which it decreases rises linearly.
2Step 2: Writing the Differential Equation
The problem translates to a differential equation where \( \frac{dD}{dt} = -kD \), where \( k > 0 \) is the proportionality constant. This equation shows that the change in demand \( \frac{dD}{dt} \) is negatively proportional to the current demand \( D \).
3Step 3: Solving the Differential Equation
Separate the variables so that we have \( \frac{1}{D} \, dD = -k \, dt \). Integrate both sides: \( \int \frac{1}{D} \, dD = \int -k \, dt \), resulting in \( \ln|D| = -kt + C \).
4Step 4: Finding the General Solution
To find \( D \), we exponentiate both sides: \( |D| = e^{C}e^{-kt} \). Let \( C_1 = e^{C} \, (C_1 > 0) \), resulting in the general solution \( D(t) = C_1 e^{-kt} \).
5Step 5: Interpreting the Solution
The general solution \( D(t) = C_1 e^{-kt} \) indicates that the demand decreases exponentially over time, characterized by the decay rate \( k \). This model only fits if the demand is initially positive.
Key Concepts
Exponential DecayRate of ChangeDemand FunctionProportionality Constant
Exponential Decay
Exponential decay describes a situation where a quantity decreases at a rate proportional to its current value. This concept is often associated with processes like radioactive decay or cooling, but it also applies to economic models, like demand functions. In these models, as the current demand for a product increases, the rate at which the demand decreases also rises.
This results in a characteristic mathematical model that resembles an exponential function. If the demand decreases over time, we can represent it using the equation \[ \frac{dD}{dt} = -kD \] where \( D \) is the demand and \( k \) is a positive constant.
This equation tells us that the rate of change in demand \( \frac{dD}{dt} \) is proportional and opposing to the demand itself. Through integration and algebra, we derive the function \[ D(t) = C_1 e^{-kt} \] which proves an exponential decrease over time.
This results in a characteristic mathematical model that resembles an exponential function. If the demand decreases over time, we can represent it using the equation \[ \frac{dD}{dt} = -kD \] where \( D \) is the demand and \( k \) is a positive constant.
This equation tells us that the rate of change in demand \( \frac{dD}{dt} \) is proportional and opposing to the demand itself. Through integration and algebra, we derive the function \[ D(t) = C_1 e^{-kt} \] which proves an exponential decrease over time.
Rate of Change
The rate of change refers to how much a variable, such as demand, changes over time. It is an essential concept in calculus and differential equations.
In our example, the rate of change of demand \( \frac{dD}{dt} \) reflects how rapidly the demand shifts as time progresses. This rate is negative, signifying a decline.
By setting up a differential equation like \( \frac{dD}{dt} = -kD \), we gain deep insights into how demand behaves over time and how external factors or initial conditions can influence it.
In our example, the rate of change of demand \( \frac{dD}{dt} \) reflects how rapidly the demand shifts as time progresses. This rate is negative, signifying a decline.
By setting up a differential equation like \( \frac{dD}{dt} = -kD \), we gain deep insights into how demand behaves over time and how external factors or initial conditions can influence it.
- A greater absolute value of \( k \) implies a faster decay rate.
- Modifications in the initial conditions or assumptions can lead to a different demand trajectory.
Demand Function
A demand function quantifies the relationship between demand for a product and influencing variables like time and price.
In this problem, our analysis conveys that demand decreases over time and the function is determined primarily by time. The differential equation \( \frac{dD}{dt} = -kD \) allows us to understand this temporal relationship by establishing how demand varies as time unfolds.
The equation posits that the demand function \( D(t) \) evolves exponentially, yielding \[ D(t) = C_1 e^{-kt} \] as the solution. It captures scenarios typical in markets where demand diminishes over time, possibly due to factors like saturation or changing consumer interests.
In this problem, our analysis conveys that demand decreases over time and the function is determined primarily by time. The differential equation \( \frac{dD}{dt} = -kD \) allows us to understand this temporal relationship by establishing how demand varies as time unfolds.
The equation posits that the demand function \( D(t) \) evolves exponentially, yielding \[ D(t) = C_1 e^{-kt} \] as the solution. It captures scenarios typical in markets where demand diminishes over time, possibly due to factors like saturation or changing consumer interests.
- It implies each time unit decreases demand by a factor influenced by \( e^{-kt} \).
- Understanding this function can help in planning marketing strategies or regulating inventory.
Proportionality Constant
A proportionality constant, denoted by \( k \), determines the strength of the relationship between two quantities. In our differential equation \( \frac{dD}{dt} = -kD \), the constant \( k \) governs how quickly demand decreases over time.
The larger the value of \( k \), the steeper the decline in demand. Conversely, a smaller \( k \) indicates a slower decay. This constant is crucial for modeling exercises in fields involving exponential change, such as economics or biology.
The larger the value of \( k \), the steeper the decline in demand. Conversely, a smaller \( k \) indicates a slower decay. This constant is crucial for modeling exercises in fields involving exponential change, such as economics or biology.
- If \( k \) is known, it helps predict future demand with greater accuracy.
- Adjusting \( k \) can simulate different market conditions for analysis.
Other exercises in this chapter
Problem 33
For Activities 33 through \(36,\) write a differential equation expressing the information given and, when possible, find a general solution for the differentia
View solution Problem 33
Explain, using the definition of a density function, why the definite integral calculation of any probability associated with this density function must result
View solution Problem 34
If \(g\) is a probability density function defined on \(-\inftyb)=1-\int_{a}^{b} g(x) d x\)
View solution Problem 36
Use Euler's method and two steps to estimate \(y\) when \(x=5\), given \(\frac{d y}{d x}=\frac{5}{y}\) with initial condition (1,1)
View solution