Problem 34
Question
Use the center and the radius to graph each circle. $$ x^{2}+(y+4)^{2}=144 $$
Step-by-Step Solution
Verified Answer
The center of the circle is at \((0,-4)\) and the radius is \(12\) units.
1Step 1: Identify the Center
The given equation of the circle is \(x^{2}+(y+4)^{2}=144\), which is in standard form \((x-h)^{2}+(y-k)^{2}=r^{2}\), where the center of the circle is \((h,k)\). Here, \(h\) is \(0\) and \(k\) is \(-4\), so the center is \((0,-4)\).
2Step 2: Identify the Radius
The radius \(r\) of the circle is the square root of the right side of the equation. In this case, \(\sqrt{144} = 12\). So, the radius of the circle is \(12\).
3Step 3: Graph the Circle
Now plot the center of the circle \((0,-4)\) on the graph. From the center, measure out the radius in all directions by \(12\) units. Draw the circle by connecting these points. This will create a circle centered at \((0,-4)\), with a radius of \(12\) units.
Key Concepts
Circle GraphingStandard Form of a CircleRadius and Center of a Circle
Circle Graphing
Graphing a circle on a coordinate plane is an enjoyable way to visualize the shape from its algebraic equation. To get started, you need to know both the center and the radius of the circle. These two bits of information will help guide where the circle sits and how big it is.
- Plot the Center: Locate the center of the circle on your graph. For example, if the center is \(0, -4\), find this point on the grid.
- Measure the Radius: Use the radius measurement to determine how far the circle extends from the center point in every direction.
- Draw the Circle: With a compass or by hand, sketch the circle by maintaining a constant distance from the center equal to the radius.
Standard Form of a Circle
The standard form of a circle's equation is crucial for easily deciphering a circle's geometric attributes. This form is written as \((x-h)^{2}+(y-k)^{2}=r^{2}\), where \(h, k\) represents the coordinates of the center of the circle, and \(r\) is the circle's radius.
Let's consider the equation \(x^{2}+(y+4)^{2}=144\). Notice how it reflects the standard form structure:
Let's consider the equation \(x^{2}+(y+4)^{2}=144\). Notice how it reflects the standard form structure:
- Here, \(h = 0\) and \(k = -4\), indicating that the circle's center is at the point \(0, -4\).
- The expression on the right side, \((y+4)^{2}\), accounts for the vertical shift, effectively translating the circle downward by four units.
- The right side of the equation equals \(r^{2}\), allowing you to calculate the radius by taking the square root of this number.
Radius and Center of a Circle
The radius and center are fundamental components of a circle, acting as the blueprint for both its location and size.
- Center Coordinates: These tell you where the circle is placed on the graph. Expressed as \(h, k\) in the standard form equation, they provide the precise midpoint around which the circle expands. For instance, \(0, -4\) shows this circle's position.
- Radius Length: The radius defines the size of the circle, indicating how far its edge reaches from the center in every direction. In our example, the radius is \sqrt{144} = 12\, suggesting a consistent extension in all dimensions.
Other exercises in this chapter
Problem 34
Solve each equation for \(y .\) Graph each relation on your graphing calculator. Use the TRACE feature to locate the vertices. $$ x^{2}-y^{2}=1 $$
View solution Problem 34
a. Writing Describe the relationship between the center of a circle and the axes of symmetry of the circle. b. Make a Conjecture Where is the center of an ellip
View solution Problem 35
Find the foci for each equation of an ellipse. $$ 36 x^{2}+4 y^{2}=144 $$
View solution Problem 35
Solve each equation for \(y .\) Graph each relation on your graphing calculator. Use the TRACE feature to locate the vertices. $$ 3 x^{2}-y^{2}=2 $$
View solution