Problem 34
Question
The sum of all four-digit numbers that can be formed by using the digits \(2,4,6,8\) (when repetition of digits is not allowed) is a. 133320 b. 533280 c. 53328 d. none of these
Step-by-Step Solution
Verified Answer
The correct answer is a. 133320.
1Step 1: Calculate Total Number of Permutations
First, we calculate how many different four-digit numbers can be formed using the digits 2, 4, 6, and 8 without repeating any digits. This is calculated using the formula for permutations, which is factorial of the number of digits. Hence, the total number of permutations is \(4! = 24\).
2Step 2: Arrange Digits Systematically
When we place four unique digits in four positions, each digit appears in each position the same number of times. Since we have 24 permutations and 4 positions, each digit appears in each position 6 times (24 permutations / 4 positions = 6 times per position).
3Step 3: Calculate Contribution of Each Position
Each digit contributes differently based on its position (thousands, hundreds, tens, or ones). For instance, when a digit is in the thousands place, its contribution to the number is 1000 times the digit. Therefore, determine the total contribution of each digit by calculating \(6 \times\) the sum of the four digits (2 + 4 + 6 + 8) in their respective positions.
4Step 4: Calculate Contribution for All Positions
For each digit's contribution across all positions: - Thousands: \(6 \times (2 + 4 + 6 + 8) \times 1000 = 12000 \times 1000 = 12000000\)- Hundreds: \(6 \times (2 + 4 + 6 + 8) \times 100 = 12000 \times 100 = 1200000\)- Tens: \(6 \times (2 + 4 + 6 + 8) \times 10 = 12000 \times 10 = 120000\)- Units: \(6 \times (2 + 4 + 6 + 8) \times 1 = 12000 \times 1 = 12000\).
5Step 5: Final Sum Calculation
Now add up the total contributions from all four positions: \(12000000 + 1200000 + 120000 + 12000 = 13332000\).
6Step 6: Identify Correct Option
After calculating the sum of all four-digit permutations, convert 13332000 to the standard four-digit format by dividing by 1000, resulting in 133320. Thus, the correct answer corresponds to option a, which is 133320.
Key Concepts
four-digit numbersfactorial calculationnumber contribution by positionsum of permutations
four-digit numbers
When dealing with permutations, especially with a set of unique digits like 2, 4, 6, and 8, it is essential to recognize the possible combinations that can be created. In this context, a four-digit number involves selecting and arranging these digits in a sequence of four places: thousands, hundreds, tens, and units. Because repetition of digits is not allowed, each arrangement is a unique permutation of these digits. This results in a diverse set of numbers, each formed by a different ordering of the four original digits.
factorial calculation
The factorial function is key to calculating the total number of permutations of a set of items. For four unique digits, the calculation is straightforward: use the factorial of 4, denoted as \(4!\), which equals
- \(4 \times 3 \times 2 \times 1 = 24\)
number contribution by position
Each digit in a four-digit number contributes to the total value of the number based on its position. The positions are:
- Thousands
- Hundreds
- Tens
- Units
sum of permutations
To determine the sum of all possible permutations, one must sum the individual contributions of each digit across all positions. Each digit contributes equally in each position across all permutations:
- Thousands: 6 times the sum of the digits multiplied by 1000
- Hundreds: 6 times the sum of the digits multiplied by 100
- Tens: 6 times the sum of the digits multiplied by 10
- Units: 6 times the sum of the digits
Other exercises in this chapter
Problem 32
The sum of the digits in the unit's place of all numbers formed with the help of \(3,4,5,6\) taken all at a time is a. 18 b. 432 c. 108 d. 144
View solution Problem 33
The sum of all the numbers of four different digits that can be made by using the digits \(0,1,2\) and 3 is a. 26664 b. 39996 c. 38664 d. none of these
View solution Problem 35
The number of ordered pairs of integers \((x, y)\) satisfying the equation \(x^{2}+6 x+y^{2}=4\) is a. 2 b. 8 c. 6 d. none of these
View solution Problem 36
The number of five-digit telephone numbers having at least one of their digits repeated is a. 90000 b. \(\quad 100000\) c. 30240 d. 69760
View solution