Problem 34
Question
Suppose that a certain plant is grown along a gradient ranging from nitrogen- poor to nitrogen-rich soil. Experimental data show that the average mass per plant grown in a soil with a total nitrogen content of \(1000 \mathrm{mg}\) nitrogen per \(\mathrm{kg}\) of soil is \(2.7 \mathrm{~g}\) and the rate of change of the average mass per plant at this nitrogen level is \(1.05 \times 10^{-3} \mathrm{~g}\) per mg change in total nitrogen per kg soil. Use a linear approximation to predict the average mass per plant grown in a soil with a total nitrogen content of \(1100 \mathrm{mg}\) nitrogen per \(\mathrm{kg}\) of soil.
Step-by-Step Solution
Verified Answer
The predicted average mass is approximately 2.805 g.
1Step 1: Understanding the Problem
We are given the average mass of the plant when the nitrogen content is 1000 mg/kg, which is 2.7 g. We are also given the rate of change of the average mass with respect to nitrogen content, which is \(1.05 \times 10^{-3} \, \mathrm{g/mg}\). The goal is to estimate the average mass when the nitrogen content is 1100 mg/kg.
2Step 2: Identify Given Values
Let's denote the nitrogen content by \(N\) and the average mass as \(M(N)\). Given: \(M(1000) = 2.7\, \mathrm{g}\) and \(\frac{dM}{dN} = 1.05 \times 10^{-3} \, \mathrm{g/mg}\). We need to find \(M(1100)\).
3Step 3: Apply Linear Approximation Formula
The formula for the linear approximation of a function \(M(N)\) at a point \(a\) is \(M(N) \approx M(a) + M'(a) \times (N - a)\). Here, \(a = 1000\), and our target \(N = 1100\). Substituting the values in, we get:\[M(1100) \approx 2.7 + 1.05 \times 10^{-3} \times (1100 - 1000)\]
4Step 4: Calculate Change in Nitrogen Content
The change in nitrogen content, \( \Delta N \), is \(1100 - 1000 = 100\, \mathrm{mg}\).
5Step 5: Compute Linear Approximation
Substitute \( \Delta N = 100\) into the linear approximation formula:\[M(1100) \approx 2.7 + 1.05 \times 10^{-3} \times 100\]Calculate this:\[M(1100) \approx 2.7 + 0.105 = 2.805\]
6Step 6: Conclusion
The predicted average mass of a plant grown in soil with a nitrogen content of 1100 mg/kg is approximately 2.805 g.
Key Concepts
Nitrogen GradientRate of ChangeAverage Mass Estimation
Nitrogen Gradient
In the context of plant growth, a nitrogen gradient refers to the variation of nitrogen levels in soil. Plants rely heavily on nitrogen as a key nutrient for growing and functioning properly.
When grown along a gradient that ranges from nitrogen-poor to nitrogen-rich soil, plants exhibit differences in growth metrics, such as size or mass.
So, how does this modify growth?
When grown along a gradient that ranges from nitrogen-poor to nitrogen-rich soil, plants exhibit differences in growth metrics, such as size or mass.
So, how does this modify growth?
- Nitrogen aids in building essential proteins.
- It is vital for photosynthesis, a process where plants generate their food.
- Higher nitrogen levels often promote more robust plant growth.
Rate of Change
The rate of change in the average mass of a plant with respect to nitrogen content gives us an indication of how sensitive plant growth is to changes in available nitrogen.
In mathematical terms, this is represented as the derivative, denoted by \(\frac{dM}{dN}\), where \(M\) stands for mass and \(N\) for nitrogen level. Here, the rate of change is \(1.05 \times 10^{-3} \: \mathrm{g/mg}\), signifying how much the plant's average mass changes with each incremental change in nitrogen.
The rate of change is crucial for:
In mathematical terms, this is represented as the derivative, denoted by \(\frac{dM}{dN}\), where \(M\) stands for mass and \(N\) for nitrogen level. Here, the rate of change is \(1.05 \times 10^{-3} \: \mathrm{g/mg}\), signifying how much the plant's average mass changes with each incremental change in nitrogen.
The rate of change is crucial for:
- Predicting growth patterns under different nutritional setups.
- Deciding on fertilizer quantities for desired outcomes.
- Understanding plant adaptability and resilience.
Average Mass Estimation
Average mass estimation utilizes mathematical approximations to predict future outcomes based on currently known data.
This concept is central to making informed predictions about growth outcomes under varied environmental conditions.
In our example, linear approximation is used to project the average plant mass when nitrogen levels shift from 1000 mg/kg to 1100 mg/kg. This requires the application of a straightforward method:
This concept is central to making informed predictions about growth outcomes under varied environmental conditions.
In our example, linear approximation is used to project the average plant mass when nitrogen levels shift from 1000 mg/kg to 1100 mg/kg. This requires the application of a straightforward method:
- Begin with known parameters: the current mass at a specific nitrogen level and the rate of change.
- Apply the linear approximation formula: \[M(N) \approx M(a) + M'(a) \times (N - a)\]
- Substitute values—\(a = 1000\), \(M(a) = 2.7\) g, and \(\Delta N = 100\) mg.
- Compute the approximation: \(M(1100) \approx 2.805\) g.
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Problem 33
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