Problem 34
Question
Solve each equation. See Example 2. $$ |6 x-3|+7=28 $$
Step-by-Step Solution
Verified Answer
The solutions are \(x = 4\) and \(x = -3\).
1Step 1: Isolate the Absolute Value
Start by isolating the absolute value expression. To do this, subtract 7 from both sides of the equation: \[|6x - 3| + 7 - 7 = 28 - 7\]which simplifies to:\[|6x - 3| = 21.\]
2Step 2: Set Up Two Equations
The absolute value expression \(|6x - 3| = 21\) means that \(6x - 3\) can be either 21 or -21. Therefore, we set up two separate equations:Equation 1: \[6x - 3 = 21\]Equation 2: \[6x - 3 = -21.\]
3Step 3: Solve Equation 1
Solve the first equation, \(6x - 3 = 21\). Add 3 to both sides:\[6x - 3 + 3 = 21 + 3\]which simplifies to:\[6x = 24.\]Now, divide by 6:\[x = \frac{24}{6}\]which simplifies to:\[x = 4.\]
4Step 4: Solve Equation 2
Solve the second equation, \(6x - 3 = -21\). Add 3 to both sides:\[6x - 3 + 3 = -21 + 3\]which simplifies to:\[6x = -18.\]Now, divide by 6:\[x = \frac{-18}{6}\]which simplifies to:\[x = -3.\]
5Step 5: Final Answer
The solutions to the original equation \(|6x - 3| + 7 = 28\) are \(x = 4\) and \(x = -3\). These are the values that satisfy the equation.
Key Concepts
Isolation of TermsEquation SolvingTwo Equation Approach
Isolation of Terms
The first important step when solving equations involving absolute values is to isolate the absolute value term. This gives clarity and makes it easier to handle the components of the equation. In our exercise, we had the expression \(|6x - 3| + 7 = 28\), which contains an absolute value expression \(|6x - 3|\).
To isolate this, we subtract 7 from both sides of the equation. This process helps in simplifying the equation by reducing additional terms that don't involve the absolute value.
Here’s how it's done step-by-step:
To isolate this, we subtract 7 from both sides of the equation. This process helps in simplifying the equation by reducing additional terms that don't involve the absolute value.
Here’s how it's done step-by-step:
- Start with \(|6x - 3| + 7 = 28\).
- Subtract 7 from both sides to eliminate the constant outside the absolute value: \(|6x - 3| + 7 - 7 = 28 - 7\).
- This simplifies to: \(|6x - 3| = 21\).
Equation Solving
Once you've isolated the absolute value, the next phase is solving the equation that emerges from it. Because absolute values can represent either positive or negative scenarios, we create two separate equations.
This step ensures all potential values that solve the equation are considered. Here's a breakdown:
This step ensures all potential values that solve the equation are considered. Here's a breakdown:
- The absolute value \( |6x - 3| = 21\) translates to two equations because both \(6x - 3 = 21\) and \(6x - 3 = -21\) can satisfy the absolute value condition.
- By setting these as separate equations, you prepare to solve each scenario independently.
Two Equation Approach
When handling absolute value equations, the two equation approach is crucial. This approach derives from the fundamental nature of absolute values: they measure distance from zero, which can equate to two possible values.
For our problem, we breakdown as follows:
For our problem, we breakdown as follows:
- First equation: \(6x - 3 = 21\). Solve it step-by-step by adding 3 to both sides (\(6x = 24\)), and then dividing by 6 (\(x = 4\)).
- Second equation: \(6x - 3 = -21\). Similarly, add 3 to both sides (\(6x = -18\)), and divide by 6 (\(x = -3\)).
Other exercises in this chapter
Problem 33
Graph each inequality. $$ y+4 x \geq 0 $$
View solution Problem 33
Solve each double inequality. Graph the solution set and write it using interval notation. \(4 \leq x+3 \leq 7\)
View solution Problem 34
Graph the solution set of each system of inequalities on a rectangular coordinate system. $$\left\\{\begin{array}{l}x+y
View solution Problem 34
Graph each inequality. $$ y \geq-\frac{5}{4} x $$
View solution