Problem 34
Question
Solve each equation and check. \(5^{x-1}=(0.04)^{2 x}\)
Step-by-Step Solution
Verified Answer
The solution is \(x = \frac{1}{5}\).
1Step 1: Recognize the Base Change
The equation given is \(5^{x-1} = (0.04)^{2x}\). First, notice that \(5\) is the base of the first exponent and \(0.04\) is the base of the second exponent. Recognize that \(0.04\) can be rewritten as a power of 5: \(0.04 = \left(\frac{1}{25}\right)\), which can further be written as \( (5^{-2}) \). Now the equation becomes \(5^{x-1} = (5^{-2})^{2x}\).
2Step 2: Rewrite Using the Same Base
With both sides of the equation now having a base of 5, we can rewrite it as \(5^{x-1} = 5^{-4x}\). Since the bases are the same, we can set the exponents equal to each other.
3Step 3: Set Exponents Equal
Equate the exponents from each side of the equation: \(x-1 = -4x\). Solve for \(x\) by combining like terms and simplifying the equation.
4Step 4: Solve for x
Solving \(x-1 = -4x\) leads to the following simplification: First add \(4x\) to both sides to get \(x + 4x - 1 = 0\), which simplifies to \(5x - 1 = 0\). Add 1 to both sides, yielding \(5x = 1\). Finally, divide both sides by 5, resulting in \(x = \frac{1}{5}\).
5Step 5: Check the Solution
Substitute \(x = \frac{1}{5}\) back into the original equation to verify: First calculate the left side \(5^{x-1}\): \(5^{\frac{1}{5}-1} = 5^{-rac{4}{5}}\). Now calculate the right side \((0.04)^{2x}\): \((0.04)^{2 \times \frac{1}{5}} = (0.04)^{\frac{2}{5}}\). Since \(0.04 = \left(\frac{1}{25}\right)= (5^{-2})\), this results in \((5^{-2})^{\frac{2}{5}} = 5^{-(\frac{4}{5})}\). Both sides evaluate to \(5^{-\frac{4}{5}}\), confirming our solution \(x = \frac{1}{5}\) is correct.
Key Concepts
Base RewritingExponent RulesSimplifying ExponentsEquation Solving Steps
Base Rewriting
Understanding how to rewrite bases is essential for solving exponential equations effectively. In the equation \(5^{x-1} = (0.04)^{2x}\), the challenge starts with the mismatched bases: 5 and 0.04. The skill here is recognizing equivalent bases. For example:
- 0.04 can be rewritten as a fraction: \(\frac{1}{25}\).
- This fraction can then be expressed as a power of 5: \(5^{-2}\).
Exponent Rules
Once the bases are rewritten to be the same, exponent rules come into play. The main rules involve multiplying exponents and understanding negative exponents. Here’s how they work:
- When you raise a power to another power, you multiply the exponents: \((5^{-2})^{2x} = 5^{-4x}\).
- If you ever encounter a negative exponent like \(5^{-4x}\), it signifies division: \(5^{-4x} = \frac{1}{5^{4x}}\).
Simplifying Exponents
Simplifying exponents involves handling expressions that might look complicated at first. Consider the equation: \(5^{x-1} = 5^{-4x}\). This is simplified by:
- Setting the exponents equal since the bases are the same.
- Equating \(x-1 = -4x\) allows the elimination of the exponents by focusing directly on solving for \(x\).
Equation Solving Steps
The process of solving equations involves clear, methodical steps. Here is a breakdown of the steps used to solve \(x-1 = -4x\):
- Add \(4x\) to both sides to eliminate the \(-4x\) on the right, resulting in \(5x - 1 = 0\).
- Next, add 1 to both sides to isolate terms with \(x\) on one side: \(5x = 1\).
- Finally, divide both sides by 5 to find \(x\): \(x = \frac{1}{5}\).
Other exercises in this chapter
Problem 34
In \(23-34,\) evaluate each function for the given value. Be sure to show your work. $$ \mathrm{f}(x)=4\left(\frac{1}{2}\right)^{-x}+3\left(\frac{1}{2}\right)^{
View solution Problem 34
In \(3-37,\) express each power as a rational number in simplest form. $$ 9^{-2}+9^{\frac{1}{2}} $$
View solution Problem 35
In \(35-63,\) write each expression with only positive exponents and express the answer in simplest form. The variables are not equal to zero. $$ x^{-4} $$
View solution Problem 35
In \(3-37,\) express each power as a rational number in simplest form. $$ 2\left[(3)^{-2}+(4)^{-2}\right]^{-\frac{1}{2}} $$
View solution