Problem 34
Question
Solve a System of Linear Equations by Graphing In the following exercises, solve the following systems of equations by graphing. $$ \left\\{\begin{array}{l} 2 x-2 y=8 \\ y=-3 \end{array}\right. $$
Step-by-Step Solution
Verified Answer
The solution to the system is (7, -3).
1Step 1 - Write the Equations
The given system of equations is: 1. \(2x - 2y = 8\) 2. \(y = -3\)
2Step 2 - Find the Y-Intercepts and X-Intercepts
For the first equation, solve for y to make it easier to graph. \(2x - 2y = 8\) Divide every term by 2: \(x - y = 4\)Solve for y: \(y = x - 4\)For the second equation: \(y = -3\) is a horizontal line at \(y = -3\)
3Step 3 - Plot the Lines on a Graph
Plot the line \(y = x - 4\) by finding the intercepts:When x = 0, \(y = -4\)When y = 0, \(x = 4\)So, the line passes through (0, -4) and (4, 0).Plot the line \(y = -3\), which is a horizontal line passing through \(y = -3\) on the y-axis.
4Step 4 - Determine the Intersection Point
The point of intersection is where the two lines meet on the graph. This point represents the solution to the system of equations. Both lines meet at (7, -3).
Key Concepts
Linear EquationsGraphing MethodsIntersection PointY-InterceptX-Intercept
Linear Equations
Linear equations form the basis of algebra and are essential for understanding more complex mathematical concepts. A linear equation is an equation that makes a straight line when graphed. The general form is expressed as: \[ Ax + By = C \] where \( A \), \( B \), and \( C \) are constants. Each point on this line is a solution to the equation. Linear equations can have variables with the highest exponent of 1, and they don't curve.
Graphing Methods
Graphing methods involve plotting linear equations on a graph to find their solutions visually. Here is a step-by-step approach:
- Find Intercepts: Calculate where the line crosses the x-axis and y-axis.
- Plot Points: Use the intercepts to mark the line on the graph.
- Draw the Line: Connect the points to visualize the line.
Intersection Point
In graphing, the intersection point is where two lines cross each other. This point satisfies both equations simultaneously. To find the intersection:
1. Plot both equations on the same graph. 2. Identify the point where the lines meet.
In our given system, the lines intersect at \(7, -3\). This means \(x = 7 \) and \(y = -3\) satisfy both equations. The intersection point is the solution to the system of equations.
1. Plot both equations on the same graph. 2. Identify the point where the lines meet.
In our given system, the lines intersect at \(7, -3\). This means \(x = 7 \) and \(y = -3\) satisfy both equations. The intersection point is the solution to the system of equations.
Y-Intercept
The y-intercept is the point where a line crosses the y-axis. It occurs when \(x = 0\). For example, in the equation \( y = x - 4 \), the y-intercept is \( -4 \) (when \( x = 0 \), \( y = -4 \)). Knowing the y-intercept helps in accurately plot the line on a graph. To determine the y-intercept:
- Set \( x = 0 \).
- Solve for \( y \).
X-Intercept
The x-intercept is the point where a line crosses the x-axis. It occurs when \( y = 0\). For the given equation \(y = x - 4\), we find the x-intercept by setting \( y = 0 \):
- Solve for \( x \) when \( y = 0 \).
- For instance: \(0 = x - 4 \Rightarrow x = 4\)
Other exercises in this chapter
Problem 32
Solve a System of Linear Equations by Graphing In the following exercises, solve the following systems of equations by graphing. $$ \left\\{\begin{array}{l} -2
View solution Problem 33
Solve a System of Linear Equations by Graphing In the following exercises, solve the following systems of equations by graphing. $$ \left\\{\begin{array}{l} x-3
View solution Problem 35
Solve a System of Linear Equations by Graphing In the following exercises, solve the following systems of equations by graphing. $$ \left\\{\begin{array}{l} 2 x
View solution Problem 36
Solve a System of Linear Equations by Graphing In the following exercises, solve the following systems of equations by graphing. $$ \left\\{\begin{array}{l} x+2
View solution