Problem 34
Question
Show that \(y=x^{1 / 2} w\left(\frac{2}{3} \alpha x^{3 / 2}\right)\) is a solution of Airy's differe equation \(y^{\prime \prime}+\alpha^{2} x y=0, x>0\), whenever \(w\) is a solutic Bessel's equation of order \(\frac{1}{3}\); that is, \(t^{2} w^{\prime \prime}+t w^{\prime}+\left(t^{2}-\frac{1}{9}\right) w\) \(t>0\). [Hint: After differentiating, substituting, and simp ing, then let \(t=\frac{2}{3} \alpha x^{3 / 2}\).1
Step-by-Step Solution
Verified Answer
Yes, the function is a solution as shown by substitution and simplification steps.
1Step 1: Differentiate the Function
Start by differentiating the function \( y = x^{1/2} w\left(\frac{2}{3} \alpha x^{3/2}\right) \) with respect to \( x \). This requires applying the product rule: \( y' = \frac{1}{2}x^{-1/2}w(t) + x^{1/2}w'(t)\cdot \frac{d}{dx}\left(\frac{2}{3}\alpha x^{3/2}\right) \). Compute \( \frac{d}{dx} \left(\frac{2}{3}\alpha x^{3/2}\right) = \alpha x^{1/2} \) to get: \( y' = \frac{1}{2}x^{-1/2} w(t) + x^{1/2} w'(t) \cdot \alpha x^{1/2} \). Simplify the expression: \( y' = \frac{1}{2}x^{-1/2} w(t) + \alpha x w'(t) \).
2Step 2: Differentiate Again for Second Derivative
Now, differentiate \( y' = \frac{1}{2}x^{-1/2} w(t) + \alpha x w'(t) \) to find \( y'' \). Differentiate using the product rule and chain rule: \[ y'' = -\frac{1}{4}x^{-3/2} w(t) + \frac{1}{2}x^{-1/2}w'(t)\cdot \alpha x^{1/2} + \alpha w'(t) + \alpha x w''(t) \cdot \alpha x^{1/2} \]. Simplify it to \[ y'' = -\frac{1}{4}x^{-3/2} w(t) + \alpha x^{1/2} w'(t) + \alpha^2 x w''(t) + \alpha w'(t) \].
3Step 3: Substitute into Airy's Differential Equation
Substitute \( y'' \) and \( \alpha^2 x y \) into Airy's equation \( y'' + \alpha^2 x y = 0 \). Use \( \alpha^2 x y = \alpha^2 x \cdot x^{1/2}w(t) = \alpha^2 x^{3/2}w(t) \). Insert into equation: \(-\frac{1}{4}x^{-3/2} w(t) + \alpha x^{1/2} w'(t) + \alpha^2 x w''(t) + \alpha w'(t) + \alpha^2 x^{3/2}w(t) = 0 \).
4Step 4: Simplify and Use Bessel's Equation
Factor the equation in Step 3 based on \( w(t) \) and its derivatives. Substitute \( t = \frac{2}{3} \alpha x^{3/2} \) into the equation to link with Bessel's equation. Confirm that these terms satisfy Bessel's equation \( t^2 w'' + t w' + (t^2 - \frac{1}{9}) w = 0 \). This consistency implies the initial function \( y \) is a solution to Airy's equation.
Key Concepts
Bessel's EquationDifferential EquationsSolution VerificationOrder of Bessel's Equation
Bessel's Equation
Bessel's Equation plays a significant role in mathematical physics, particularly when analyzing wave propagation and static potentials. In the context of Airy's Differential Equation, the function \( w \) is specified to satisfy Bessel's equation of order \( \frac{1}{3} \). This means the equation it satisfies is:
- \( t^2 w^{\prime\prime} + t w^{\prime} + (t^2 - \frac{1}{9})w = 0 \)
Differential Equations
Differential equations are mathematical expressions that involve unknown functions and their derivatives. These equations are foundational in describing various physical phenomena, ranging from physics to engineering and beyond. Airy's differential equation, which we are solving here, describes a broad set of physical situations like optical diffraction patterns and quantum mechanics.
- The form of Airy's differential equation given is: \( y^{\prime \prime} + \alpha^2 x y = 0 \)
Solution Verification
To verify whether the assumed function \( y = x^{1/2} w\left(\frac{2}{3} \alpha x^{3/2}\right) \) is a solution to Airy's differential equation, we follow a structured process of substitution and simplification. By first differentiating the function and then substituting back into the original differential equation, one can check if the equation holds true.
- The derived expressions \( y' \) and \( y'' \) need to link correctly with Airy's differential equation through these substitutions.
Order of Bessel's Equation
The order of Bessel's equation, denoted in this problem as \( \frac{1}{3} \), determines the specific form and complexity of the Bessel functions involved. These orders affect the overall solution behavior and properties.When looking at Bessel's equation with an order of \( \frac{1}{3} \), it alters how the solutions behave as functions of \( t \).
- This order contributes to determining the specific characteristic oscillations and zeros of the function \( w(t) \).
Other exercises in this chapter
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