Problem 34
Question
Nitrogen-13, with a half-life of \(10.0 \mathrm{~min}\), decays by beta emission. (a) Write down the decay equation to determine the daughter product and whether the beta particle is a positron or electron. (b) If a sample of pure \({ }^{13} \mathrm{~N}\) has a mass of \(1.50 \mathrm{~g}\) at a certain time, what is the activity 35.0 min later? (c) What percentage of the sample is \({ }^{13} \mathrm{~N}\) at this time? (d) What alternative process could have happened to the nitrogen-13? Write down its decay equation and determine the daughter product for this process.
Step-by-Step Solution
Verified Answer
(a) \( ^{13}N \rightarrow ^{13}C + e^+ + \nu_e \). (b) Use \( A = A_0 e^{-\lambda t} \). (c) Calculate \( N/N_0 \) and convert to %. (d) Electron capture: \( ^{13}N + e^- \rightarrow ^{13}C + \nu_e \).
1Step 1: Write the Beta Decay Equation for Nitrogen-13
Nitrogen-13 decays by beta-plus decay, which means it transforms by emitting a positron. The beta decay equation for \( ^{13}N \) can be written as \( ^{13}N \rightarrow ^{13}C + e^+ + u_e \). Here, \( e^+ \) is a positron and \( u_e \) is a neutrino. The daughter product is Carbon-13.
2Step 2: Calculate Activity 35 Minutes Later
Activity (\(A\)) can be calculated using the formula \( A = A_0 e^{-\lambda t} \). The decay constant \( \lambda \) is calculated by \( \lambda = \frac{\ln(2)}{t_{1/2}} \), where \( t_{1/2} = 10 \) minutes. Calculate \( \lambda \), then substitute \( \lambda \) and \( t = 35 \) minutes into the activity formula to get the final activity.
3Step 3: Determine Remaining Percentage of Nitrogen-13
The remaining percentage of \(^{13}N\) can be found using the formula \( N = N_0 e^{-\lambda t} \). First calculate \( N/N_0 \), which represents the fraction of \(^{13}N\) left. Then convert it into a percentage.
4Step 4: Identify Alternative Decay Process for Nitrogen-13
An alternative decay process for \(^{13}N\) is electron capture. In this process, one proton in the nucleus captures an electron, transforming into a neutron. The reaction is \( ^{13}N + e^- \rightarrow ^{13}C + u_e \), with Carbon-13 as the daughter product.
Key Concepts
Nitrogen-13Half-lifePositron EmissionRadioactive Decay
Nitrogen-13
Nitrogen-13 is a radioactive isotope of nitrogen. It is denoted as \(^ {13}N\), where the number 13 represents its atomic mass, which is the sum of its protons and neutrons. This isotope contains 7 protons and 6 neutrons.
Nitrogen-13 is commonly used in positron emission tomography (PET) scans in the medical field due to its short half-life and the emission of positrons. This makes it ideal for imaging and diagnosing medical conditions.
It typically originates from the bombardment of natural nitrogen with high-energy particles such as protons. This process is often performed in a cyclotron, a type of particle accelerator.
Nitrogen-13 is commonly used in positron emission tomography (PET) scans in the medical field due to its short half-life and the emission of positrons. This makes it ideal for imaging and diagnosing medical conditions.
It typically originates from the bombardment of natural nitrogen with high-energy particles such as protons. This process is often performed in a cyclotron, a type of particle accelerator.
Half-life
The half-life of Nitrogen-13 is 10 minutes. This means that every 10 minutes, half of the atoms in a sample of \(^ {13}N\) will decay into more stable products.
The concept of a half-life is crucial in understanding radioactive decay as it describes the rate at which instability reduces.
The concept of a half-life is crucial in understanding radioactive decay as it describes the rate at which instability reduces.
- In 10 minutes, 50% of the original sample remains.
- In 20 minutes, 25% of the original sample is left.
- In 30 minutes, 12.5% remains, and so on.
Positron Emission
Positron emission is a type of beta decay where a proton inside the nucleus transforms into a neutron, emitting a positron and a neutrino. For Nitrogen-13, this process can be written as: \(^ {13}N \rightarrow ^ {13}C + e^+ + u_e \)
Here, \( e^+ \) represents the positron, which is essentially an anti-electron with the same mass as an electron but a positive charge.
During this process:
Here, \( e^+ \) represents the positron, which is essentially an anti-electron with the same mass as an electron but a positive charge.
During this process:
- The atomic number decreases by 1, turning the nitrogen into carbon.
- The mass number remains unchanged at 13.
- The emitted positron (along with the neutrino) travels a short distance before it encounters an electron, leading to annihilation and the release of gamma rays, which can be detected externally.
Radioactive Decay
Radioactive decay is a natural process by which unstable atomic nuclei lose energy by emitting radiation. For isotopes like Nitrogen-13, this decay occurs via positron emission, transforming them into more stable elements like Carbon-13.
This transformation involves the emission of particles and energy. Understanding radioactive decay helps predict the behavior of radioactive isotopes over time.
Besides positron emission, Nitrogen-13 can also decay through a process known as electron capture, described by the reaction: \(^ {13}N + e^- \rightarrow ^{13}C + u_e \).
This transformation involves the emission of particles and energy. Understanding radioactive decay helps predict the behavior of radioactive isotopes over time.
Besides positron emission, Nitrogen-13 can also decay through a process known as electron capture, described by the reaction: \(^ {13}N + e^- \rightarrow ^{13}C + u_e \).
- In electron capture, a proton captures an electron and converts to a neutron.
- This also results in the formation of Carbon-13 as the daughter product.
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