Problem 34
Question
List all numbers from the given set that are: a. natural numbers, b. whole numbers, c. integers, d. rational numbers, e. irrational numbers, I. real numbers. $$\\{-7,-0 . \overline{6}, 0, \sqrt{49}, \sqrt{50}\\}$$
Step-by-Step Solution
Verified Answer
**Natural numbers:** \(\{0, \sqrt{49}\}\), **Whole Numbers:** \(\{\sqrt{49}, 0\}\), **Integers:** \(\{-7, 0, \sqrt{49}\}\), **Rational numbers:** \(\{-7,-0 . \overline{6}, 0, \sqrt{49}\}\), **Irrational numbers:** \(\{\sqrt{50}\}\), **Real numbers:** \(-7,-0 . \overline{6}, 0, \sqrt{49}, \sqrt{50\).
1Step 1: Identify the Natural Numbers
Natural numbers are all non-negative counting numbers. From our provided set \(\{-7,-0 . \overline{6}, 0, \sqrt{49}, \sqrt{50}\}\), the numbers that fall into this category are 0, \(\sqrt{49}\).
2Step 2: Identify the Whole Numbers
Whole numbers are natural numbers, including zero. From our set, \(\sqrt{49}\) and 0 are whole numbers.
3Step 3: Identify the Integers
Integers are whole numbers that include both positive and negative numbers. So from our set, -7, 0, and \(\sqrt{49}\) are integers.
4Step 4: Identify the Rational Numbers
Rational numbers are numbers that can be expressed as fractions (ratios) of integers. From the given set, -7, -0.\(\overline{6}\), 0, and \(\sqrt{49}\) are rational.
5Step 5: Identify the Irrational Numbers
Irrational numbers are numbers which cannot be expressed as fractions of integers, but they are real numbers. From the provided set, only \(\sqrt{50}\) is irrational as its decimal representation is non-repeating and non-terminating.
6Step 6: Identify the Real Numbers
Real numbers encompass natural, whole, integer, rational, and irrational numbers. Every number in our set \(-7,-0 . \overline{6}, 0, \sqrt{49}, \sqrt{50}\) is a real number.
Key Concepts
Natural NumbersWhole NumbersIntegersRational NumbersIrrational Numbers
Natural Numbers
Natural numbers are often referred to as counting numbers. They are the set of positive numbers beginning from 1 and go on infinitely, like 1, 2, 3, 4, and so on. It’s essential to note that natural numbers do not include zero, negatives, or any form of decimal or fraction.
However, in some mathematical contexts, zero may be counted among the natural numbers. That can be a source of confusion, but for the problem's sake, we are looking for simple counting numbers.
From the original set \( \{-7,-0 . \overline{6}, 0, \sqrt{49}, \sqrt{50}\} \), \(\sqrt{49} \ = 7 \) is the natural number as it falls within this straightforward counting category.
However, in some mathematical contexts, zero may be counted among the natural numbers. That can be a source of confusion, but for the problem's sake, we are looking for simple counting numbers.
From the original set \( \{-7,-0 . \overline{6}, 0, \sqrt{49}, \sqrt{50}\} \), \(\sqrt{49} \ = 7 \) is the natural number as it falls within this straightforward counting category.
Whole Numbers
Whole numbers expand the category of natural numbers by including zero. They start from 0 and move upwards in the counting sequence, so they are
- 0
- 1
- 2
- 3
- and so on...
Integers
Integers are an extended family of whole numbers. They include all those positive numbers, zero, and their negative counterparts too. Integers are numbers without end in both the positive and negative directions. Examples are -2, -1, 0, 1, 2, continuing onward. Due to their expansive range, integers do not include fractions or decimals.
In the original set \( \{-7, -0.\overline{6}, 0, \sqrt{49}, \sqrt{50}\} \), the integers present are
In the original set \( \{-7, -0.\overline{6}, 0, \sqrt{49}, \sqrt{50}\} \), the integers present are
- -7
- 0
- \(\sqrt{49} = 7\)
Rational Numbers
Rational numbers are very versatile. They can be expressed in the form of a fraction \( \frac{a}{b} \), where \(a\) and \(b\) are integers and \(b eq 0\). This means rational numbers can be fractions, integers, positive or negative, and, importantly, they can have repeating or terminating decimals.
The set \( \{-7, -0.\overline{6}, 0, \sqrt{49}, \sqrt{50} \} \)
provides several rational numbers:
The set \( \{-7, -0.\overline{6}, 0, \sqrt{49}, \sqrt{50} \} \)
provides several rational numbers:
- -7 (it can be seen as \( \frac{-7}{1} \))
- -0.\overline{6} (which equals \( \frac{-2}{3} \) when expressed as a fraction)
- 0 (which is \( \frac{0}{1} \))
- \(\sqrt{49} = 7 \)
Irrational Numbers
Irrational numbers are the opposite of rational numbers. They cannot be expressed as a simple fraction and their decimal representations are neither terminating nor repeating. This makes them a fascinating set of numbers that exist between the rational ones on the number line.
A classic example of an irrational number is \( \pi \). In the given set \( \{-7, -0.\overline{6}, 0, \sqrt{49}, \sqrt{50} \} \), \(\sqrt{50}\) is irrational. While \(\sqrt{50}\) can be approximated as about 7.071, it continues in a non-repeating, non-terminating fashion, solidifying its place as irrational.
A classic example of an irrational number is \( \pi \). In the given set \( \{-7, -0.\overline{6}, 0, \sqrt{49}, \sqrt{50} \} \), \(\sqrt{50}\) is irrational. While \(\sqrt{50}\) can be approximated as about 7.071, it continues in a non-repeating, non-terminating fashion, solidifying its place as irrational.
Other exercises in this chapter
Problem 34
perform the indicated multiplication. $$(-9)(-12)(-18)(0)(-3)$$
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Find each sum without the use of a number line. $$-\frac{5}{6}+\frac{1}{3}$$
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Write each English phrase as an algebraic expression. Let the variable \(x\) represent the number. three decreased by a number
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Simplify each fraction by reducing it to its lowest terms. $$\frac{45}{50}$$
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