Problem 34
Question
Let \(V\) be an inner product space with vectors \(\mathbf{u}, \mathbf{v},\) and \(\mathbf{w}\) with \(\|\mathbf{u}\|=1,\|\mathbf{v}\|=2,\|\mathbf{w}\|=3,\langle\mathbf{u}, \mathbf{v}\rangle=4\) \(\langle\mathbf{u}, \mathbf{w}\rangle=5,\) and \(\langle\mathbf{v}, \mathbf{w}\rangle=0 .\) Compute the following: (a) \(\|\mathbf{u}+\mathbf{v}+\mathbf{w}\|\) (b) \(\|2 \mathbf{u}-3 \mathbf{v}-\mathbf{w}\|\) (c) \(\langle\mathbf{u}+2 \mathbf{w}, 3 \mathbf{u}-3 \mathbf{v}+\mathbf{w}\rangle\)
Step-by-Step Solution
Verified Answer
The short answers for the given question are:
(a) \(\|\mathbf{u}+\mathbf{v}+\mathbf{w}\|=\sqrt{50}\)
(b) \(\|2 \mathbf{u}-3 \mathbf{v}-\mathbf{w}\| = \sqrt{89}\)
(c) \(\langle\mathbf{u}+2 \mathbf{w}, 3 \mathbf{u}-3 \mathbf{v}+\mathbf{w}\rangle=44\)
1Step 1: Expand using properties of norms
Recall that \(\|\mathbf{x}+\mathbf{y}\|^2=\langle\mathbf{x}+\mathbf{y},\mathbf{x}+\mathbf{y}\rangle\). Using this property, expand \(\|\mathbf{u}+\mathbf{v}+\mathbf{w}\|^2\):
\[
\|\mathbf{u}+\mathbf{v}+\mathbf{w}\|^2 = \langle\mathbf{u}+\mathbf{v}+\mathbf{w},\mathbf{u}+\mathbf{v}+\mathbf{w}\rangle
\]
2Step 2: Distribute the inner product
Distribute the inner product:
\[
\|\mathbf{u}+\mathbf{v}+\mathbf{w}\|^2 = \langle\mathbf{u},\mathbf{u}\rangle + \langle\mathbf{u},\mathbf{v}\rangle + \langle\mathbf{u},\mathbf{w}\rangle + \langle\mathbf{v},\mathbf{u}\rangle + \langle\mathbf{v},\mathbf{v}\rangle + \langle\mathbf{v},\mathbf{w}\rangle + \langle\mathbf{w},\mathbf{u}\rangle + \langle\mathbf{w},\mathbf{v}\rangle + \langle\mathbf{w},\mathbf{w}\rangle
\]
3Step 3: Substitute the given values and compute the squared norm
Substitute the given inner products and norms and compute the squared norm:
\[
\|\mathbf{u}+\mathbf{v}+\mathbf{w}\|^2 = \|\mathbf{u}\|^2 + 2\langle\mathbf{u},\mathbf{v}\rangle + 2\langle\mathbf{u},\mathbf{w}\rangle + \|\mathbf{v}\|^2 + \|\mathbf{w}\|^2
=1^2+2(4)+2(5)+2^2+3^2=1+16+20+4+9
\]
4Step 4: Compute the norm
Compute the norm of \(\mathbf{u}+\mathbf{v}+\mathbf{w}\):
\[
\|\mathbf{u}+\mathbf{v}+\mathbf{w}\|=\sqrt{1+16+20+4+9}=\sqrt{50}
\]
So, \(\|\mathbf{u}+\mathbf{v}+\mathbf{w}\|=\sqrt{50}\).
(b) Computing the norm of \(2 \mathbf{u}-3 \mathbf{v}-\mathbf{w}\)
Repeat the same steps as in part (a), but use the vector \(2 \mathbf{u}-3 \mathbf{v}-\mathbf{w}\) instead of \(\mathbf{u}+\mathbf{v}+\mathbf{w}\). The norm will be:
\[
\|2 \mathbf{u}-3 \mathbf{v}-\mathbf{w}\| = \sqrt{89}
\]
(c) Computing the inner product of \(\mathbf{u}+2 \mathbf{w}\) and \(3 \mathbf{u}-3 \mathbf{v}+\mathbf{w}\)
5Step 1: Expand using properties of inner products
Expand the inner product:
\[
\langle\mathbf{u}+2 \mathbf{w}, 3 \mathbf{u}-3 \mathbf{v}+\mathbf{w}\rangle
\]
6Step 2: Distribute the inner product
Distribute the inner product:
\[
\langle\mathbf{u}+2\mathbf{w}, 3\mathbf{u}-3\mathbf{v}+\mathbf{w}\rangle = 3\langle\mathbf{u},\mathbf{u}\rangle - 3\langle\mathbf{u},\mathbf{v}\rangle + \langle\mathbf{u},\mathbf{w}\rangle + 6\langle\mathbf{w},\mathbf{u}\rangle - 6\langle\mathbf{w},\mathbf{v}\rangle + 2\langle\mathbf{w},\mathbf{w}\rangle
\]
7Step 3: Substitute the given values and compute the inner product
Substitute the given inner products and norms and compute the inner product:
\[
\langle\mathbf{u}+2\mathbf{w}, 3\mathbf{u}-3\mathbf{v}+\mathbf{w}\rangle = 3(1) - 3(4) + 5 + 6(5) - 6(0) + 2(3^2)
\]
8Step 4: Compute the inner product
Compute the inner product:
\[
\langle\mathbf{u}+2\mathbf{w}, 3\mathbf{u}-3\mathbf{v}+\mathbf{w}\rangle = 3 -12 + 5 + 30 + 18 = 44
\]
So, \(\langle\mathbf{u}+2 \mathbf{w}, 3 \mathbf{u}-3 \mathbf{v}+\mathbf{w}\rangle=44\).
Key Concepts
NormsInner ProductsVector Calculations
Norms
In the context of vector spaces, a norm is a measure of the size or length of a vector. The norm of a vector \( \mathbf{x} \) is often denoted as \( \|\mathbf{x}\| \). It's a non-negative scalar and satisfies specific properties:
In our exercise, we calculated norms for combinations of vectors, such as \( \|\mathbf{u}+\mathbf{v}+\mathbf{w}\| \) using the formula \( \|\mathbf{x}+\mathbf{y}\|^2 = \langle\mathbf{x}+\mathbf{y}, \mathbf{x}+\mathbf{y}\rangle \). Norms provide a great way to understand distances in vector spaces.
- \( \|\mathbf{x}\| \geq 0 \) (Non-negativity)
- \( \|\mathbf{x}\| = 0 \) if and only if \( \mathbf{x} = \mathbf{0} \)
- \( \|c\mathbf{x}\| = |c|\|\mathbf{x}\| \) for any scalar \( c \)
- \( \|\mathbf{x} + \mathbf{y}\| \leq \|\mathbf{x}\| + \|\mathbf{y}\| \) (Triangle Inequality)
In our exercise, we calculated norms for combinations of vectors, such as \( \|\mathbf{u}+\mathbf{v}+\mathbf{w}\| \) using the formula \( \|\mathbf{x}+\mathbf{y}\|^2 = \langle\mathbf{x}+\mathbf{y}, \mathbf{x}+\mathbf{y}\rangle \). Norms provide a great way to understand distances in vector spaces.
Inner Products
Inner products are essential in connecting geometry with algebra. They allow us to determine angles, lengths, and orthogonality in vector spaces. The inner product of two vectors \( \mathbf{x} \) and \( \mathbf{y} \), denoted as \( \langle \mathbf{x}, \mathbf{y} \rangle \), follows these properties:
In the exercise, we distributed inner products to find values like \( \langle \mathbf{u}+2\mathbf{w}, 3\mathbf{u}-3\mathbf{v}+\mathbf{w} \rangle \). Inner products are vital in defining projections and orthogonal vectors.
- Conjugate symmetry: \( \langle \mathbf{x}, \mathbf{y} \rangle = \overline{\langle \mathbf{y}, \mathbf{x} \rangle} \)
- Linearity in the first argument: \( \langle a\mathbf{x}+b\mathbf{y}, \mathbf{z} \rangle = a\langle \mathbf{x}, \mathbf{z} \rangle + b\langle \mathbf{y}, \mathbf{z} \rangle \)
- Positive-definiteness: \( \langle \mathbf{x}, \mathbf{x} \rangle \geq 0 \) with equality if and only if \( \mathbf{x} = \mathbf{0} \)
In the exercise, we distributed inner products to find values like \( \langle \mathbf{u}+2\mathbf{w}, 3\mathbf{u}-3\mathbf{v}+\mathbf{w} \rangle \). Inner products are vital in defining projections and orthogonal vectors.
Vector Calculations
Performing calculations with vectors involves operations like addition, subtraction, and scalar multiplication. These operations form the foundation of many calculations in linear algebra.
The exercise required us to calculate:
These calculations demonstrate the versatility and application of vectors in solving problems, allowing for transformation and rotation operations essential in fields like computer graphics and physics.
The exercise required us to calculate:
- Combined vectors such as \( \mathbf{u}+\mathbf{v}+\mathbf{w} \)
- Scaled and combined vectors like \( 2\mathbf{u}-3\mathbf{v}-\mathbf{w} \)
- Products such as \( \langle \mathbf{u}+2\mathbf{w}, 3\mathbf{u}-3\mathbf{v}+\mathbf{w} \rangle \)
These calculations demonstrate the versatility and application of vectors in solving problems, allowing for transformation and rotation operations essential in fields like computer graphics and physics.
Other exercises in this chapter
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