Problem 34
Question
In Exercises 9-50, verify the identity \( \dfrac{\cos [(\pi/2) - x]}{\sin [(\pi/2) - x]} = \tan x \)
Step-by-Step Solution
Verified Answer
The given identity \( \dfrac{\cos [(\pi/2) - x]}{\sin [(\pi/2) - x]} = \tan x \) is verified by using the co-function identities to simplify the left-hand side of the equation to \( \tan x \), which matches the right-hand side.
1Step 1: Trigonometric Co-Function Identities
Use the co-function identities to rewrite the left side expression. These identities state that \( \cos (\pi/2 - x) = \sin x \) and \( \sin (\pi/2 - x) = \cos x \). The left side of the equation can then be rewritten as \( \dfrac{\sin x}{\cos x} \)
2Step 2: Simplification
Simplify \( \dfrac{\sin x}{\cos x} \) using the definition of the tangent function. Recall that the tangent of an angle in trigonometry is defined as \( \tan x = \dfrac{\sin x}{\cos x} \). Therefore our expression simplifies to \( \tan x \)
3Step 3: Verification of the Identity
The right side of the initial equation was \( \tan x \). After the conversion and simplification steps applied to the left side of the equation, the left side is now also \( \tan x \). Hence, the trigonometric identity is verified.
Key Concepts
Co-Function IdentitiesTangent FunctionVerifying Trigonometric Identities
Co-Function Identities
Co-function identities in trigonometry are a powerful tool that helps relate different trigonometric functions to one another. These identities are especially useful when dealing with angles that sum up to 90 degrees or \(\pi/2\) radians. Here are the basic co-function relationships:
- \( \cos (\frac{\pi}{2} - x) = \sin x \)
- \( \sin (\frac{\pi}{2} - x) = \cos x \)
- \( \tan (\frac{\pi}{2} - x) = \cot x \)
- \( \cot (\frac{\pi}{2} - x) = \tan x \)
Tangent Function
The tangent function is one of the fundamental trigonometric functions, generally denoted as \(\tan x\). It helps in understanding the relationship between the sine and cosine functions. The basic definition of the tangent function is:\[\tan x = \frac{\sin x}{\cos x}\]This definition implies the tangent can be interpreted as the ratio of the opposite side to the adjacent side in a right-angled triangle.
Therefore, in the context of our exercise, simplifying the expression \(\frac{\sin x}{\cos x}\) directly showcases it as \(\tan x\), aligning with the right side of the identity. Understanding the tangent function through this formula is crucial, as it lays the foundation for further identity verification and enhances one's problem-solving skillset in trigonometry.
Therefore, in the context of our exercise, simplifying the expression \(\frac{\sin x}{\cos x}\) directly showcases it as \(\tan x\), aligning with the right side of the identity. Understanding the tangent function through this formula is crucial, as it lays the foundation for further identity verification and enhances one's problem-solving skillset in trigonometry.
Verifying Trigonometric Identities
Verifying trigonometric identities involves transforming one side of an equation to match the other using known identities and simplifications. In our exercise, the task is to show that both sides of the given identity \( \frac{\cos [(\pi/2) - x]}{\sin [(\pi/2) - x]} = \tan x \) evaluate to the same expression.The verification process generally follows these steps:
It reinforces confidence in applying identities to solve diverse mathematical problems.
- Use known trigonometric identities, like co-function or reciprocal identities.
- Simplify one or both sides until they appear identical.
- In our case, using co-function identities reduced the left side to \( \tan x \), exactly matching the right side.
It reinforces confidence in applying identities to solve diverse mathematical problems.
Other exercises in this chapter
Problem 34
In Exercises 29 - 36, write the expression as the sine, cosine,or tangent of an angle. \( \dfrac{\tan 140^\circ - \tan 60^\circ}{1 + \tan 140^\circ \tan 60^\cir
View solution Problem 34
In Exercises 25-38, find all solutions of the equation in the interval \( [0, 2\pi) \). \( 2 \sin^2 x + 3 \sin x + 1 = 0 \)
View solution Problem 35
In Exercises 29-36, use a double-angle formula to rewrite the expression. \( (\cos x + \sin x)(\cos x - \sin x) \)
View solution Problem 35
In Exercises 25-38, find all solutions of the equation in the interval \( [0, 2\pi) \). \( 2 \sec^2 x + \tan^2 x - 3 = 0 \)
View solution