Problem 34
Question
In Exercises 34 - 39 , use the appropriate change of base formula to approximate the logarithm. $$ \log _{3}(12) $$
Step-by-Step Solution
Verified Answer
\( \log_{3}(12) \approx 2.26186 \) using base 10 logarithms.
1Step 1: Understand the Problem
We need to find an approximate value for the logarithm \( \log_{3}(12) \). Since this isn't a simple integer, we will use the change of base formula to compute it.
2Step 2: Apply Change of Base Formula
The change of base formula states that \( \log_{b}(a) = \frac{\log_{c}(a)}{\log_{c}(b)} \), where \( c \) is a new base you choose. Commonly, \( c = 10 \) (common log) or \( c = e \) (natural log). We'll use base 10 for this problem.
3Step 3: Write the Expression Using Base 10
Using the change of base formula with base 10, we have:\[\log_{3}(12) = \frac{\log_{10}(12)}{\log_{10}(3)}\]
4Step 4: Calculate Logarithms Separately
Find the values of \( \log_{10}(12) \) and \( \log_{10}(3) \) using a calculator or log table:- \( \log_{10}(12) \approx 1.07918 \) - \( \log_{10}(3) \approx 0.47712 \)
5Step 5: Divide the Results
Now, divide the values obtained: \[\frac{1.07918}{0.47712} \approx 2.26186\]
6Step 6: State the Final Approximation
Thus, \( \log_{3}(12) \approx 2.26186 \) to five decimal places.
Key Concepts
Understanding LogarithmsThe Process of Base ConversionLogarithmic Calculations in Practice
Understanding Logarithms
Logarithms are essentially the inverse operations of exponentiation. If you're familiar with powers and exponents, understanding logarithms will feel like working backwards. They're used to determine what power you need to raise a base to in order to obtain a specific number. For instance, if we say \( \, b^x = a \, \), then \( \, ext{log}_b(a) = x \, \). Here's a breakdown:
- The base \( b \) is the number you multiply by itself.
- The exponent \( x \) is the number of times you multiply the base.
- \( a \) is the result after raising the base to the exponent.
The Process of Base Conversion
Base conversion in logarithms refers to changing the base of a logarithm to another base that might be easier to work with. This is helpful because calculating logarithms with bases other than 10 or \( e \) directly is often impractical. The change of base formula allows you to convert a logarithm to a new base of your choice.
- The formula for base conversion is \( \log_b(a) = \frac{\log_c(a)}{\log_c(b)} \), where \( c \) is your chosen new base, usually 10 or \( e \) for convenience.
- This formula works because logarithms are ratios of the exponents needed to reach a certain number from a given base. Thus, changing the base doesn't change the ratio of these exponents.
Logarithmic Calculations in Practice
Now let's apply our understanding to the practical calculation of logarithms using the change of base formula. When you use a base-10 calculator or tools, the process becomes straightforward. Here's a step-by-step method:
- First, calculate \( \log_{10}(12) \) which approximates to 1.07918. This is finding how many times 10 has to be raised to reach 12.
- Next, calculate \( \log_{10}(3) \) which approximates to 0.47712. It tells us how many times 10 must be raised to equal 3.
- Finally, divide these two results: \( \frac{1.07918}{0.47712} \). This gives you approximately 2.26186, which means 3 raised to 2.26186 equals about 12.
Other exercises in this chapter
Problem 34
In Exercises \(34-39,\) solve the inequality analytically. $$ e^{x}>53 $$
View solution Problem 34
Use your calculator to help you solve the equation or inequality. $$ \ln \left(-2 x^{3}-x^{2}+13 x-6\right)
View solution Problem 34
Evaluate the expression. \(\log _{36}\left(36^{216}\right)\)
View solution Problem 35
In Exercises \(34-39,\) solve the inequality analytically. $$ 1000(1.005)^{12 t} \geq 3000 $$
View solution