Problem 34
Question
In \(33-44,\) if \(\ln 2=x\) and \(\ln 3=y,\) write each of the natural logs in terms of \(x\) and \(y\) $$ \ln 9 $$
Step-by-Step Solution
Verified Answer
\( \ln 9 = 2y \), where \( y = \ln 3 \).
1Step 1: Understanding the Problem
We need to express the natural logarithm \( \ln 9 \) using the given \( \ln 2 = x \) and \( \ln 3 = y \).
2Step 2: Breaking Down \( \ln 9 \)
Recognize that \( 9 = 3^2 \). Therefore, we can rewrite \( \ln 9 \) as \( \ln (3^2) \).
3Step 3: Using the Logarithm Power Rule
Apply the power rule of logarithms: \( \ln (a^b) = b \ln a \). Using this, \( \ln (3^2) = 2 \ln 3 \).
4Step 4: Substituting Given Values
Substitute \( \ln 3 = y \) into the equation: \( 2 \ln 3 = 2y \). So, \( \ln 9 = 2y \).
Key Concepts
Logarithm RulesExpressing LogarithmsLogarithm Properties
Logarithm Rules
Understanding logarithms starts by knowing their key rules. These rules help simplify and transform logarithmic expressions. Here are three important ones:
- Product Rule: The logarithm of a product is the sum of the logarithms: \( \log_b (MN) = \log_b M + \log_b N \).
- Quotient Rule: The logarithm of a quotient is the difference of the logarithms: \( \log_b \left( \frac{M}{N} \right) = \log_b M - \log_b N \).
- Power Rule: Useful for powers, the logarithm of a power is the exponent times the logarithm of the base: \( \log_b (M^n) = n \cdot \log_b M \).
Expressing Logarithms
When expressing logarithms, the goal is to write them using known values or simpler components, as seen in the problem. Breaking down complex logarithms into terms of simpler ones is a common technique.
- Identify Simpler Components: Start by recognizing the equivalent form of the number inside the logarithm. For instance, \(9\) is the same as \(3^2\).
- Substitute Known Values: Use given logarithmic values for substitution. In the provided problem, \( \ln 2 = x \) and \( \ln 3 = y \), serving as basis for expressing \( \ln 9 \).
Logarithm Properties
Logarithm properties are the foundational characteristics that define how logarithms behave. These properties make it possible to manipulate and simplify complex logarithmic expressions. Here's a closer look:
- Inverse Property: Logarithms are the inverse operations of exponents. If \( b^x = N \), then \( \log_b N = x \).
- Change of Base Formula: To convert logarithmic bases, use: \( \log_b M = \frac{\log_k M}{\log_k b} \), useful when comparing logs of different bases.
- Special Values: Logarithms of 1 or same base: \( \log_b 1 = 0 \) and \( \log_b b = 1 \), provide trivially simple results.
Other exercises in this chapter
Problem 33
In \(27-56,\) evaluate each logarithmic expression. Show all work. $$ \log _{4} \frac{1}{16} $$
View solution Problem 33
Expand each expression using the properties of logarithms. \(\log _{10}(x+1)^{2}\)
View solution Problem 34
In \(24-35,\) for each given logarithm, find the antilogarithm, \(x .\) Write the answer to four decimal places. $$ \log x=-3 $$
View solution Problem 34
In \(27-56,\) evaluate each logarithmic expression. Show all work. $$ 3 \log _{4} \frac{1}{16} $$
View solution