Problem 34
Question
Identify whether each equation, when graphed, will be a parabola, circle,ellipse, or hyperbola. Sketch the graph of each equation. If a parabola, label the vertex. If a circle, label the center and note the radius. If an ellipse, label the center. If a hyperbola, label the \(x\) - or \(y\) -intercepts. $$ \frac{x^{2}}{16}-\frac{y^{2}}{4}=1 $$
Step-by-Step Solution
Verified Answer
The equation represents a horizontally opening hyperbola centered at (0,0), with x-intercepts at (-4,0) and (4,0).
1Step 1: Identify the Type of Conic Section
The given equation is \( \frac{x^2}{16} - \frac{y^2}{4} = 1 \). This can be compared to the standard form of a hyperbola, which is \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \), where \( a^2 = 16 \) and \( b^2 = 4 \). Since the equation matches this form, it represents a hyperbola that opens horizontally along the \(x\)-axis.
2Step 2: Determine Key Features of the Hyperbola
Identify \( a \), \( b \), and the center of the hyperbola. Here, \( a^2 = 16 \) thus \( a = 4 \), and \( b^2 = 4 \) thus \( b = 2 \). The hyperbola's center is at \((h, k) = (0, 0)\) given that there are no \(h\) or \(k\) terms and it's aligned to the origin.
3Step 3: Sketch the Hyperbola
Draw a set of axes and mark the center at \((0,0)\). Plot the vertices at \((\pm 4, 0)\), since \(a = 4\). Draw the asymptotes, which have slopes of \( \pm \frac{b}{a} = \pm \frac{2}{4} = \pm \frac{1}{2} \), passing through the center. The transverse axis is on the \(x\)-axis from \(-4\) to \(4\), and sketch the hyperbola opening left and right.
4Step 4: Label Key Features
For a hyperbola, the \(x\)-intercepts are the vertices which we found at \((-4, 0)\) and \((4, 0)\). There are no \(y\)-intercepts since the branches do not meet the \(y\)-axis.
Key Concepts
Hyperbola EquationsGraphing Conic SectionsIdentifying Conic Sections
Hyperbola Equations
A hyperbola is one of four types of conic sections, defined by a particular equation form. A hyperbola's equation involves two squared terms, one subtracted from the other. In this form:
- The equation is generally written as \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \), or its counterpart with axes swapped.
- Here, \(a^2\) and \(b^2\) are positive constants, which help define the hyperbola's shape and orientation.
- The equation means the curve will open horizontally if \(x^2\) comes first and vertically if \(y^2\) comes first.
Graphing Conic Sections
Graphing conic sections can initially seem challenging, but knowing your conic type simplifies it incredibly. A hyperbola, given by its unique equation type, tells us how to draw its path around a center, which is typically at the origin unless translated. To plot a hyperbola:
- Identify the center: This is where the axes meet. For our hyperbola, it's at \((0,0)\).
- Locate the vertices: These are directly influenced by \(a\). Here, vertices lie on the x-axis at \((-4,0)\) and \((4,0)\) because \(a = 4\).
- Draw the asymptotes: Asymptotes aid in sketching a more accurate hyperbola. The asymptotes here are slanted lines with slopes \(\pm \frac{1}{2}\), cutting through the center.
- Sketch the hyperbola opening to each side of the center, guided by asymptotes.
Identifying Conic Sections
To correctly identify conic sections, examine the equation provided. The equations reveal much about the underlying conic section type. Look for certain characteristics:
- Parabola: Defined by one squared term, e.g., \(y = ax^2 + bx + c\), opening in a single direction.
- Circle: Appears when both terms are squared and equally weighted, e.g., \(x^2 + y^2 = r^2\).
- Ellipse: Similar to a circle but with differing coefficients, e.g., \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\), different from a circle by stretch differences along axes.
- Hyperbola: Defined when the squared terms are set apart by subtraction, like \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\).
Other exercises in this chapter
Problem 33
Graph each system. $$ \left\\{\begin{array}{l} x+y \geq 1 \\ 2 x+3 y-3 \end{array}\right. $$
View solution Problem 33
Graph each inequality in two variables. $$ x>-3 $$
View solution Problem 34
Hint: For Exercises 33 through 38 , first divide the equation through by the coefficient of \(x^{2}\) (or \(\left.y^{2}\right)\). $$ 2 x^{2}+2 y^{2}=18 $$
View solution Problem 34
Graph each system. $$ \left\\{\begin{array}{l} x-y0 \\ y>0 \end{array}\right. $$
View solution