Problem 34
Question
How does the graph of \(y=4 x^{2}\) compare to the graph of \(y=2 x^{2}\) ? Explain your answer.
Step-by-Step Solution
Verified Answer
The graph of \(y=4x^2\) is narrower than \(y=2x^2\) because 4 > 2, leading to a steeper curve.
1Step 1: Understanding the Parabola Equation
Both given equations are in the form of a parabola, specifically vertically oriented parabolas because they are quadratic in terms of 'x'. The general form for such parabolas is \( y = ax^2 \), where \( a \) is a constant determining the parabola's width and direction.
2Step 2: Analyze the Coefficient's Role
The coefficient \( a \) in \( y = ax^2 \) affects the parabola's width and "stretch." If \( |a| > 1 \), the parabola is narrower compared to \( y = x^2 \), and if \( |a| < 1 \), it is wider.
3Step 3: Compare the Coefficients
For \( y = 4x^2 \), the coefficient \( a \) is 4, and for \( y = 2x^2 \), \( a \) is 2. Since 4 > 2, the graph of \( y = 4x^2 \) is narrower than \( y = 2x^2 \).
4Step 4: Conclusion on Graph Comparison
Given that both parabolas open upwards (since both coefficients are positive), \( y = 4x^2 \) will appear narrower (steeper) than \( y = 2x^2 \), because the larger coefficient results in a steeper ascent.
Key Concepts
Understanding Quadratic FunctionsExploring the Coefficient EffectInvestigating Graph Transformations
Understanding Quadratic Functions
Quadratic functions are an essential concept in mathematics, mostly represented by the equation \(y = ax^2 + bx + c\). In the context of parabolas, where the interest is in vertical changes, this simplifies to \(y = ax^2\). Here, 'a' is the key player. It determines how the parabola will look like in terms of width and direction. Parabolas are symmetrical graphs shaped like a "U" or an inverted "U" depending on the sign of 'a'. If \(a > 0\), the parabola opens upward, resembling a bowl, while if \(a < 0\), it opens downward.
- The vertex of the parabola is the central point where it either peaks or troughs.
- The y-intercept is where the parabola crosses the y-axis, and in \(y = ax^2\), this is always the origin when \(b\) and \(c\) are zero.
Exploring the Coefficient Effect
The coefficient 'a' in a quadratic function, \(y = ax^2\), plays a critical role in defining the parabola's appearance. Specifically, it influences the parabola's width and steepness. Here's how it works:
- If \(|a| > 1\), the graph of the parabola becomes narrower than that of \(y = x^2\), indicating it is "stretched" vertically.
- If \(|a| < 1\), the parabola widens, as it appears more "flattened."
- When \(a = 0\), the quadratic function doesn't form a parabola either, since it lacks the squared term.
Investigating Graph Transformations
Graph transformations describe how we can modify a graph's appearance by changing parameters within its equation. With quadratic functions, the coefficient 'a' is central to these transformations. Depending on its value, we see the parabolas "shift" in shape:
- "Stretching" occurs when \(|a|\) increases, causing the parabola to become steeper and narrower.
- "Compressing" happens if \(|a|\) decreases, resulting in a wider, more flattened graph.
Other exercises in this chapter
Problem 34
Are the graphs of \(x^{2}-y^{2}=0\) and \(y^{2}-x^{2}=0\) identical? Are the graphs of \(x^{2}-y^{2}=4\) and \(y^{2}-x^{2}=4\) identical? Explain your answers.
View solution Problem 34
\(9 x^{2}+9 y^{2}-6 x-12 y-40=0\)
View solution Problem 36
(a) Graph \(y=x^{2}, y=2 x^{2}, y=3 x^{2}\), and \(y=4 x^{2}\) on the same set of axes. (b) Graph \(y=x^{2}, y=\frac{3}{4} x^{2}, y=\frac{1}{2} x^{2}\), and \(y
View solution Problem 37
(a) Graph \(y=x^{2}, y=(x-2)^{2}, y=(x-3)^{2}\), and \(y=\) \((x-5)^{2}\) on the same set of axes. (b) Graph \(y=x^{2}, y=(x+1)^{2}, y=(x+3)^{2}\), and \(y=\) \
View solution