Problem 34
Question
Graph the solution set to the system of inequalities. $$ \begin{aligned} &2 x+3 y \leq 6\\\ &\frac{1}{2} x^{2}-y \leq 2 \end{aligned} $$
Step-by-Step Solution
Verified Answer
The graph's solution set is where the shaded regions of both constraints overlap.
1Step 1: Identify Inequalities
First, we will identify the system of inequalities that we need to graph. These are: 1. \(2x + 3y \leq 6\)2. \(\frac{1}{2}x^2 - y \leq 2\).
2Step 2: Convert Inequalities to Equations for Graphing
Convert each inequality to an equation to find the boundary lines or curves:1. \(2x + 3y = 6\)2. \(\frac{1}{2}x^2 - y = 2\).
3Step 3: Graph the First Inequality
Plot the line \(2x + 3y = 6\). To do this, find the intercepts:- When \(x=0\), \(3y = 6\) gives \(y = 2\).- When \(y=0\), \(2x = 6\) gives \(x = 3\). Connect these points to draw the line, and shade the region below this line as it represents \(2x + 3y \leq 6\).
4Step 4: Graph the Second Inequality
Plot the curve \(\frac{1}{2}x^2 - y = 2\) by rewriting it as \(y = \frac{1}{2}x^2 - 2\). This is a parabola with vertex at \((0, -2)\) opening upwards. Shade the area below the parabola as it represents \(\frac{1}{2}x^2 - y \leq 2\).
5Step 5: Find the Intersection of Shaded Regions
Determine the region where the shading of both inequalities overlaps. This common shaded area is the solution set for the system of inequalities.
Key Concepts
Graphing InequalitiesLinear EquationsParabolic Equations
Graphing Inequalities
Graphing inequalities involves plotting a line or curve and shading a specific region of the graph. The shaded area represents all the possible solutions for that inequality. When graphing the inequality \( 2x + 3y \leq 6 \), we first convert it to an equation \( 2x + 3y = 6 \) to find the line plot points. Next, we plot the intercepts to draw the line:
- For the y-intercept, let \( x = 0 \). Then, \( 3y = 6 \) gives \( y = 2 \).
- For the x-intercept, let \( y = 0 \). Then, \( 2x = 6 \) gives \( x = 3 \).
Linear Equations
Linear equations form the backbone of many algebraic problems. A linear equation in two variables has the form \( ax + by = c \) and always produces a straight line when graphed. In this exercise, the equation \( 2x + 3y = 6 \) represents a line in a two-dimensional coordinate system.To graph a linear equation:
- Identify the x- and y-intercepts by setting each variable to zero in turn.
- Use these intercepts to plot two points on the graph.
- Connect the points to create the line.
Parabolic Equations
Parabolic equations graph as curved lines, known as parabolas. Typically, they take the form \( y = ax^2 + bx + c \). The equation \( y = \frac{1}{2}x^2 - 2 \) is a parabola opening upwards due to the positive coefficient \( \frac{1}{2} \) in front of \( x^2 \).Key characteristics to graph a parabola:
- Vertex: The turning point of the parabola. For our equation, the vertex is at \( (0, -2) \).
- Direction: Determined by the coefficient of \( x^2 \). Positive values open upwards, negatives downwards.
- Axis of Symmetry: A vertical line through the vertex, \( x = 0 \) here.
Other exercises in this chapter
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