Problem 34
Question
Graph each inequality in two variables. $$ y \leq 1 $$
Step-by-Step Solution
Verified Answer
Graph a solid horizontal line at \( y = 1 \) and shade below.
1Step 1: Understand the Inequality
The inequality given is \( y \leq 1 \). This means that the value of \( y \) is less than or equal to 1 for any value of \( x \). The solution set includes all points on the plane where \( y \) is 1 or less.
2Step 2: Graph the Boundary Line
First, we need to graph the boundary line. For \( y \leq 1 \), the boundary line is \( y = 1 \). This is a horizontal line because the value of \( y \) does not depend on \( x \). Draw a solid horizontal line across the y-axis at \( y = 1 \) to indicate that points on this line are included in the solution set.
3Step 3: Shade the Solution Region
Since \( y \leq 1 \), we need to shade the region below the line \( y = 1 \). This includes all points where \( y \) is less than (but not greater than) 1. This shaded region represents all solutions to the inequality.
Key Concepts
Boundary LineSolution RegionInequality Symbols
Boundary Line
When graphing an inequality in two variables, the first step is to identify the boundary line. The boundary line helps you know exactly where the inequality switches from true to false. Think of it like a border that divides the areas where the inequality holds from those where it does not.
In the example of the inequality \( y \leq 1 \), the boundary line is \( y = 1 \). This is a straightforward horizontal line because its value does not change regardless of what \( x \) is. In other words, no matter how far left or right the line goes, \( y \) stays at 1.
By drawing this line as solid rather than dashed, we show that \( y = 1 \) itself is part of the solution. Solid lines are used for \( \leq \) and \( \geq \) symbols, indicating that points directly on the line satisfy the inequality.
In the example of the inequality \( y \leq 1 \), the boundary line is \( y = 1 \). This is a straightforward horizontal line because its value does not change regardless of what \( x \) is. In other words, no matter how far left or right the line goes, \( y \) stays at 1.
By drawing this line as solid rather than dashed, we show that \( y = 1 \) itself is part of the solution. Solid lines are used for \( \leq \) and \( \geq \) symbols, indicating that points directly on the line satisfy the inequality.
Solution Region
Once the boundary line is drawn, the next step is to identify the solution region. This is the part of the graph where the inequality holds true. It's like a map showing all the areas where the inequality "lives."
For the inequality \( y \leq 1 \), the solution region includes all the points where \( y \) values are 1 or less. Since the boundary line \( y = 1 \) is solid, it is included in this region. To graph this, shade the area below the line on your graph.
Remember:
For the inequality \( y \leq 1 \), the solution region includes all the points where \( y \) values are 1 or less. Since the boundary line \( y = 1 \) is solid, it is included in this region. To graph this, shade the area below the line on your graph.
Remember:
- If the inequality symbol is \(<\) or \(>\), shade above or below the boundary line respectively.
- If the inequality symbol includes equal to, as in \( \leq \) or \( \geq \), include the line itself by making it solid.
Inequality Symbols
Understanding the symbols in inequalities is crucial for properly graphing them. They tell us not only how the boundary line should appear but also which part of the graph to shade.
Here's a quick guide to inequality symbols:
When graphing:
Here's a quick guide to inequality symbols:
- \( < \): Less than.
- \( \leq \): Less than or equal to.
- \( > \): Greater than.
- \( \geq \): Greater than or equal to.
When graphing:
- Use a solid line for "\( \leq \)" or "\( \geq \)" to show the line is included in the solution.
- Use a dashed line for "\(<\)" or "\(>\)" when the line itself is not part of the solution.
Other exercises in this chapter
Problem 34
Hint: For Exercises 33 through 38 , first divide the equation through by the coefficient of \(x^{2}\) (or \(\left.y^{2}\right)\). $$ 2 x^{2}+2 y^{2}=18 $$
View solution Problem 34
Graph each system. $$ \left\\{\begin{array}{l} x-y0 \\ y>0 \end{array}\right. $$
View solution Problem 35
Identify whether each equation, when graphed, will be a parabola, circle,ellipse, or hyperbola. Sketch the graph of each equation. If a parabola, label the vert
View solution Problem 35
Hint: For Exercises 33 through 38 , first divide the equation through by the coefficient of \(x^{2}\) (or \(\left.y^{2}\right)\). $$ 6(x-4)^{2}+6(y-1)^{2}=24 $$
View solution