Problem 34
Question
For the following exercises, simplify each expression. $$ 3 \sqrt[3]{-432}+\sqrt[1]{16} $$
Step-by-Step Solution
Verified Answer
The simplified expression is -2.
1Step 1: Simplify the Cube Root
The first step involves solving \( \sqrt[3]{-432} \). The cube root of a negative number is negative. \( \sqrt[3]{-432} \) is \( -\sqrt[3]{432} \). Breaking 432 down gives us \( 432 = 2^4 \times 3^3 \). So, \( \sqrt[3]{432} = \sqrt[3]{2^4 \times 3^3} = 2 \times 3 = 6 \). Thus, \( \sqrt[3]{-432} = -6 \).
2Step 2: Solve the Cube Root Expression
Now substitute the cube root value into the original expression: \( 3 \times -6 = -18 \). This simplifies the cube root component to \( -18 \).
3Step 3: Simplify the Square Root
Now address the square root \( \sqrt[1]{16} \). However, \( \sqrt[1]{16} \) is just \( 16 \) because any number to the power of one is itself.
4Step 4: Combine the Results
Finally, combine the simplified results from both parts: \( -18 + 16 \). Simplifying gives us: \( -18 + 16 = -2 \).
Key Concepts
Cube RootSquare RootNegative NumbersExponent Properties
Cube Root
A cube root is a value that, when multiplied by itself three times, produces the original number. For example, the cube root of 27 is 3 because when you multiply 3 × 3 × 3, you get 27.
Now, if you have a negative number under the cube root, such as \(-432\), the result will be negative. This is because a negative number times itself twice more still results in a negative product.
For example:
Now, if you have a negative number under the cube root, such as \(-432\), the result will be negative. This is because a negative number times itself twice more still results in a negative product.
For example:
- The cube root of \(-8\) is \(-2\), because \(-2 imes -2 imes -2 = -8\).
- In our exercise, \(-432\) can be factored into \(2^4 imes 3^3\). So the cube root of \(-432\) simplifies as \(-6\).
Square Root
The square root gives you a number that, when multiplied by itself, equals the original number. For example, the square root of 16 is 4 because 4 × 4 = 16.
In our problem, the expression \(\sqrt[1]{16}\) is simplified as just 16. The notation \(\sqrt[1]{x}\) simply represents the number itself. It's because any number to the first power remains unchanged.
Here’s a quick breakdown:
In our problem, the expression \(\sqrt[1]{16}\) is simplified as just 16. The notation \(\sqrt[1]{x}\) simply represents the number itself. It's because any number to the first power remains unchanged.
Here’s a quick breakdown:
- \(\sqrt[1]{25}\) equals 25 because it’s 25 raised to the power of 1.
- In the exercise: \(\sqrt[1]{16}\) = 16.
Negative Numbers
Negative numbers provide a method for representing quantities less than zero. They can be handled in operations like addition, subtraction, and multiplication.
When you multiply a positive number by a negative number, your result is negative. For instance:
\(-18 + 16\) results in \(-2\).
Thus, careful attention to sign will allow correct simplification of expressions.
When you multiply a positive number by a negative number, your result is negative. For instance:
- 3 × \(-4\) equals \(-12\).
- In the problem, \(3 \sqrt[3]{-432}\) leads to 3 × \(-6\) which results in \(-18\).
\(-18 + 16\) results in \(-2\).
Thus, careful attention to sign will allow correct simplification of expressions.
Exponent Properties
Understanding exponent properties is crucial for simplifying complex expressions. Different properties explain how numbers behave under exponents.
Understanding these rules can simplify and solve expressions accurately.
- **Product of Powers**: \((a^m imes a^n = a^{m+n})\)
- **Power of a Power**: \((a^{m})^n = a^{m imes n}\)
- **Power of a Product**: \((ab)^m = a^m imes b^m\)
Understanding these rules can simplify and solve expressions accurately.
Other exercises in this chapter
Problem 34
For the following exercises, factor the polynomial. $$ m^{2}-20 m+100 $$
View solution Problem 34
For the following exercises, divide the rational expressions. $$ \frac{12}{2 q}-\frac{6}{3 p} $$
View solution Problem 34
For the following exercises, multiply the binomials. $$(25 b+2)(25 b-2)$$
View solution Problem 34
Add and subtract the rational expressions, and then simplify. $$ \frac{12}{2 q}-\frac{6}{3 p} $$
View solution