Problem 34
Question
For the following exercises, let \(f(x)=\sin x\) On \([0,2 \pi), f(x)=\frac{\sqrt{2}}{2} .\) Find all values of \(x\)
Step-by-Step Solution
Verified Answer
The values of \(x\) are \(\frac{\pi}{4}\) and \(\frac{3\pi}{4}\).
1Step 1: Understand the problem
We need to find all the values of \(x\) in the interval \([0, 2\pi)\) where \(f(x) = \sin x = \frac{\sqrt{2}}{2}\).
2Step 2: Recall the sine function values
Recall the unit circle values where \(\sin x = \frac{\sqrt{2}}{2}\). These values are at angles \(x = \frac{\pi}{4}\) and \(x = \frac{3\pi}{4}\) in one full rotation \([0, 2\pi)\).
3Step 3: Identify values in given interval
Given that the domain is \([0, 2\pi)\), check whether both \(x = \frac{\pi}{4}\) and \(x = \frac{3\pi}{4}\) fall within this interval. In this case, both values are within \([0, 2\pi)\).
4Step 4: Verify the solution
Double-check by plugging the values \(x = \frac{\pi}{4}\) and \(x = \frac{3\pi}{4}\) back into \(f(x) = \sin x\) to ensure they both result in \(\frac{\sqrt{2}}{2}\). Indeed, \(\sin \left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2}\) and \(\sin \left(\frac{3\pi}{4}\right) = \frac{\sqrt{2}}{2}\).
5Step 5: Conclusion
Therefore, the solutions for \(x\) are \[ \frac{\pi}{4}, \frac{3\pi}{4} \].
Key Concepts
Sine FunctionUnit CircleAngles in Radians
Sine Function
The sine function is one of the fundamental trigonometric functions used in mathematics. It arises frequently in geometry, physics, engineering, and other fields requiring the study of waves and periodic phenomena. The function is defined for any angle in radians and is written as \(\sin x\). The sine function measures the vertical component of a point on the unit circle. It outputs the y-coordinate of that point, which lies on a circle with a radius of 1.
Some key characteristics of the sine function include:
Some key characteristics of the sine function include:
- Periodic behavior with a cycle of \(2\pi\). This means the sine function repeats its values every \(2\pi\) radians.
- An amplitude of 1, indicating its maximum and minimum outputs are 1 and -1, respectively.
- The sine function is an odd function, showing symmetry about the origin: \(\sin(-x) = -\sin x\).
Unit Circle
The unit circle is a circle with a radius of 1, centered at the origin of a coordinate plane. It's a valuable tool in trigonometry because it allows us to easily determine the sine and cosine values for various angles. Every point on the unit circle can be represented as \((\cos \theta, \sin \theta)\), where \(\theta\) is the angle measured from the positive x-axis.
Here are important points about the unit circle:
Here are important points about the unit circle:
- It provides a geometric representation of trigonometric functions. The x-coordinate of a point is the cosine of the angle, and the y-coordinate is the sine of the angle.
- Significant angles and their sine and cosine values are often memorized using the unit circle, such as \(\frac{\pi}{4}\), \(\frac{\pi}{2}\), and \(\pi\).
- The unit circle makes it easier to visualize and solve trigonometric equations, like finding where \(\sin x = \frac{\sqrt{2}}{2}\), by identifying points on the circle corresponding to these values.
Angles in Radians
Angles in trigonometry are often measured in radians, a unit and method of measuring angles based on the radius of a circle. One full circle rotation is equal to \(2\pi\) radians, which equates to 360 degrees. Converting between radians and degrees can be helpful in many mathematical applications.
Here are some important points about radians:
Here are some important points about radians:
- In the radian system, the angle is calculated by taking the arc length divided by the radius of the circle.
- Common angles in radians include: \(\pi/6\), \(\pi/4\), \(\pi/3\), and \(\pi/2\), corresponding to 30°, 45°, 60°, and 90°, respectively.
- Radians allow the trigonometric functions to be periodic with a simpler period of \(2\pi\), easing calculations in calculus and physics.
Other exercises in this chapter
Problem 32
For the following exercises, let \(f(x)=\sin x\) On \([0,2 \pi),\) solve \(f(x)=\frac{1}{2}\)
View solution Problem 33
For the following exercises, let \(f(x)=\sin x\) Evaluate \(f\left(\frac{\pi}{2}\right)\)
View solution Problem 35
For the following exercises, let \(f(x)=\sin x\) On \([0,2 \pi),\) the maximum value(s) of the function occur(s) at what \(x\) -value(s)?
View solution Problem 36
For the following exercises, let \(f(x)=\sin x\) On \([0,2 \pi),\) the minimum value(s) of the function occur(s) at what \(x\) -value(s)?
View solution