Problem 34
Question
Find the indicated term of the sequence. $$\begin{aligned} &a_{n}=\frac{n^{2}}{2 n+1}\\\ &a_{5}= \end{aligned}$$
Step-by-Step Solution
Verified Answer
\(\frac{25}{11}\)
1Step 1: Identify the general formula of the Sequence
The general formula for the given sequence is \(a_n = \frac{n^2}{2n+1}\). This formula gives the \(n^{th}\) term of the sequence.
2Step 2: Substitute the Value
To find the \(5^{th}\) term, substitute \(n = 5\) in the general formula. So, \(a_5 = \frac{5^2}{2*5+1}\).
3Step 3: Perform Simplification
Solve the right side of the equation. First calculate the numerator, \(5^2 = 25\), then calculate the denominator, \(2*5+1 = 11\).
4Step 4: Calculate the Fifth Term
Now divide the numerator by the denominator. So, \(a_5 = \frac{25}{11}\).
Key Concepts
General Formula of a SequenceSubstitution in AlgebraSimplification in Fractions
General Formula of a Sequence
Understanding sequences in algebra can feel like unraveling a mystery story. At the heart of every sequence is its general formula. For our sequence, the general formula is given by \(a_n = \frac{n^2}{2n+1}\). This formula allows us to find any term in the sequence, referred to as the \(n^{th}\) term.
In essence, the general formula is a blueprint. It tells us how to construct each term based on its position in the sequence (denoted by \(n\)). With this formula, you aren't just finding numbers, you're discovering how the sequence grows and evolves.
To use the general formula, simply replace \(n\) with the position of the term you want to find. This ability to replace \(n\) is a powerful tool that enables us to move from a broad description of the sequence to specific numerical terms.
In essence, the general formula is a blueprint. It tells us how to construct each term based on its position in the sequence (denoted by \(n\)). With this formula, you aren't just finding numbers, you're discovering how the sequence grows and evolves.
To use the general formula, simply replace \(n\) with the position of the term you want to find. This ability to replace \(n\) is a powerful tool that enables us to move from a broad description of the sequence to specific numerical terms.
Substitution in Algebra
Substitution is like putting a puzzle piece into its perfect spot. In mathematics, especially in algebra, substitution means replacing a variable with a specific value.
Let's look at our sequence example. We want to find the \(5^{th}\) term, so we substitute \(n = 5\) into our general formula \(a_n = \frac{n^2}{2n+1}\). This gives us \(a_5 = \frac{5^2}{2\cdot5+1}\).
Let's look at our sequence example. We want to find the \(5^{th}\) term, so we substitute \(n = 5\) into our general formula \(a_n = \frac{n^2}{2n+1}\). This gives us \(a_5 = \frac{5^2}{2\cdot5+1}\).
- First, identify the term you need.
- Replace \(n\) with your chosen term number (here it is 5).
- Solve the equation step by step to avoid mistakes.
Simplification in Fractions
After substitution, the next journey is through simplification. Simplifying fractions can often feel like clearing up a cluttered room. Your goal is to make everything as neat and tidy as possible.
For our sequence, after substituting \(n = 5\), we have the fraction \(\frac{25}{11}\). This involves two main steps: simplifying the numerator and the denominator.
For our sequence, after substituting \(n = 5\), we have the fraction \(\frac{25}{11}\). This involves two main steps: simplifying the numerator and the denominator.
- Numerator: Calculate \(5^2\), resulting in 25.
- Denominator: Calculate \(2\cdot5+1\), resulting in 11.
Other exercises in this chapter
Problem 33
Finding a Term of a Geometric Sequence Find the indicated term of the geometric sequence (a) using the table feature of a graphing utility and (b) algebraically
View solution Problem 34
Use the Binomial Theorem to expand and simplify the expression. \((2 y-5)^{3}\)
View solution Problem 34
Write the first five terms of the arithmetic sequence. Use the table feature of a graphing utility to verify your results. $$a_{1}=-10, d=9$$
View solution Problem 34
Evaluate \(_{n} P_{r}\) using the formula from this section. $$_{20} P_{2}$$
View solution