Problem 34
Question
Find the following products and express answers in simplest radical form. All variables represent nonnegative real numbers. \((\sqrt{7}-2)(\sqrt{7}-8)\)
Step-by-Step Solution
Verified Answer
The product is \(23 - 10\sqrt{7}\).
1Step 1: Identify the Expression
The expression given is \((\sqrt{7} - 2)(\sqrt{7} - 8)\). We are multiplying two binomials.
2Step 2: Apply the Distributive Property
Use the FOIL method (First, Outer, Inner, Last) to expand the binomials: - First: \(\sqrt{7} \times \sqrt{7} = 7\)- Outer: \(\sqrt{7} \times (-8) = -8\sqrt{7}\)- Inner: \((-2) \times \sqrt{7} = -2\sqrt{7}\)- Last: \((-2) \times (-8) = 16\)
3Step 3: Combine Like Terms
Combine the results from the FOIL method:\(7 - 8\sqrt{7} - 2\sqrt{7} + 16\). Combine the constant terms and then the radical terms:\(7 + 16 = 23\)\(-8\sqrt{7} - 2\sqrt{7} = -10\sqrt{7}\)
4Step 4: Simplify the Expression
The expression simplifies to:\(23 - 10\sqrt{7}\)
Key Concepts
Distributive Property in AlgebraFOIL MethodCombining Like Terms
Distributive Property in Algebra
The distributive property in algebra is a fundamental principle that comes in handy, especially when you're dealing with expressions like \((\sqrt{7} - 2)(\sqrt{7} - 8)\). This property allows us to multiply a single term by two or more terms inside a parenthesis. The distributive property states that \(a(b + c) = ab + ac\).
To tackle this operation, we start by understanding that we're essentially distributing each term in one binomial to every term in the other binomial. This approach simplifies our computation, making it a preferred method for expanding expressions. For instance, in the original problem, we express each multiplication separately:
To tackle this operation, we start by understanding that we're essentially distributing each term in one binomial to every term in the other binomial. This approach simplifies our computation, making it a preferred method for expanding expressions. For instance, in the original problem, we express each multiplication separately:
- The term \(\sqrt{7}\) is multiplied by both \(\sqrt{7}\) and \(-8\), and
- The term \(-2\) is multiplied by \(\sqrt{7}\) and \(-8\).
FOIL Method
The FOIL method is a specific application of the distributive property for multiplying two binomials. The term "FOIL" is an acronym that helps us remember the order of multiplying the terms: First, Outer, Inner, and Last.
Here's how it works in the context of our expression \((\sqrt{7} - 2)(\sqrt{7} - 8)\):
Here's how it works in the context of our expression \((\sqrt{7} - 2)(\sqrt{7} - 8)\):
- First: Multiply the first terms in each binomial: \(\sqrt{7} \times \sqrt{7} = 7\).
- Outer: Multiply the outer terms: \(\sqrt{7} \times -8 = -8\sqrt{7}\).
- Inner: Multiply the inner terms: \(-2 \times \sqrt{7} = -2\sqrt{7}\).
- Last: Multiply the last terms in each binomial: \(-2 \times -8 = 16\).
Combining Like Terms
Once we've expanded our expression using the FOIL method, the next critical step is simplifying it by combining like terms. Like terms refer to the terms in an expression that have the same variable raised to the same power, or in this case, the same radical.
In our example, after applying FOIL to \((\sqrt{7} - 2)(\sqrt{7} - 8)\), we obtain \(7 - 8\sqrt{7} - 2\sqrt{7} + 16\).
Here's how we combine like terms:
In our example, after applying FOIL to \((\sqrt{7} - 2)(\sqrt{7} - 8)\), we obtain \(7 - 8\sqrt{7} - 2\sqrt{7} + 16\).
Here's how we combine like terms:
- Identify the constant terms: These are \(7\) and \(16\). When combined, they yield \(23\).
- Identify the radical terms: These are \(-8\sqrt{7}\) and \(-2\sqrt{7}\). They share the same radicand, \(\sqrt{7}\), which allows us to combine them into \(-10\sqrt{7}\).
Other exercises in this chapter
Problem 34
Write each of the following in radical form. For example, \(3 x^{\frac{2}{3}}=3 \sqrt[3]{x^{2}}\). \(5 x^{\frac{1}{4}}\)
View solution Problem 34
Solve each equation. Don't forget to check each of your potential solutions. \(\sqrt{x^{2}+2 x+1}=x+3\)
View solution Problem 34
Express each of the following in simplest radical form. All variables represent positive real numbers. \(4 \sqrt{90 a^{5}}\)
View solution Problem 34
Change each radical to simplest radical form. \(\frac{1}{3} \sqrt{90}\)
View solution