Problem 34
Question
Find the fifth term in the expansion of \((a b-1)^{20}\).
Step-by-Step Solution
Verified Answer
The fifth term is \(4845 (ab)^{16}\).
1Step 1: Identify Binomial Theorem
To find the fifth term of the binomial expansion of \((ab-1)^{20}\), we use the binomial theorem. The theorem states that for any positive integer \(n\), \((x + y)^{n} = \sum_{k=0}^{n} \binom{n}{k} x^{n-k} y^{k}\). This implies that we need to find the general term first.
2Step 2: Write the General Term
The general term \(T_{k+1}\) in the expansion \((ab-1)^{20}\) is given by \(T_{k+1} = \binom{20}{k} (ab)^{20-k} (-1)^{k}\). The negative sign comes from replacing \(y\) with \(-1\).
3Step 3: Determine the Specific Term Index
We need the fifth term, so we set \(k+1 = 5\), thus \(k = 4\).
4Step 4: Calculate Binomial Coefficient
Calculate the binomial coefficient: \(\binom{20}{4} = \frac{20 \times 19 \times 18 \times 17}{4 \times 3 \times 2 \times 1} = 4845\).
5Step 5: Substitute Values into the General Term
Substitute \(k = 4\) into the general term: \(T_5 = \binom{20}{4} (ab)^{16} (-1)^{4} = 4845 (ab)^{16} (1)\).
6Step 6: Simplify the Result
Finally, simplify the expression: \(T_5 = 4845 (ab)^{16}\).
Key Concepts
Binomial ExpansionBinomial CoefficientGeneral Term
Binomial Expansion
The binomial expansion is an essential concept in algebra that allows us to expand expressions raised to a power, specifically expressions in the form \((x + y)^{n}\). This powerful tool provides a systematic method for expanding polynomials. The expansion is expressed as the sum of terms involving coefficients, powers of \(x\), and powers of \(y\).
One of the main applications of the binomial expansion is finding specific terms in large power expressions, like \((a b - 1)^{20}\). In this case, instead of manually multiplying the expression 20 times, we use the binomial theorem to find any desired term directly. This saves an immense amount of time and effort.
The general formula involves the binomial coefficients and can be expressed as:
One of the main applications of the binomial expansion is finding specific terms in large power expressions, like \((a b - 1)^{20}\). In this case, instead of manually multiplying the expression 20 times, we use the binomial theorem to find any desired term directly. This saves an immense amount of time and effort.
The general formula involves the binomial coefficients and can be expressed as:
- \[ (x + y)^{n} = \sum_{k=0}^{n} \binom{n}{k} x^{n-k} y^{k} \]
Binomial Coefficient
In polynomial expressions, the binomial coefficient is a crucial element of the binomial expansion accompanied by combinations. It quantifies the number of ways to choose \(k\) elements from \(n\) elements without regard to the order, represented by \(\binom{n}{k}\). This value is obtained using the formula:
- \[ \binom{n}{k} = \frac{n!}{k! (n-k)!} \]
- \[ \binom{20}{4} = \frac{20 \times 19 \times 18 \times 17}{4 \times 3 \times 2 \times 1} = 4845\]
General Term
The general term in a binomial expansion provides an efficient way to determine any specific term without fully expanding the polynomial expression. Defined by the formula:
To find the fifth term, set \(k+1 = 5\), solving for \(k\), which gives \(k = 4\). Plugging this value into the general term formula gives us:
- \[ T_{k+1} = \binom{n}{k} x^{n-k} y^{k} \]
- \[ T_{k+1} = \binom{20}{k} (ab)^{20-k} (-1)^{k} \]
To find the fifth term, set \(k+1 = 5\), solving for \(k\), which gives \(k = 4\). Plugging this value into the general term formula gives us:
- \[ T_5 = \binom{20}{4} (ab)^{16} (-1)^{4} = 4845 (ab)^{16} (1) \]
Other exercises in this chapter
Problem 33
Determine the common difference, the fifth term, the \(n\) th term, and the 100 th term of the arithmetic sequence. $$25,26.5,28,29.5, \dots$$
View solution Problem 33
Find the first six partial sums \(S_{1}, S_{2}, S_{3}, S_{4}, S_{5}, S_{6}\) of the sequence. $$1,3,5,7, \dots$$
View solution Problem 34
Determine the common ratio, the fifth term, and the \(n\) th term of the geometric sequence. $$t, \frac{t^{2}}{2}, \frac{t^{3}}{4}, \frac{t^{4}}{8}, \dots$$
View solution Problem 34
Let \(a_{n}\) be the \(n\) th term of the sequence defined recursively by $$a_{n+1}=\frac{1}{1+a_{n}}$$ and let \(a_{1}=1 .\) Find a formula for \(a_{n}\) in te
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