Problem 34
Question
Find \(f_{x x}, f_{x y}, f_{y x},\) and \(f_{y y}\). $$f(x, y)=3 x+5 y$$
Step-by-Step Solution
Verified Answer
All second partial derivatives \(f_{xx}, f_{xy}, f_{yx},\) and \(f_{yy}\) are 0.
1Step 1: Understanding Partial Derivatives
The function provided is a multivariable function, and we need to calculate the second-order partial derivatives with respect to the variables \(x\) and \(y\). The notation \(f_{xx}\) denotes the second partial derivative of \(f\) with respect to \(x\) twice. Similarly, \(f_{xy}\) denotes taking the derivative with respect to \(x\) first and then \(y\), \(f_{yx}\) denotes the derivative with respect to \(y\) first and then \(x\), and \(f_{yy}\) denotes the second partial derivative with respect to \(y\) twice.
2Step 2: Calculating the First Partial Derivatives
First, find the partial derivative of \(f\) with respect to \(x\): \[ \frac{\partial f}{\partial x} = 3 \]Secondly, find the partial derivative of \(f\) with respect to \(y\):\[ \frac{\partial f}{\partial y} = 5 \]
3Step 3: Calculating Second Partial Derivatives with Respect to x
Find \(f_{xx}\), the second partial derivative with respect to \(x\) using \(\frac{\partial f}{\partial x} = 3\):\[ f_{xx} = \frac{\partial}{\partial x} \left( \frac{\partial f}{\partial x} \right) = \frac{\partial}{\partial x} (3) = 0 \]
4Step 4: Calculating Mixed Partial Derivative f_{xy}
Find \(f_{xy}\), the derivative with respect to \(x\) then \(y\) using \(\frac{\partial f}{\partial x} = 3\):\[ f_{xy} = \frac{\partial}{\partial y} \left( \frac{\partial f}{\partial x} \right) = \frac{\partial}{\partial y} (3) = 0 \]
5Step 5: Calculating Mixed Partial Derivative f_{yx}
Find \(f_{yx}\), the derivative with respect to \(y\) then \(x\) using \(\frac{\partial f}{\partial y} = 5\):\[ f_{yx} = \frac{\partial}{\partial x} \left( \frac{\partial f}{\partial y} \right) = \frac{\partial}{\partial x} (5) = 0 \]
6Step 6: Calculating Second Partial Derivatives with Respect to y
Find \(f_{yy}\), the second partial derivative with respect to \(y\) using \(\frac{\partial f}{\partial y} = 5\):\[ f_{yy} = \frac{\partial}{\partial y} \left( \frac{\partial f}{\partial y} \right) = \frac{\partial}{\partial y} (5) = 0 \]
Key Concepts
Second-Order Partial DerivativesMultivariable FunctionMixed Partial Derivatives
Second-Order Partial Derivatives
The concept of second-order partial derivatives involves taking partial derivatives of a function not once, but twice. Imagine you have a function of two variables, say \(f(x, y)\). Here, you can either take partial derivatives twice with respect to the same variable or with different ones.
The specific notation tells you how to proceed:
The specific notation tells you how to proceed:
- \(f_{xx}\) means take the derivative with respect to \(x\) twice.
- \(f_{yy}\) means to take the derivative with respect to \(y\) twice.
Multivariable Function
An essential concept in multivariable calculus, a multivariable function is a function that depends on more than one variable. Unlike single-variable functions which can be plotted in two dimensions, multivariable functions exist in a higher-dimensional space. For example, the function in question \(f(x, y) = 3x + 5y\) is a simple two-variable function with linearity.
Key characteristics of multivariable functions include:
Key characteristics of multivariable functions include:
- They form surfaces when graphed, with values changing based on multiple inputs.
- They allow for examination of interactions between variables, providing a broad perspective on how systems behave.
- Partial derivatives have to be used to explore changes in these functions, as they tell you how the function changes with respect to one of the variables while holding the others constant.
Mixed Partial Derivatives
In the exploration of multivariable functions, mixed partial derivatives are imperative. These derivatives measure the change in slope of a function with respect to two variables. Considering a function \(f(x, y)\), mixed partial derivatives take partial derivatives with respect to different variables.
- \(f_{xy}\) involves differentiating first with respect to \(x\) and then \(y\).
- \(f_{yx}\) is calculated by differentiating first with respect to \(y\) and then \(x\).
Other exercises in this chapter
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